Major Competitive Exams

My Learning Cart

Major Competitive Exams

Download Q&A

Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

Civil Services Defence Exams Engineering & Architecture Admissions Government Jobs Management Admissions Undergraduate

Q. A jar contains 5 red, 3 blue, and 2 yellow marbles. If one marble is drawn, what is the probability that it is either red or yellow?

A. 1/2
B. 2/5
C. 4/10
D. 7/10

Solution

Total marbles = 5 + 3 + 2 = 10. Probability of red or yellow = (Number of red + Number of yellow) / Total = (5 + 2) / 10 = 7/10.

Correct Answer: D — 7/10

Q. A jar contains 5 red, 3 blue, and 2 yellow marbles. What is the probability of drawing a yellow marble?

A. 1/5
B. 1/10
C. 1/4
D. 1/6

Solution

Total marbles = 5 + 3 + 2 = 10. Probability of drawing a yellow marble = Number of yellow marbles / Total marbles = 2/10 = 1/5.

Correct Answer: B — 1/10

Q. A jar contains 5 red, 3 blue, and 2 yellow marbles. What is the probability of picking a yellow marble? (2023)

A. 1/5
B. 1/10
C. 1/4
D. 1/2

Solution

Total marbles = 5 + 3 + 2 = 10. Probability of picking a yellow marble = Number of yellow marbles / Total marbles = 2/10 = 1/5.

Correct Answer: B — 1/10

Q. A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is either red or green?

A. 1/2
B. 2/5
C. 4/5
D. 3/5

Solution

Total marbles = 5 + 3 + 2 = 10. Favorable outcomes (red or green) = 5 + 3 = 8. Probability = 8/10 = 4/5.

Correct Answer: C — 4/5

Q. A jar contains 5 red, 3 green, and 2 blue marbles. What is the probability of drawing a green marble?

A. 1/5
B. 1/4
C. 3/10
D. 1/2

Solution

Total marbles = 5 + 3 + 2 = 10. Probability of green = 3/10.

Correct Answer: C — 3/10

Q. A jar contains 5 red, 3 green, and 2 yellow marbles. If one marble is drawn at random, what is the probability that it is either red or green?

A. 1/2
B. 4/5
C. 2/5
D. 3/5

Solution

The total number of marbles is 5 + 3 + 2 = 10. The number of favorable outcomes (red or green) is 5 + 3 = 8. Thus, the probability is 8/10 = 4/5.

Correct Answer: B — 4/5

Q. A jar contains 6 green and 4 yellow marbles. What is the probability of picking a yellow marble?

A. 2/5
B. 1/2
C. 4/10
D. 3/5

Solution

Total marbles = 6 + 4 = 10. Probability of yellow marble = 4/10 = 2/5.

Correct Answer: A — 2/5

Q. A jar contains 7 red, 5 blue, and 8 green marbles. What is the probability of selecting a blue marble?

A. 5/20
B. 1/4
C. 1/5
D. 1/3

Solution

Total marbles = 7 + 5 + 8 = 20. Probability of blue marble = 5/20 = 1/4.

Correct Answer: A — 5/20

Q. A jar contains 8 red and 4 blue marbles. What is the probability of selecting a blue marble?

A. 1/3
B. 1/2
C. 1/4
D. 1/5

Solution

Total marbles = 8 + 4 = 12. Probability of blue marble = 4/12 = 1/3.

Correct Answer: A — 1/3

Q. A jar contains 8 red, 6 blue, and 4 green marbles. What is the probability of selecting a blue marble?

A. 1/3
B. 1/4
C. 2/5
D. 3/10

Solution

Total marbles = 8 + 6 + 4 = 18. Probability of blue marble = 6/18 = 1/3.

Correct Answer: D — 3/10

Q. A job can be done by 8 men in 12 days. How many days will it take for 4 men to complete the same job?

A. 24 days
B. 30 days
C. 36 days
D. 48 days

Solution

If 8 men take 12 days, then 4 men will take (8 * 12) / 4 = 24 days.

Correct Answer: C — 36 days

Q. A journalist uncovers a scandal involving a public figure. They can publish the story, which could harm the public figure's reputation, or hold back for ethical reasons. What should they do?

A. Publish the story
B. Hold back the story
C. Investigate further
D. Consult with legal counsel

Solution

The journalist should publish the story if it serves the public interest, balancing ethics with the right to know.

Correct Answer: A — Publish the story

Q. A judge spends 1/3 of his time on civil cases and the rest on criminal cases. If he works 60 hours a week, how many hours does he spend on criminal cases?

A. 40
B. 30
C. 20
D. 50

Solution

Hours on criminal cases = 60 - (1/3 * 60) = 60 - 20 = 40 hours

Correct Answer: A — 40

Q. A key is to a lock as a password is to a _____.

A. computer
B. door
C. safe
D. file

Solution

A key unlocks a lock, just as a password unlocks a computer.

Correct Answer: A — computer

Q. A kite is flying at a height of 100 m. If the angle of elevation from a point on the ground to the kite is 30 degrees, how far is the point from the base of the kite?

A. 100 m
B. 200 m
C. 300 m
D. 400 m

Solution

Using tan(30°) = height/distance, we have 1/√3 = 100/distance. Therefore, distance = 100√3 ≈ 173.2 m.

Correct Answer: B — 200 m

Q. A kite is flying at a height of 100 meters. If the angle of depression from the kite to a point on the ground is 30 degrees, how far is the point from the point directly below the kite?

A. 50 m
B. 60 m
C. 70 m
D. 80 m

Solution

Using tan(30°) = 100/distance, we have 1/√3 = 100/distance. Therefore, distance = 100√3 ≈ 173.21 m.

