Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. What is the electric field due to a point charge of +5μC at a distance of 0.2m?
A.
11250 N/C
B.
4500 N/C
C.
2250 N/C
D.
5625 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (5 × 10^-6) / (0.2)^2 = 11250 N/C.
Correct Answer:
A
— 11250 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.3m? (2000)
A.
1500 N/C
B.
5000 N/C
C.
1000 N/C
D.
2000 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (5 × 10^-6) / (0.3)^2 = 5000 N/C.
Correct Answer:
B
— 5000 N/C
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Q. What is the electric field due to a uniformly charged infinite plane sheet with surface charge density σ?
A.
σ/2ε₀
B.
σ/ε₀
C.
2σ/ε₀
D.
0
Show solution
Solution
The electric field due to an infinite plane sheet is E = σ/2ε₀ on both sides, thus total E = σ/ε₀.
Correct Answer:
C
— 2σ/ε₀
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Q. What is the electric field due to a uniformly charged infinite plane sheet?
A.
0
B.
σ/2ε₀
C.
σ/ε₀
D.
σ/4ε₀
Show solution
Solution
According to Gauss's law, the electric field due to an infinite plane sheet with surface charge density σ is E = σ/2ε₀, directed away from the sheet.
Correct Answer:
B
— σ/2ε₀
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Q. What is the electric field due to a uniformly charged line of charge with linear charge density λ at a distance r from the line?
A.
λ/(2πε₀r)
B.
λ/(4πε₀r²)
C.
2λ/(πε₀r)
D.
λ/(ε₀r)
Show solution
Solution
Using Gauss's law, the electric field due to a uniformly charged line of charge is E = λ/(2πε₀r).
Correct Answer:
A
— λ/(2πε₀r)
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Q. What is the electric field due to an infinite plane sheet of charge with surface charge density σ?
A.
σ/2ε₀
B.
σ/ε₀
C.
σ/4ε₀
D.
0
Show solution
Solution
The electric field due to an infinite plane sheet of charge is given by E = σ/2ε₀, directed away from the sheet if the charge is positive.
Correct Answer:
A
— σ/2ε₀
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Q. What is the electric field inside a charged conductor in electrostatic equilibrium?
A.
Zero
B.
Constant
C.
Varies with distance
D.
Depends on charge density
Show solution
Solution
Inside a charged conductor in electrostatic equilibrium, the electric field is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field inside a uniformly charged hollow sphere?
A.
Zero
B.
Uniform and equal to the surface field
C.
Varies linearly with distance from the center
D.
Depends on the charge outside the sphere
Show solution
Solution
According to Gauss's law, the electric field inside a uniformly charged hollow sphere is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field inside a uniformly charged spherical shell?
A.
Zero
B.
Uniform
C.
Varies linearly
D.
Depends on the charge outside
Show solution
Solution
The electric field inside a uniformly charged spherical shell is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field outside a uniformly charged sphere of radius R with total charge Q?
A.
0
B.
Q/(4πε₀R²)
C.
Q/(4πε₀R)
D.
Q/(2πε₀R²)
Show solution
Solution
For a uniformly charged sphere, outside the sphere, the electric field behaves as if all the charge were concentrated at the center, E = Q/(4πε₀R²).
Correct Answer:
B
— Q/(4πε₀R²)
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Q. What is the electric flux through a closed surface surrounding a charge of -3Q?
A.
-3Q/ε₀
B.
3Q/ε₀
C.
0
D.
-6Q/ε₀
Show solution
Solution
According to Gauss's law, the electric flux through a closed surface is Φ = Q_enc/ε₀. Here, Q_enc = -3Q, so Φ = -3Q/ε₀.
Correct Answer:
A
— -3Q/ε₀
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Q. What is the electric flux through a closed surface surrounding a charge Q?
A.
0
B.
Q/ε₀
C.
Q/2ε₀
D.
Q/4ε₀
Show solution
Solution
According to Gauss's law, the electric flux Φ through a closed surface is given by Φ = Q/ε₀.
Correct Answer:
B
— Q/ε₀
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Q. What is the electric flux through a closed surface that encloses no charge?
A.
0
B.
Q/ε₀
C.
Q
D.
4πQ/ε₀
Show solution
Solution
According to Gauss's law, if there is no charge enclosed, the electric flux through the surface is zero.
Correct Answer:
A
— 0
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Q. What is the electric potential at a distance of 3 m from a charge of 10 μC?
A.
3000 V
B.
9000 V
C.
6000 V
D.
1000 V
Show solution
Solution
V = k * q / r = (9 × 10^9 N m²/C²) * (10 × 10^-6 C) / (3 m) = 30000 V / 3 = 9000 V.
Correct Answer:
B
— 9000 V
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Q. What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)
A.
4500 V
B.
1800 V
C.
2000 V
D.
None of the above
Show solution
Solution
Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m) = 1800 V.
Correct Answer:
B
— 1800 V
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Q. What is the electric potential at a point 0.3m away from a charge of +4μC?
A.
12000 V
B.
3000 V
C.
6000 V
D.
9000 V
Show solution
Solution
V = k * q / r = (9 × 10^9) * (4 × 10^-6) / 0.3 = 12000 V.
Correct Answer:
A
— 12000 V
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Q. What is the electric potential at a point 0.4 m away from a charge of +5 µC?
A.
45 V
B.
50 V
C.
55 V
D.
60 V
Show solution
Solution
V = k * q / r = (9 × 10^9) * (5 × 10^-6) / 0.4 = 112.5 V.
Correct Answer:
B
— 50 V
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Q. What is the electric potential at a point due to a charge Q at a distance r? (2021)
A.
kQ/r
B.
kQr
C.
kQ/r^2
D.
0
Show solution
Solution
The electric potential (V) at a distance r from a point charge Q is given by V = kQ/r.
Correct Answer:
A
— kQ/r
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Q. What is the electric potential at a point due to a point charge?
A.
kQ/r
B.
Q/(4πε₀r²)
C.
kQ/(4πε₀r)
D.
Q/(4πr²)
Show solution
Solution
The electric potential V at a distance r from a point charge Q is given by V = kQ/r, where k is Coulomb's constant.
Correct Answer:
A
— kQ/r
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Q. What is the electric potential at a point due to a positive point charge?
A.
Zero
B.
Positive
C.
Negative
D.
Depends on distance
Show solution
Solution
The electric potential due to a positive point charge is positive and decreases with distance from the charge.
Correct Answer:
B
— Positive
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Q. What is the electric potential at a point in space where the electric field is zero?
A.
Zero
B.
Positive
C.
Negative
D.
Undefined
Show solution
Solution
The electric potential can be positive or negative; it is not necessarily zero when the electric field is zero.
Correct Answer:
B
— Positive
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Q. What is the electric potential due to a dipole at a point along the axial line at a distance 'r' from the center of the dipole?
A.
0
B.
k * p / r²
C.
k * p / r
D.
k * p / 2r
Show solution
Solution
The potential V = k * p / r, where p is the dipole moment.
Correct Answer:
C
— k * p / r
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Q. What is the electric potential due to a point charge at a distance r?
A.
k * q / r
B.
k * q / r^2
C.
k * q * r
D.
k * q * r^2
Show solution
Solution
The electric potential V due to a point charge q at a distance r is given by V = k * q / r.
Correct Answer:
A
— k * q / r
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Q. What is the electric potential due to a point charge of 5 μC at a distance of 2 m?
A.
0 V
B.
2250 V
C.
1125 V
D.
4500 V
Show solution
Solution
Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (2 m) = 2250 V.
Correct Answer:
B
— 2250 V
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Q. What is the electric potential energy of a charge of 1 C at a point where the electric potential is 10 V?
A.
10 J
B.
1 J
C.
0 J
D.
100 J
Show solution
Solution
Electric potential energy U = q * V = 1 C * 10 V = 10 J.
Correct Answer:
A
— 10 J
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Q. What is the electric potential energy of a charge of 1 C placed in an electric field of 10 N/C at a distance of 2 m?
A.
20 J
B.
10 J
C.
5 J
D.
2 J
Show solution
Solution
Electric potential energy U = q * V = q * E * d = 1 C * 10 N/C * 2 m = 20 J.
Correct Answer:
A
— 20 J
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Q. What is the electric potential energy of a charge of 1 μC placed in an electric potential of 200 V?
A.
0.2 mJ
B.
0.1 mJ
C.
0.4 mJ
D.
0.5 mJ
Show solution
Solution
Electric potential energy U = q * V = 1 × 10^-6 C * 200 V = 0.2 mJ.
Correct Answer:
A
— 0.2 mJ
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Q. What is the electric potential energy of a system of two charges +q and -q separated by a distance r?
A.
0
B.
kq²/r
C.
-kq²/r
D.
kq/r
Show solution
Solution
The electric potential energy U = k(q1*q2)/r = k(+q*-q)/r = -kq²/r.
Correct Answer:
C
— -kq²/r
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Q. What is the electric potential energy of a system of two charges of +2 μC and -2 μC separated by 0.5 m?
A.
-72 J
B.
72 J
C.
0 J
D.
-36 J
Show solution
Solution
U = k * (q1 * q2) / r = (9 × 10^9 N m²/C²) * (2 × 10^-6 C * -2 × 10^-6 C) / 0.5 m = -72 J.
Correct Answer:
D
— -36 J
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Q. What is the electric potential energy of a system of two point charges Q1 and Q2 separated by a distance r?
A.
kQ1Q2/r
B.
kQ1Q2/2r
C.
kQ1Q2/r²
D.
kQ1Q2
Show solution
Solution
The electric potential energy U of a system of two point charges is given by U = kQ1Q2/r.
Correct Answer:
A
— kQ1Q2/r
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