Using Pythagorean theorem: diagonal = √(length² + width²) = √(5² + 12²) = √(25 + 144) = √169 = 13 cm.

Using the Pythagorean theorem: d = √(length² + width²) = √(6² + 8²) = √(36 + 64) = √100 = 10.

The length of the diagonal d of a rectangle is given by d = √(length² + width²). Here, d = √(6² + 8²) = √(36 + 64) = √100 = 10 units.

Diagonal = √(8² + 6²) = √(64 + 36) = √100 = 10.

The length of the diagonal (d) of a rectangle can be calculated using the Pythagorean theorem: d = √(length² + width²). Here, d = √(8² + 6²) = √(64 + 36) = √100 = 10.

Using the Pythagorean theorem: d = √(length² + width²) = √(6² + 8²) = √(36 + 64) = √100 = 10.

The length of the diagonal can be found using the distance formula: d = √((8 - 0)² + (6 - 0)²) = √(64 + 36) = √100 = 10.

Diagonal length = √((a - 0)² + (b - 0)²) = √(a² + b²).

The diagonal can be calculated using the distance formula: d = sqrt((5-1)^2 + (4-1)^2) = sqrt(16 + 9) = sqrt(25) = 5.

The length of the diagonal can be calculated using the distance formula between (2, 1) and (5, 4). Diagonal = √((5-2)² + (4-1)²) = √(3² + 3²) = √18 = 3√2.

The length of the diagonal can be found using the Pythagorean theorem: d = √(width^2 + height^2) = √(6^2 + 8^2) = √(36 + 64) = √100 = 10.

Area = πr² = 50π. Thus, r² = 50, r = √50 = 5√2 cm. Diameter = 2r = 10 cm.

Area = πr², so 50π = πr². Thus, r² = 50, r = √50 = 5√2. Diameter = 2r = 10√2 units.

The circumference C of a circle is given by C = πd. Therefore, d = C/π = 31.4/3.14 = 10 cm.

Circumference = πd, so d = C/π = 31.4/π ≈ 10 cm.

Circumference = πd, so d = C/π = 31.4/π = 10 cm.

Diameter d = 2 * radius = 2 * 7 = 14 units.

Area = πr²; 50π = πr²; r² = 50; r = √50; Diameter = 2r = 2√50 = 10 cm.

Using the Pythagorean theorem, hypotenuse = √(3^2 + 4^2) = √(9 + 16) = √25 = 5.

Using the Pythagorean theorem: c = √(3² + 4²) = √(9 + 16) = √25 = 5 cm.

Using the Pythagorean theorem, hypotenuse = √(3² + 4²) = √(9 + 16) = √25 = 5 cm.

Using the Pythagorean theorem: hypotenuse = √(3^2 + 4^2) = √(9 + 16) = √25 = 5.

Using Pythagorean theorem: c = √(3² + 4²) = √(9 + 16) = √25 = 5 cm.

Using the Pythagorean theorem, c² = a² + b². Here, c² = 3² + 4² = 9 + 16 = 25, so c = √25 = 5 units.

Using the Pythagorean theorem, c = √(3² + 4²) = √(9 + 16) = √25 = 5.

Using the Pythagorean theorem, c² = a² + b², we have c² = 3² + 4² = 9 + 16 = 25, so c = 5 cm.

Using the Pythagorean theorem, c² = a² + b². Here, c² = 6² + 8² = 36 + 64 = 100, so c = √100 = 10.

Using the Pythagorean theorem, c² = a² + b², we have c² = 3² + 4² = 9 + 16 = 25, thus c = 5 cm.

Using the Pythagorean theorem, hypotenuse = √(5^2 + 12^2) = √(25 + 144) = √169 = 13 cm.

Using the Pythagorean theorem, c² = a² + b², where a = 6 cm and b = 8 cm. Thus, c² = 6² + 8² = 36 + 64 = 100, so c = √100 = 10 cm.