Q. What is the magnetic field at a distance r from an infinitely long straight wire carrying current I?
-
A.
μ₀I/2πr
-
B.
μ₀I/4πr
-
C.
μ₀I/πr
-
D.
0
Solution
Using Ampere's Law, B = μ₀I/2πr for an infinitely long straight wire.
Correct Answer:
A
— μ₀I/2πr
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Q. What is the magnetic field at a point due to a long straight current-carrying conductor using Biot-Savart Law?
-
A.
μ₀I/(2πr)
-
B.
μ₀I/(4πr²)
-
C.
μ₀I/(2r)
-
D.
μ₀I/(4r)
Solution
The magnetic field B at a distance r from a long straight conductor carrying current I is given by B = μ₀I/(2πr) according to Biot-Savart Law.
Correct Answer:
A
— μ₀I/(2πr)
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Q. What is the magnetic field at a point on the axis of a circular loop of radius R carrying a current I at a distance x from the center?
-
A.
(μ₀I)/(2R) * (R²/(R²+x²)^(3/2))
-
B.
(μ₀I)/(4R) * (R²/(R²+x²)^(3/2))
-
C.
(μ₀I)/(2R) * (1/(R²+x²)^(3/2))
-
D.
(μ₀I)/(4R) * (1/(R²+x²)^(3/2))
Solution
The magnetic field on the axis of a circular loop is given by B = (μ₀I)/(2R) * (R²/(R²+x²)^(3/2)).
Correct Answer:
A
— (μ₀I)/(2R) * (R²/(R²+x²)^(3/2))
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Q. What is the magnetic field at a point on the axis of a circular loop of radius R carrying current I?
-
A.
μ₀I/(2R)
-
B.
μ₀I/(4R)
-
C.
μ₀I/(2R²)
-
D.
μ₀I/(2√2R)
Solution
The magnetic field on the axis of a circular loop is given by B = (μ₀I/(2R)) * (1/(1 + (z/R)²)^(3/2)) where z is the distance along the axis.
Correct Answer:
D
— μ₀I/(2√2R)
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Q. What is the magnetic field at the center of a circular loop carrying current? (2022)
-
A.
Zero
-
B.
Directly proportional to current
-
C.
Inversely proportional to radius
-
D.
Both A and B
Solution
The magnetic field at the center of a circular loop carrying current is directly proportional to the current and inversely proportional to the radius.
Correct Answer:
B
— Directly proportional to current
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Q. What is the magnetic field at the center of a circular loop of radius R carrying a current I?
-
A.
μ₀I/(2R)
-
B.
μ₀I/(4R)
-
C.
μ₀I/(R)
-
D.
μ₀I/(8R)
Solution
The magnetic field at the center of a circular loop is given by B = μ₀I/(2R).
Correct Answer:
A
— μ₀I/(2R)
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Q. What is the magnetic field at the center of a circular loop of radius R carrying current I?
-
A.
μ₀I/2R
-
B.
μ₀I/R
-
C.
μ₀I/4R
-
D.
μ₀I/πR
Solution
The magnetic field at the center of a circular loop is given by B = μ₀I/2R.
Correct Answer:
A
— μ₀I/2R
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Q. What is the magnetic field at the center of a square loop of side a carrying current I?
-
A.
μ₀I/4a
-
B.
μ₀I/2a
-
C.
μ₀I/a
-
D.
μ₀I/8a
Solution
The magnetic field at the center of a square loop is B = μ₀I/4a.
Correct Answer:
A
— μ₀I/4a
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Q. What is the magnetic field at the midpoint of a wire carrying current I in opposite directions?
-
A.
Zero
-
B.
μ₀I/2
-
C.
μ₀I
-
D.
Depends on distance
Solution
At the midpoint, the magnetic fields due to the two currents cancel each other out, resulting in zero net magnetic field.
Correct Answer:
A
— Zero
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Q. What is the magnetic field due to a circular loop of radius R carrying current I at a point on its axis at a distance x from the center?
