Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. Find the area under the curve y = x^2 from x = 0 to x = 3.
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Solution
Area = ∫ from 0 to 3 of x^2 dx = [1/3 * x^3] from 0 to 3 = 9.
Correct Answer:
A
— 9
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Q. Find the area under the curve y = x^2 from x = 1 to x = 3.
A.
8/3
B.
10/3
C.
9/3
D.
7/3
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Solution
The area is given by the integral ∫ (x^2) dx from 1 to 3. This evaluates to [x^3/3] from 1 to 3 = (27/3 - 1/3) = 26/3.
Correct Answer:
B
— 10/3
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Q. Find the area under the curve y = x^4 from x = 0 to x = 1.
A.
1/5
B.
1/4
C.
1/3
D.
1/2
Show solution
Solution
The area under the curve y = x^4 from 0 to 1 is given by ∫(from 0 to 1) x^4 dx = [x^5/5] from 0 to 1 = 1/5.
Correct Answer:
A
— 1/5
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Q. Find the area under the curve y = x^4 from x = 0 to x = 2.
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Solution
The area is given by the integral from 0 to 2 of x^4 dx. This evaluates to [x^5/5] from 0 to 2 = (32/5) = 16.
Correct Answer:
C
— 16
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Q. Find the argument of the complex number z = -1 - i.
A.
-3π/4
B.
3π/4
C.
π/4
D.
-π/4
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Solution
The argument of z = -1 - i is θ = tan^(-1)(-1/-1) = 3π/4.
Correct Answer:
A
— -3π/4
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Q. Find the arithmetic mean of the first five prime numbers.
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Solution
First five primes: 2, 3, 5, 7, 11. Mean = (2 + 3 + 5 + 7 + 11) / 5 = 28 / 5 = 5.6.
Correct Answer:
C
— 7
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Q. Find the arithmetic mean of the numbers 12, 15, 18, 21, and 24.
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Solution
Mean = (12 + 15 + 18 + 21 + 24) / 5 = 90 / 5 = 18.
Correct Answer:
A
— 18
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Q. Find the coefficient of x^0 in the expansion of (2x + 3)^4.
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Solution
The coefficient of x^0 is C(4, 0) * (2x)^0 * 3^4 = 1 * 81 = 81.
Correct Answer:
A
— 81
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Q. Find the coefficient of x^1 in the expansion of (x + 2)^5.
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Solution
The coefficient of x^1 is C(5,1) * 2^4 = 5 * 16 = 80.
Correct Answer:
B
— 20
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Q. Find the coefficient of x^2 in the expansion of (3x - 4)^6.
A.
540
B.
720
C.
480
D.
360
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Solution
The coefficient of x^2 is C(6,2) * (3)^2 * (-4)^4 = 15 * 9 * 256 = 34560.
Correct Answer:
B
— 720
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Q. Find the coefficient of x^3 in the expansion of (2x - 3)^6.
A.
-540
B.
-720
C.
540
D.
720
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Solution
The coefficient of x^3 is C(6,3)(2)^3(-3)^3 = 20 * 8 * (-27) = -4320.
Correct Answer:
A
— -540
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Q. Find the coefficient of x^3 in the expansion of (x + 1/2)^6.
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Solution
The coefficient of x^3 is C(6,3) * (1/2)^3 = 20 * 1/8 = 2.5.
Correct Answer:
B
— 15
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Q. Find the coefficient of x^3 in the expansion of (x + 2)^6.
A.
80
B.
120
C.
160
D.
240
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Solution
The coefficient of x^3 is C(6,3) * (2)^3 = 20 * 8 = 160.
Correct Answer:
B
— 120
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Q. Find the coefficient of x^3 in the expansion of (x - 1)^5.
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Solution
The coefficient of x^3 is C(5,3) * (-1)^2 = 10.
Correct Answer:
A
— -10
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Q. Find the coefficient of x^3 in the expansion of (x - 1)^6.
A.
-20
B.
-15
C.
-10
D.
-6
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Solution
The coefficient of x^3 is C(6,3) * (-1)^3 = 20 * (-1) = -20.
Correct Answer:
A
— -20
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Q. Find the coefficient of x^3 in the expansion of (x - 3)^5.
A.
-135
B.
-90
C.
-60
D.
-45
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Solution
The coefficient of x^3 is C(5,3) * (-3)^2 = 10 * 9 = -90.
Correct Answer:
A
— -135
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Q. Find the coefficient of x^4 in the expansion of (3x - 2)^6.
A.
540
B.
720
C.
810
D.
960
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Solution
Using the binomial theorem, the coefficient of x^4 in (3x - 2)^6 is given by 6C4 * (3)^4 * (-2)^2 = 15 * 81 * 4 = 4860.
Correct Answer:
C
— 810
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Q. Find the coefficient of x^5 in the expansion of (x + 1)^8.
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Solution
The coefficient of x^5 is C(8,5) = 56.
Correct Answer:
B
— 70
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Q. Find the coefficient of x^5 in the expansion of (x + 3)^8.
A.
56
B.
168
C.
336
D.
672
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Solution
The coefficient of x^5 is C(8,5) * (3)^3 = 56 * 27 = 1512.
Correct Answer:
B
— 168
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Q. Find the coefficient of x^5 in the expansion of (x - 3)^7.
A.
-1890
B.
-2187
C.
-2401
D.
-2430
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Solution
The coefficient of x^5 is C(7,5) * (-3)^2 = 21 * 9 = -1890.
Correct Answer:
A
— -1890
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Q. Find the condition for the lines represented by the equation 2x^2 + 3xy + y^2 = 0 to be parallel.
A.
D = 0
B.
D > 0
C.
D < 0
D.
D = 1
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Solution
For the lines to be parallel, the discriminant D must be equal to 0.
Correct Answer:
A
— D = 0
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Q. Find the condition for the lines represented by the equation ax^2 + 2hxy + by^2 = 0 to be perpendicular.
A.
ab + h^2 = 0
B.
ab - h^2 = 0
C.
a + b = 0
D.
a - b = 0
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Solution
The condition for the lines to be perpendicular is given by the relation ab + h^2 = 0.
Correct Answer:
A
— ab + h^2 = 0
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Q. Find the condition for the lines represented by the equation ax^2 + 2hxy + by^2 = 0 to be parallel.
A.
h^2 = ab
B.
h^2 > ab
C.
h^2 < ab
D.
h^2 = 0
Show solution
Solution
The condition for the lines to be parallel is given by h^2 = ab.
Correct Answer:
A
— h^2 = ab
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Q. Find the conjugate of the complex number z = 5 - 6i.
A.
5 + 6i
B.
5 - 6i
C.
-5 + 6i
D.
-5 - 6i
Show solution
Solution
The conjugate of z = 5 - 6i is z̅ = 5 + 6i.
Correct Answer:
A
— 5 + 6i
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Q. Find the coordinates of the centroid of the triangle with vertices at (0, 0), (6, 0), and (3, 6).
A.
(3, 2)
B.
(3, 3)
C.
(2, 3)
D.
(0, 0)
Show solution
Solution
Centroid = ((x1+x2+x3)/3, (y1+y2+y3)/3) = (9/3, 6/3) = (3, 2).
Correct Answer:
B
— (3, 3)
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Q. Find the coordinates of the centroid of the triangle with vertices at (1, 2), (3, 4), and (5, 6).
A.
(3, 4)
B.
(2, 3)
C.
(4, 5)
D.
(5, 6)
Show solution
Solution
Centroid = ((1+3+5)/3, (2+4+6)/3) = (3, 4).
Correct Answer:
B
— (2, 3)
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Q. Find the coordinates of the focus of the parabola y^2 = -12x.
A.
(-3, 0)
B.
(-2, 0)
C.
(3, 0)
D.
(2, 0)
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Solution
The equation y^2 = -12x can be rewritten as (y - 0)^2 = 4p(x - 0) with p = -3, so the focus is at (-3, 0).
Correct Answer:
A
— (-3, 0)
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Q. Find the coordinates of the foot of the perpendicular from the point (1, 2) to the line 2x - 3y + 6 = 0.
A.
(0, 2)
B.
(1, 1)
C.
(2, 0)
D.
(3, -1)
Show solution
Solution
Using the formula for foot of perpendicular, we find the coordinates to be (1, 1).
Correct Answer:
B
— (1, 1)
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Q. Find the coordinates of the foot of the perpendicular from the point (3, 4) to the line 2x + 3y - 6 = 0.
A.
(2, 0)
B.
(1, 1)
C.
(0, 2)
D.
(3, 2)
Show solution
Solution
Using the formula for foot of perpendicular, we find the coordinates to be (3, 2).
Correct Answer:
D
— (3, 2)
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Q. Find the coordinates of the point on the curve y = x^3 - 3x + 2 where the slope of the tangent is 0.
A.
(1, 0)
B.
(0, 2)
C.
(2, 0)
D.
(3, 2)
Show solution
Solution
f'(x) = 3x^2 - 3. Setting f'(x) = 0 gives x^2 = 1, so x = 1 or x = -1. f(1) = 0, f(-1) = 4. The point is (1, 0).
Correct Answer:
A
— (1, 0)
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