Length = |5 - 2| = 3.

In an equilateral triangle, the median is equal to the side length, so it is 10 cm.

Median length m_a = 1/2 * √(2b^2 + 2c^2 - a^2) = 1/2 * √(2*8^2 + 2*10^2 - 6^2) = 1/2 * √(128 + 200 - 36) = 1/2 * √292 = 7.

Using the median formula: m_a = 1/2 * sqrt(2b^2 + 2c^2 - a^2), where a = BC, b = AC, c = AB. m_a = 1/2 * sqrt(2*6^2 + 2*10^2 - 8^2) = 7 cm.

The x-intercept is (4, 0) and the y-intercept is (0, 3). The length of the segment is sqrt((4-0)^2 + (0-3)^2) = sqrt(16 + 9) = 5.

Using the tangent length formula: length = √(distance from center² - radius²) = √(10² - 6²) = √(100 - 36) = √64 = 8.

As x approaches infinity, (1/x) approaches 0.

Using L'Hôpital's Rule, lim (x -> 1) (x^2 - 1)/(x - 1) = lim (x -> 1) (2x)/(1) = 2.

As x approaches 0 from the right, f(x) approaches infinity, indicating a discontinuity at x = 0.

Using the identity 1 - cos(x) = 2sin^2(x/2), we have lim (x -> 0) (1 - cos(x))/(x^2) = lim (x -> 0) (2sin^2(x/2))/(x^2) = 1/2.

Using the Taylor series expansion for cos(x), we find that lim (x -> 0) (cos(x) - 1)/x^2 = -1/2.

Using the derivative of e^x at x = 0, we find that lim (x -> 0) (e^x - 1)/x = 1.

Using L'Hôpital's Rule, we differentiate the numerator and denominator to find lim (x -> 0) (1/(1 + x)) = 1.

Using the limit lim (x -> 0) (tan(x)/x) = 1, we have lim (x -> 0) (tan(3x)/x) = 3 * lim (x -> 0) (tan(3x)/(3x)) = 3.

Factoring gives (x - 1)(x + 1)/(x - 1), which simplifies to x + 1. Thus, lim (x -> 1) (x + 1) = 2.

The reaction requires 1.5 moles of B for 3 moles of A. Since only 2 moles of B are available, B is the limiting reagent.

The reaction requires 2 moles of B for every mole of A. For 5 moles of A, 10 moles of B are needed. Since only 3 moles of B are available, B is the limiting reagent.

The total difference is 60° + 120° = 180°. This is 12 hours difference. Therefore, 6:00 AM + 12 hours = 6:00 PM.

120°E is 120/15 = 8 hours ahead. Therefore, 3:00 PM + 8 hours = 11:00 PM.

150 degrees East is 150/15 = 10 hours ahead of GMT. Therefore, 12:00 noon + 10 hours = 10:00 PM.

The time difference is (15° / 15°) = 1 hour. Therefore, it is 6:00 PM + 1 hour = 7:00 PM.

45°E corresponds to 45 / 15 = 3 hours ahead of GMT, so it will be 12:00 noon + 3 hours = 3:00 PM.

45°E is 45 * 4 = 180 minutes ahead of GMT, which is 3 hours. Therefore, 6:00 PM + 3 hours = 9:00 PM.

At 75°W, the time is 75° / 15° = 5 hours behind GMT. Therefore, 3:00 PM GMT - 5 hours = 10:00 AM.

90 degrees East is 6 hours ahead of GMT, so 6:00 AM + 6 hours = 12:00 PM.

The correct sequence is C, A, B, D, as it follows a coherent flow of ideas.

The correct sequence is C, A, B, D, as it follows a coherent flow of ideas from the introduction to the conclusion.

The magnetic field around a straight conductor carrying current forms concentric circles around the wire.

The magnetic field around a straight current-carrying conductor forms concentric circles around the wire, as described by Ampère's circuital law.

The magnetic field around a long straight wire is given by B = (μ₀I)/(2πr).