Correct Answer: A — 50 m

Q. A kite is flying at a height of 30 m. If the angle of elevation from a point on the ground to the kite is 60 degrees, how far is the point from the base of the kite?

A. 15√3 m
B. 30 m
C. 10√3 m
D. 20 m

Solution

Using tan(60°) = height/distance, we have distance = height/tan(60°) = 30/√3 = 15√3 m.

Correct Answer: A — 15√3 m

Q. A kite is flying at a height of 30 meters. If the angle of elevation from a point on the ground to the kite is 45 degrees, how far is the point from the base of the kite?

A. 15 m
B. 30 m
C. 45 m
D. 60 m

Solution

Using tan(45°) = height/distance, we have 1 = 30/distance. Therefore, distance = 30 m.

Correct Answer: B — 30 m

Q. A kite is flying at a height of 40 meters. If the angle of elevation from a point on the ground to the kite is 45 degrees, how far is the point from the base of the kite?

A. 40 meters
B. 20√2 meters
C. 30 meters
D. 50 meters

Solution

Using tan(45°) = height / distance, we have distance = height / tan(45°) = 40 / 1 = 40 meters.

Correct Answer: B — 20√2 meters

Q. A kite is flying at a height of 40 meters. If the angle of elevation from a point on the ground to the kite is 30 degrees, how far is the point from the base of the kite?

A. 40√3 meters
B. 20√3 meters
C. 30 meters
D. 50 meters

Solution

Using the tangent function, tan(30) = 40 / distance. Therefore, distance = 40 / tan(30) = 40√3 meters.

Correct Answer: A — 40√3 meters

Q. A kite is flying at a height of 40 meters. If the angle of elevation from a point on the ground to the kite is 60 degrees, how far is the point from the base of the kite's height?

A. 20√3 meters
B. 40 meters
C. 30 meters
D. 10√3 meters

Solution

Using tan(60) = 40/distance, distance = 40/tan(60) = 40/√3 = 20√3 meters.

Correct Answer: A — 20√3 meters

Q. A kite is flying at a height of 50 m. If the angle of elevation from a point on the ground to the kite is 60 degrees, how far is the point from the base of the kite? (2021)

A. 25 m
B. 50 m
C. 75 m
D. 100 m

Solution

Distance = height / tan(angle) = 50 / tan(60) = 50 / √3 ≈ 25 m.

Correct Answer: A — 25 m

Q. A kite is flying at a height of 50 m. If the angle of elevation from a point on the ground to the kite is 45 degrees, how far is the point from the base of the kite? (2020)

A. 50 m
B. 70 m
C. 100 m
D. 30 m

Solution

Using tan(45) = 1, distance = height = 50 m.

Correct Answer: A — 50 m

Q. A kite is flying at a height of 50 meters. If the angle of elevation from a point on the ground to the kite is 30 degrees, how far is the point from the base of the kite?

A. 50√3 meters
B. 25√3 meters
C. 100 meters
D. 75 meters

Solution

Distance = height / tan(angle) = 50 / (1/√3) = 50√3 meters.

Correct Answer: B — 25√3 meters

Q. A kite is flying at a height of 50 meters. If the angle of elevation from a point on the ground to the kite is 45 degrees, how far is the point from the base of the kite?

A. 50 meters
B. 25 meters
C. 35 meters
D. 70 meters

Solution

Using the tangent function, tan(45) = 50 / distance. Therefore, distance = 50 / tan(45) = 50 meters.

Correct Answer: A — 50 meters

Q. A laboratory has 3 bioreactors. If each bioreactor can process 200 liters of culture, what is the total capacity of the laboratory?

A. 400 liters
B. 600 liters
C. 800 liters
D. 1000 liters

Solution

Total capacity = 3 bioreactors * 200 liters/bioreactor = 600 liters.

Correct Answer: C — 800 liters

Q. A ladder 10 m long reaches a window 8 m above the ground. What is the angle of elevation of the ladder from the ground?

A. 30 degrees
B. 45 degrees
C. 60 degrees
D. 75 degrees

Solution

Using sin(θ) = opposite/hypotenuse, we have sin(θ) = 8/10. Therefore, θ = sin⁻¹(0.8) ≈ 53.13 degrees.

Correct Answer: C — 60 degrees

Q. A ladder 10 m long reaches a window 8 m high. What is the angle of elevation of the ladder from the ground? (2019)

A. 30 degrees
B. 45 degrees
C. 60 degrees
D. 75 degrees

Solution

Using sin(θ) = opposite/hypotenuse, sin(θ) = 8/10, θ = sin⁻¹(0.8) ≈ 53.13 degrees.

Correct Answer: C — 60 degrees

Q. A ladder 10 meters long leans against a wall, forming an angle of 60 degrees with the ground. How high does the ladder reach on the wall?

A. 5 meters
B. 8.66 meters
C. 10 meters
D. 7.5 meters

Solution

Using sin(60°) = height / ladder length, we have height = ladder length * sin(60°) = 10 * (√3/2) = 5√3 ≈ 8.66 meters.

Correct Answer: B — 8.66 meters

Q. A ladder 10 meters long leans against a wall, making an angle of 60 degrees with the ground. How high does the ladder reach on the wall?

A. 5 meters
B. 10 meters
C. 8.66 meters
D. 7.5 meters

Solution

Using sine, height = 10 * sin(60) = 10 * (√3/2) = 5√3 ≈ 8.66 meters.

Correct Answer: C — 8.66 meters

Showing 1861 to 1890 of 31669 (1056 Pages)

School

College

Degree

Competitve

Skills

Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely