Arc length = (θ/360) * 2πr = (90/360) * 2π * 4 = 2π cm.

Arc length = (θ/360) * 2πr = (60/360) * 2π(5) = (1/6) * 10π ≈ 5.24 cm.

Arc length = (θ/360) * 2πr = (60/360) * 2 * 3.14 * 6 cm = 6.28 cm.

Arc length = (θ/360) × 2πr = (60/360) × 2π(7) = (1/6) × 14π = 7π/3 cm.

Arc length = (θ/360) * 2πr = (60/360) * 2 * π * 5 = 5.24 cm.

Arc length = (θ/360) × 2πr = (60/360) × 2π(5) = (1/6) × 10π = 5π/6 cm.

Using the area formula, Area = 1/2 * base * height. The area can also be calculated using Heron's formula, which gives 24. Thus, height = (2 * Area) / base = (2 * 24) / 10 = 4.8.

Using the area formula, Area = 1/2 * base * height. First, find the area using Heron's formula, then use it to find the height.

The area of the triangle can be calculated as (1/2) * base * height. The area is 30 cm² (since it's a right triangle). Using area = (1/2) * 12 * height, we find height = 5 cm.

In a right triangle, the altitude from the right angle to the hypotenuse is equal to the length of the other side. Thus, the altitude is 6 cm.

Using Heron's formula, the area is 30 cm². The altitude = (2 * Area) / base = (2 * 30) / 13 = 6 cm.

Diagonal = √(2² + 3² + 6²) = √(4 + 9 + 36) = √49 = 7.

The length of the diagonal d of a rectangle can be found using the Pythagorean theorem: d = √(length² + width²) = √(6² + 8²) = √(36 + 64) = √100 = 10 cm.

Diagonal = √(length² + width²) = √(3² + 4²) = √(9 + 16) = √25 = 5 cm

Diagonal = √(length² + width²) = √(6² + 8²) = √(36 + 64) = √100 = 10 cm

Diagonal = √[(4-0)² + (3-0)²] = √[16 + 9] = √25 = 5.

Diagonal length = √[(3-0)² + (4-0)²] = √[9 + 16] = √25 = 5.

Length of diagonal = √[(4-0)² + (3-0)²] = √[16 + 9] = √25 = 5.

Diagonal length = √[(5-1)² + (4-1)²] = √[16 + 9] = √25 = 5.

Area = πr². Given area = 50π, r² = 50, r = √50 = 5√2. Diameter = 2r = 10√2 units.

The diameter is twice the radius, so 2 * 7 = 14.

The radius is √16 = 4, so the diameter is 2 * radius = 8.

Using the Pythagorean theorem, c = √(a² + b²) = √(3² + 4²) = √(9 + 16) = √25 = 5.

The length of the latus rectum is given by (2b^2/a). Here, b^2 = 16, a^2 = 36, so length = (2*16/6) = 12.

The length of the latus rectum of the ellipse is given by 2a^2/b.

The length of the latus rectum of a parabola given by the equation y^2 = 4px is 4p. Here, 4p = 12, so p = 3. Therefore, the length of the latus rectum is 4p = 12.

The length of the latus rectum of the parabola y^2 = 4ax is 4a.

The length of the latus rectum of the parabola y^2 = 8x is 4.

Using the distance formula, length = sqrt((7-3)^2 + (1-4)^2) = sqrt(16 + 9) = 5.

Length = √[(2 - (-1))² + (3 - (-1))²] = √[3² + 4²] = √25 = 5.