Major Competitive Exams

My Learning Cart

?

Welcome to

Soulshift

Categories

Account

Major Competitive Exams

Download Q&A

Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

Civil Services Defence Exams Engineering & Architecture Admissions Government Jobs Management Admissions Undergraduate

Q. What is the common oxidation state of the p-block elements in group 13?

A. +1
B. +2
C. +3
D. +4

Solution

The common oxidation state of group 13 elements, such as Aluminum, is +3.

Correct Answer: C — +3

Q. What is the common oxidation state of transition metals in the d-block? (2023)

A. +1
B. +2
C. +3
D. +4

Solution

The common oxidation state of transition metals in the d-block is +2, as they often lose two electrons from their outermost shell.

Correct Answer: B — +2

Q. What is the common oxidation state of transition metals in their compounds?

A. +1
B. +2
C. +3
D. +4

Solution

Transition metals commonly exhibit a +2 oxidation state due to the loss of two 4s electrons.

Correct Answer: B — +2

Q. What is the common ratio of the geometric series 4, 12, 36, ...?

A. 3
B. 2
C. 1.5
D. 4

Solution

The common ratio r = 12/4 = 3.

Correct Answer: A — 3

Q. What is the composition of functions f(g(x)) if f(x) = x + 1 and g(x) = 2x?

A. 2x + 1
B. 2x - 1
C. x + 2
D. x + 1

Solution

f(g(x)) = f(2x) = 2x + 1.

Correct Answer: A — 2x + 1

Q. What is the compound interest on $1500 at a rate of 12% per annum for 2 years?

A. $360.00
B. $400.00
C. $450.00
D. $500.00

Solution

CI = P(1 + r)^n - P = 1500(1 + 0.12)^2 - 1500 = 1500(1.2544) - 1500 = $381.60.

Correct Answer: A — $360.00

Q. What is the compound interest on a principal of $1000 at an annual interest rate of 5% for 3 years?

A. $157.63
B. $150.00
C. $100.00
D. $115.76

Solution

Compound Interest = P(1 + r/n)^(nt) - P = 1000(1 + 0.05/1)^(1*3) - 1000 = 1000(1.157625) - 1000 = $157.63

Correct Answer: A — $157.63

Q. What is the compound interest on a principal of $1000 at an annual interest rate of 5% for 2 years?

A. $102.50
B. $105.00
C. $110.25
D. $100.00

Solution

Compound Interest = P(1 + r/n)^(nt) - P = 1000(1 + 0.05/1)^(1*2) - 1000 = 1000(1.1025) - 1000 = 102.50.

Correct Answer: C — $110.25

Q. What is the compound interest on a principal of $5000 at an annual interest rate of 10% for 1 year?

A. $500
B. $550
C. $600
D. $650

Solution

Compound Interest = P(1 + r/n)^(nt) - P = 5000(1 + 0.10/1)^(1*1) - 5000 = 5000(1.10) - 5000 = 500.

Correct Answer: B — $550

Q. What is the concentration in g/L of a solution containing 0.5 moles of KCl in 1.5 L of solution? (Molar mass of KCl = 74.5 g/mol)

A. 24.83 g/L
B. 49.67 g/L
C. 37.25 g/L
D. 50 g/L

Solution

Mass of KCl = 0.5 moles × 74.5 g/mol = 37.25 g. Concentration = 37.25 g / 1.5 L = 24.83 g/L.

Correct Answer: B — 49.67 g/L

Q. What is the concentration in mol/L of a solution made by dissolving 58.5 grams of NaCl in 1 liter of water? (Molar mass of NaCl = 58.5 g/mol) (2023) 2023

A. 1 M
B. 0.5 M
C. 2 M
D. 0.25 M

Solution

Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.

Correct Answer: A — 1 M

Q. What is the concentration in molality of a solution made by dissolving 5 moles of solute in 3 kg of solvent?

A. 1.67 m
B. 2 m
C. 1.5 m
D. 2.5 m

Solution

Molality (m) = moles of solute / kg of solvent = 5 moles / 3 kg = 1.67 m.

Correct Answer: B — 2 m

Q. What is the concentration in molarity of a solution that contains 0.5 moles of solute in 1.5 liters of solution?

A. 0.33 M
B. 0.5 M
C. 0.75 M
D. 1 M

Solution

Molarity (M) = moles of solute / liters of solution = 0.5 moles / 1.5 L = 0.33 M.

Correct Answer: C — 0.75 M

Q. What is the concentration in ppm of a solution containing 1 gram of solute in 1 liter of solution?

A. 1000 ppm
B. 100 ppm
C. 10 ppm
D. 1 ppm

Solution

PPM = (mass of solute in grams / volume of solution in liters) * 10^6 = (1 g / 1 L) * 10^6 = 1000 ppm.

Correct Answer: A — 1000 ppm

Q. What is the concentration of a solution if 10 grams of NaCl is dissolved in 500 mL of water? (Molar mass of NaCl = 58.5 g/mol)

A. 0.34 M
B. 0.17 M
C. 0.50 M
D. 0.25 M

Solution

Molarity (M) = moles of solute / liters of solution = (10 g / 58.5 g/mol) / 0.5 L = 0.34 M.

