The acceleration of a rolling object down an incline is given by g sin(θ)/2, considering both translational and rotational motion.

'Quickly' is the adverb that describes how he finished his homework.

'Atmanirbhar Bharat' aims to promote self-reliance in various sectors of the Indian economy.

The Pradhan Mantri Ujjwala Yojana aims to provide clean cooking fuel to women from below poverty line households.

The angle between a tangent to a circle and a chord drawn from the point of contact is always 90 degrees.

The angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment.

The angle between a tangent and a radius at the point of tangency is always 90 degrees.

The angle between Magnetic North and True North is known as Declination.

The slopes of the lines are -2/3 and 4. The angle θ can be found using tan(θ) = |(m1 - m2) / (1 + m1*m2)|.

The slopes of the lines are -2/3 and 4. The angle θ can be found using tan(θ) = |(m1 - m2) / (1 + m1*m2)|.

Using the formula for the angle between two lines, we find that the angle is 90 degrees.

The angle can be calculated using the slopes derived from the equation, leading to 90 degrees.

By completing the square, we can find the slopes of the lines and calculate the angle between them.

The slopes are m1 = 2 and m2 = -1/2. The angle θ between the lines is given by tan(θ) = |(m1 - m2) / (1 + m1*m2)|, which results in 90 degrees.

The slopes are m1 = 2 and m2 = -0.5. The angle θ is given by tan(θ) = |(m1 - m2) / (1 + m1*m2)| = |(2 + 0.5) / (1 - 1)|, which is undefined, indicating 90 degrees.

The slopes are m1 = 2 and m2 = -1/2. The angle θ = tan^(-1) |(m1 - m2) / (1 + m1*m2)| = tan^(-1)(5/4) which is approximately 60 degrees.

The slopes are m1 = 2 and m2 = -1/2. The angle θ = tan^(-1) |(m1 - m2) / (1 + m1*m2)| = tan^(-1)(5/0) = 90 degrees.

The slopes are m1 = 3 and m2 = -1/3. The angle θ = tan⁻¹(|(m1 - m2) / (1 + m1*m2)|) = tan⁻¹(10/8) = 90 degrees.

The angle between (1, 0) and (0, 1) is 90 degrees.

Cosine of angle θ = (u · v) / (|u| |v|). Calculate to find θ = 60 degrees.

cos(θ) = (a · b) / (|a| |b|). Calculate a · b = 1*2 + 2*0 + 2*2 = 6, |a| = √(1^2 + 2^2 + 2^2) = 3, |b| = √(2^2 + 0^2 + 2^2) = 2√2. Thus, cos(θ) = 6 / (3 * 2√2) = 1/√2, θ = 45 degrees.

cos(θ) = (A · B) / (|A||B|) = (8) / (√8 * √8) = 1, θ = 0 degrees.

cos(θ) = (A · B) / (|A||B|) = (1*2 + 1*2) / (√2 * √8) = 4 / (2√2) = √2. θ = 45 degrees.

The angle between u and v is 90 degrees since they are perpendicular.

In uniform circular motion, velocity is tangential and acceleration is radial, hence the angle is 90°.

The angle between two tangents from a point outside a circle is given by the formula: angle = 90° - (angle subtended by the radius at the point of tangency). Here, the angle is 45°.

The angle between the two tangents is twice the angle between the radius and the tangent, so it is 2 * 45 = 90 degrees.

The angle θ = cos⁻¹((A . B) / (|A| |B|)) = cos⁻¹(0) = 90 degrees.

The angle for the first minimum is given by sin θ = λ/a, where a is the slit width. Thus, sin θ = 500 nm / 0.5 mm = 0.001, leading to θ ≈ 30°.

Light is completely polarized upon reflection at Brewster's angle, which is given by the formula tan(θ_B) = n2/n1.