-
A.
μ₀I/(2R)
-
B.
μ₀I/(2(x² + R²)^(3/2))
-
C.
μ₀I/(4πR)
-
D.
μ₀I/(x² + R²)
Solution
The magnetic field at a point on the axis of a circular loop at a distance x from the center is given by B = μ₀I/(2(x² + R²)^(3/2)).
Correct Answer:
B
— μ₀I/(2(x² + R²)^(3/2))
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Q. What is the magnetic field due to a current I flowing through a straight wire at a distance d?
-
A.
μ₀I/(2πd)
-
B.
μ₀I/(4πd²)
-
C.
μ₀I/(d)
-
D.
μ₀I/(2d)
Solution
The magnetic field B at a distance d from a straight wire carrying current I is given by B = μ₀I/(2πd).
Correct Answer:
A
— μ₀I/(2πd)
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Q. What is the magnetic field due to a current loop at a point on its axis?
-
A.
μ₀I/2R
-
B.
μ₀I/4R
-
C.
μ₀I/2R²
-
D.
μ₀I/4R²
Solution
Using Ampere's Law, B = μ₀I/2R² at a point on the axis of a current loop.
Correct Answer:
C
— μ₀I/2R²
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Q. What is the magnetic field due to a long straight wire carrying current I at a distance r from the wire?
-
A.
μ₀I/2πr
-
B.
μ₀I/4πr
-
C.
μ₀I/πr
-
D.
μ₀I/8πr
Solution
The magnetic field due to a long straight wire is given by B = (μ₀I)/(2πr).
Correct Answer:
A
— μ₀I/2πr
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Q. What is the magnetic field due to a magnetic dipole at a point along its axial line?
-
A.
(μ₀/4π) * (2m/r³)
-
B.
(μ₀/4π) * (m/r³)
-
C.
(μ₀/4π) * (m/r²)
-
D.
(μ₀/4π) * (m/r⁴)
Solution
The magnetic field due to a magnetic dipole at a point along its axial line is given by B = (μ₀/4π) * (2m/r³).
Correct Answer:
A
— (μ₀/4π) * (2m/r³)
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Q. What is the magnetic field due to a solenoid of length L, carrying n turns per unit length and current I?
-
A.
μ₀nI
-
B.
μ₀nI/L
-
C.
μ₀nI/2
-
D.
μ₀nI/L²
Solution
The magnetic field inside a long solenoid is B = μ₀nI.
Correct Answer:
A
— μ₀nI
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Q. What is the magnetic field due to a straight conductor at a point 1 meter away carrying a current of 5 A?
-
A.
0.01 T
-
B.
0.02 T
-
C.
0.03 T
-
D.
0.04 T
Solution
Using Biot-Savart Law, B = μ₀I/(2πr) = (4π × 10^-7 Tm/A)(5 A)/(2π(1 m)) = 0.01 T.
Correct Answer:
B
— 0.02 T
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Q. What is the magnetic field due to a straight current-carrying conductor at a distance 'r' from it? (2020)
-
A.
μ₀I/2πr
-
B.
μ₀I/4πr²
-
C.
μ₀I/2r
-
D.
μ₀I/πr
Solution
The magnetic field due to a straight current-carrying conductor is given by B = μ₀I/2πr.
Correct Answer:
A
— μ₀I/2πr
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Q. What is the magnetic field due to a straight wire at a distance of 0.5 m carrying a current of 10 A?
-
A.
0.4 μT
-
B.
0.2 μT
-
C.
0.1 μT
-
D.
0.8 μT
Solution
Using B = μ₀I/(2πr), substituting μ₀ = 4π × 10⁻⁷ Tm/A, I = 10 A, and r = 0.5 m gives B = 0.4 μT.
Correct Answer:
A
— 0.4 μT
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Q. What is the magnetic field inside a hollow conductor carrying current?
-
A.