Correct Answer: A — 0.34 M

Q. What is the concentration of a solution if 5 g of NaOH is dissolved in 250 mL of water? (2020)

A. 0.5 M
B. 1 M
C. 0.2 M
D. 0.1 M

Solution

Moles of NaOH = 5 g / 40 g/mol = 0.125 mol. Molarity = 0.125 mol / 0.25 L = 0.5 M.

Correct Answer: B — 1 M

Q. What is the concentration of H+ ions in a solution with a pH of 3?

A. 0.001 M
B. 0.01 M
C. 0.1 M
D. 1 M

Solution

[H+] = 10^(-pH) = 10^(-3) = 0.001 M

Correct Answer: A — 0.001 M

Q. What is the concentration of H+ ions in a solution with pH 3? (2019) 2019

A. 0.001 M
B. 0.01 M
C. 0.1 M
D. 1 M

Solution

Concentration of H+ = 10^(-pH) = 10^(-3) = 0.001 M.

Correct Answer: B — 0.01 M

Q. What is the concentration of H+ ions in a solution with pH 4?

A. 0.0001 M
B. 0.01 M
C. 0.1 M
D. 1 M

Solution

[H+] = 10^(-pH) = 10^(-4) = 0.0001 M.

Correct Answer: A — 0.0001 M

Q. What is the conclusion drawn by the author?

A. The issue will resolve itself.
B. Immediate action is required.
C. More research is needed.
D. The problem is overstated.

Solution

The author concludes that immediate action is necessary based on the evidence presented.

Correct Answer: B — Immediate action is required.

Q. What is the condition for a system to be critically damped?

A. Damping coefficient equals zero
B. Damping coefficient is less than the natural frequency
C. Damping coefficient equals the square root of the product of mass and spring constant
D. Damping coefficient is greater than the natural frequency

Solution

A system is critically damped when the damping coefficient equals the square root of the product of mass and spring constant.

Correct Answer: C — Damping coefficient equals the square root of the product of mass and spring constant

Q. What is the condition for a Wheatstone bridge to be balanced?

A. R1/R2 = R3/R4
B. R1 + R2 = R3 + R4
C. R1 - R2 = R3 - R4
D. R1 * R2 = R3 * R4

Solution

The condition for a Wheatstone bridge to be balanced is R1/R2 = R3/R4.

Correct Answer: A — R1/R2 = R3/R4

Q. What is the condition for a Wheatstone bridge to be in a balanced state?

A. R1/R2 = R3/R4
B. R1 + R2 = R3 + R4
C. R1 - R2 = R3 - R4
D. R1 * R4 = R2 * R3

Solution

The condition for balance is R1/R2 = R3/R4.

Correct Answer: A — R1/R2 = R3/R4

Q. What is the condition for a Wheatstone bridge to be in equilibrium?

A. R1/R2 = R3/R4
B. R1 + R2 = R3 + R4
C. R1 - R2 = R3 - R4
D. R1 * R3 = R2 * R4

Solution

In a Wheatstone bridge, the bridge is in equilibrium when the ratio of the resistances in one branch is equal to the ratio in the other branch, i.e., R1/R2 = R3/R4.

Correct Answer: A — R1/R2 = R3/R4

Q. What is the condition for an object to be in rotational equilibrium?

A. Net force is zero
B. Net torque is zero
C. Both net force and net torque are zero
D. None of the above

Solution

For rotational equilibrium, the net torque acting on the object must be zero.

Correct Answer: B — Net torque is zero

Q. What is the condition for constructive interference in a double-slit experiment?

A. Path difference is an odd multiple of lambda/2
B. Path difference is an even multiple of lambda
C. Path difference is an odd multiple of lambda
D. Path difference is zero

Solution

Constructive interference occurs when the path difference between the two waves is an even multiple of the wavelength (nλ, where n is an integer).

Correct Answer: B — Path difference is an even multiple of lambda

Q. What is the condition for constructive interference in a thin film?

A. 2t = (m + 1/2)λ
B. 2t = mλ
C. t = mλ/2
D. t = (m + 1/2)λ/2

Solution

For constructive interference, the condition is 2t = mλ, where t is the thickness of the film and m is an integer.

Correct Answer: B — 2t = mλ

Q. What is the condition for constructive interference in two waves?

A. Path difference = (n + 1/2)λ
B. Path difference = nλ
C. Path difference = (n - 1/2)λ
D. Path difference = 0

Solution

Constructive interference occurs when the path difference is nλ, where n is an integer.

Correct Answer: B — Path difference = nλ

Q. What is the condition for critical damping in a damped harmonic oscillator?

A. Damping coefficient equals zero
B. Damping coefficient equals mass times natural frequency
C. Damping coefficient equals twice the mass times natural frequency
D. Damping coefficient is less than mass times natural frequency

Solution

Critical damping occurs when the damping coefficient equals twice the mass times the natural frequency of the system.

Correct Answer: C — Damping coefficient equals twice the mass times natural frequency

Q. What is the condition for critical damping in a damped oscillator?

A. Damping coefficient equals zero
B. Damping coefficient equals mass times natural frequency
C. Damping coefficient is less than mass times natural frequency
D. Damping coefficient is greater than mass times natural frequency

Solution

Critical damping occurs when the damping coefficient equals the mass times the natural frequency.

Correct Answer: B — Damping coefficient equals mass times natural frequency

Showing 19441 to 19470 of 31669 (1056 Pages)

Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely