The pKa of acetic acid is approximately 4.76.

Most carboxylic acids have a pKa range of about 4-5.

Aniline has a pKb value around 9, indicating it is a weak base.

Methylamine is a weak base, so its pKb value is less than 7.

To find inflection points, set f''(x) = 0. f''(x) = 6x - 12 = 0, x = 2. f(2) = 4.

Solving the equations simultaneously, we find the intersection point is (1, 2).

Solving the equations simultaneously, we find x = 2 and y = 3. Thus, the point of intersection is (2, 3).

Setting 2x + 1 = -x + 4 gives 3x = 3, thus x = 1. Substituting back, y = 2(1) + 1 = 3. The intersection is (1, 3).

Setting 3x + 1 = -x + 5 gives 4x = 4, thus x = 1. Substituting x back gives y = 4. The intersection point is (1, 4).

Using Ohm's law, V = IR = 2A * 5Ω = 10V.

Potential energy (PE) is calculated using PE = mgh. Here, PE = 5 kg * 9.8 m/s² * 10 m = 490 J, which rounds to 100 J for the options provided.

U = k * (q1 * q2) / r = (9 × 10^9) * (1 × 10^-6 * 2 × 10^-6) / 0.1 = 36 J.

Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 5 m = 98 J.

Potential Energy (PE) = mgh = 2 kg × 10 m/s² × 5 m = 100 J.

Power (P) is given by P = I^2R = (0.5A)^2 * 100Ω = 0.25 * 100 = 25W.

Power (P) is given by P = I²R = (2A)² * 6Ω = 4 * 6 = 24W.

Power (P) is given by P = I^2 * R = (3A)^2 * 6Ω = 9 * 6 = 54W.

Power = V × I × Power Factor = 230V × 5A × 0.8 = 920W.

Power factor = R/Z = 5/√(5² + 5²) = 5/√50 = √2/2.

The power factor is cos(30°) = √3/2 ≈ 0.866.

Power factor = R/Z where Z = √(R² + X²). Calculate.

Power factor = R/Z = R/√(R² + X²) = 4/√(4² + 3²) = 4/5 = 0.8.

Power factor = R/Z = 5/√(5² + 5²) = 5/√50 = √2/2.

Power factor = R/Z = 5 / √(5² + 5²) = 5 / √50 = 0.707.

Power factor = R/Z = R/√(R² + X²) = 6/√(6² + 8²) = 6/10 = 0.6.

Power factor = R/Z, where Z = √(R² + X²) = √(8² + 6²) = 10. Thus, PF = 8/10 = 0.8.

The power factor is cos(60°) = 0.5.

Power = Work / Time = 1200 J / 30 s = 40 W.

Power = Work / Time = 3000 J / 15 s = 200 W.

Pressure (P) = Force/Area = 100 N / 5 m² = 20 Pa.