Zero
-
B.
Uniform
-
C.
Varies with distance
-
D.
Depends on the current
Solution
According to Ampere's law, the magnetic field inside a hollow conductor carrying current is zero.
Correct Answer:
A
— Zero
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Q. What is the magnetic field inside a hollow cylindrical shell carrying current I?
-
A.
0
-
B.
μ₀I/2πR
-
C.
μ₀I/4πR
-
D.
μ₀I/πR
Solution
Inside a hollow cylindrical shell, the magnetic field is zero.
Correct Answer:
A
— 0
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Q. What is the magnetic field inside a long solenoid carrying current I?
-
A.
Zero
-
B.
μ₀nI
-
C.
μ₀I/n
-
D.
μ₀I/2
Solution
The magnetic field inside a long solenoid is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer:
B
— μ₀nI
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Q. What is the magnetic field inside a long solenoid carrying current?
-
A.
Zero
-
B.
Uniform and parallel to the axis
-
C.
Varies with distance
-
D.
Depends on the current only
Solution
The magnetic field inside a long solenoid is uniform and parallel to the axis of the solenoid.
Correct Answer:
B
— Uniform and parallel to the axis
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Q. What is the magnetic field inside a long solenoid when it carries a current? (2023)
-
A.
Zero
-
B.
Uniform and directed along the axis
-
C.
Varies with distance
-
D.
Depends on the temperature
Solution
The magnetic field inside a long solenoid is uniform and directed along the axis of the solenoid when it carries a current.
Correct Answer:
B
— Uniform and directed along the axis
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Q. What is the magnetic field inside a long solenoid when the current is flowing through it? (2023)
-
A.
Zero
-
B.
Uniform and parallel
-
C.
Concentric circles
-
D.
Radial
Solution
The magnetic field inside a long solenoid is uniform and parallel to the axis of the solenoid.
Correct Answer:
B
— Uniform and parallel
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Q. What is the magnetic field inside a long solenoid when the current is steady? (2023)
-
A.
Zero
-
B.
Uniform and parallel to the axis
-
C.
Varies with distance
-
D.
Depends on the temperature
Solution
The magnetic field inside a long solenoid is uniform and parallel to the axis of the solenoid when the current is steady.
Correct Answer:
B
— Uniform and parallel to the axis
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Q. What is the magnetic field inside a long solenoid with n turns per unit length carrying a current I?
-
A.
μ₀nI
-
B.
μ₀I/n
-
C.
μ₀I/2n
-
D.
μ₀I/4n
Solution
The magnetic field inside a long solenoid is given by B = μ₀nI.
Correct Answer:
A
— μ₀nI
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Q. What is the magnetic field inside a long solenoid? (2023)
-
A.
Zero
-
B.
Uniform and parallel
-
C.
Concentric circles
-
D.
Decreasing
Solution
The magnetic field inside a long solenoid is uniform and parallel to the axis of the solenoid.
Correct Answer:
B
— Uniform and parallel
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Q. What is the magnetic field inside a long straight conductor carrying a current I?
-
A.
0
-
B.
μ₀I/2πr
-
C.
μ₀I/4πr
-
D.
μ₀I/πr
Solution
Using Ampere's Law, B = μ₀I/2πr for a long straight conductor.
Correct Answer:
B
— μ₀I/2πr
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Q. What is the magnetic field inside a long straight conductor carrying current I?
-
A.
0
-
B.
μ₀I/2πr
-
C.
μ₀I/4πr
-
D.
μ₀I/πr
Solution
Using Ampere's Law, B = μ₀I/2πr for a long straight conductor.
Correct Answer:
B
— μ₀I/2πr
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Q. What is the magnetic field inside a long, ideal solenoid carrying current I?
-
A.
Zero
-
B.
μ₀I
-
C.
μ₀I/n
-
D.
μ₀nI
Solution
The magnetic field inside a long, ideal solenoid is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer:
D
— μ₀nI
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