Q. Which of the following complexes exhibits geometrical isomerism?
A.
[Co(NH3)3Cl3]
B.
[Ni(CN)4]2-
C.
[CuCl4]2-
D.
[Fe(CO)6]
Show solution
Solution
[Co(NH3)3Cl3] can exhibit geometrical isomerism due to the presence of different ligands in a square planar geometry.
Correct Answer:
A
— [Co(NH3)3Cl3]
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Q. Which of the following complexes exhibits optical isomerism?
A.
[Cr(en)3]3+
B.
[Co(NH3)6]3+
C.
[NiCl2(H2O)4]
D.
[CuCl2]
Show solution
Solution
The complex [Cr(en)3]3+ exhibits optical isomerism due to its chiral nature.
Correct Answer:
A
— [Cr(en)3]3+
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Q. Which of the following complexes is an example of a bidentate ligand?
A.
[Cu(NH3)4]SO4
B.
[Fe(CN)6]3-
C.
[Ni(en)3]Cl2
D.
[AgCl2]-
Show solution
Solution
Ethylenediamine (en) is a bidentate ligand as it can form two bonds with the metal ion.
Correct Answer:
C
— [Ni(en)3]Cl2
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Q. Which of the following complexes is expected to be diamagnetic?
A.
[Fe(H2O)6]3+
B.
[Cu(NH3)4]2+
C.
[Co(NH3)6]3+
D.
[Ni(CO)4]
Show solution
Solution
[Ni(CO)4] is diamagnetic because all electrons are paired in the presence of the strong field ligand CO.
Correct Answer:
D
— [Ni(CO)4]
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Q. Which of the following complexes is paramagnetic?
A.
[Fe(CN)6]3-
B.
[Co(NH3)6]3+
C.
[CuCl4]2-
D.
[MnO4]-
Show solution
Solution
[Co(NH3)6]3+ has unpaired electrons and is therefore paramagnetic.
Correct Answer:
B
— [Co(NH3)6]3+
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Q. Which of the following compounds can act as a reducing agent?
A.
H2O2
B.
Cl2
C.
Na
D.
O2
Show solution
Solution
Sodium (Na) can act as a reducing agent as it readily donates electrons.
Correct Answer:
C
— Na
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Q. Which of the following compounds can act as an oxidizing agent?
A.
NaCl
B.
H2O
C.
KMnO4
D.
C6H12O6
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Solution
KMnO4 is a strong oxidizing agent due to the presence of Mn in a high oxidation state.
Correct Answer:
C
— KMnO4
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Q. Which of the following compounds can be classified as a ketone?
A.
C3H6O
B.
C2H4O
C.
C4H8O
D.
C5H10O
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Solution
C3H6O (acetone) is a ketone, characterized by the carbonyl group (C=O) between two carbon atoms.
Correct Answer:
A
— C3H6O
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Q. Which of the following compounds can be distinguished from aldehydes using Tollen's reagent?
A.
Acetone
B.
Formaldehyde
C.
Benzaldehyde
D.
Propionaldehyde
Show solution
Solution
Tollen's reagent can oxidize aldehydes but not ketones. Acetone is a ketone and will not react.
Correct Answer:
A
— Acetone
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Q. Which of the following compounds can be formed by the decarboxylation of a carboxylic acid?
A.
Alkane
B.
Alkene
C.
Alkyne
D.
Aldehyde
Show solution
Solution
Decarboxylation of a carboxylic acid typically yields an alkane.
Correct Answer:
A
— Alkane
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Q. Which of the following compounds can be formed by the decarboxylation of sodium acetate?
A.
Methane
B.
Ethane
C.
Propane
D.
Butane
Show solution
Solution
Decarboxylation of sodium acetate yields methane.
Correct Answer:
A
— Methane
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Q. Which of the following compounds can be formed by the elimination reaction of 2-bromobutane?
A.
1-Butene
B.
2-Butene
C.
Butyne
D.
All of the above
Show solution
Solution
2-bromobutane can undergo elimination to form both 1-butene and 2-butene.
Correct Answer:
B
— 2-Butene
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Q. Which of the following compounds can be formed by the esterification of a carboxylic acid?
A.
Alcohol
B.
Ester
C.
Amide
D.
Aldehyde
Show solution
Solution
Ester is formed by the reaction of a carboxylic acid with an alcohol in an esterification reaction.
Correct Answer:
B
— Ester
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Q. Which of the following compounds can be formed by the esterification of acetic acid?
A.
Ethyl acetate
B.
Methyl acetate
C.
Butyl acetate
D.
All of the above
Show solution
Solution
All of the listed compounds can be formed by the esterification of acetic acid with the respective alcohols.
Correct Answer:
D
— All of the above
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Q. Which of the following compounds can be formed by the reaction of an aldehyde with a Grignard reagent?
A.
Alcohol
B.
Carboxylic acid
C.
Ketone
D.
Ester
Show solution
Solution
The reaction of an aldehyde with a Grignard reagent forms a primary alcohol after hydrolysis.
Correct Answer:
A
— Alcohol
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Q. Which of the following compounds can be oxidized to a ketone?
A.
1-butanol
B.
2-butanol
C.
tert-butanol
D.
Cyclohexanol
Show solution
Solution
2-butanol can be oxidized to form a ketone, specifically butanone.
Correct Answer:
B
— 2-butanol
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Q. Which of the following compounds can be prepared by the reaction of an alkyl halide with magnesium?
A.
Grignard reagent
B.
Alkoxide
C.
Alcohol
D.
Ether
Show solution
Solution
The reaction of an alkyl halide with magnesium forms a Grignard reagent, which is a key intermediate in organic synthesis.
Correct Answer:
A
— Grignard reagent
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Q. Which of the following compounds can be reduced to an alcohol using NaBH4?
A.
Aldehyde
B.
Ketone
C.
Both Aldehyde and Ketone
D.
None of the above
Show solution
Solution
Both aldehydes and ketones can be reduced to their corresponding alcohols using sodium borohydride (NaBH4).
Correct Answer:
C
— Both Aldehyde and Ketone
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Q. Which of the following compounds can be reduced to an alcohol?
A.
Aldehyde
B.
Ketone
C.
Both Aldehyde and Ketone
D.
None of the above
Show solution
Solution
Both aldehydes and ketones can be reduced to their corresponding alcohols.
Correct Answer:
C
— Both Aldehyde and Ketone
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Q. Which of the following compounds can be used to distinguish between aldehydes and ketones?
A.
Benedict's solution
B.
Tollens' reagent
C.
Fehling's solution
D.
All of the above
Show solution
Solution
Tollens' reagent can be used to distinguish aldehydes from ketones, as it oxidizes aldehydes but not ketones.
Correct Answer:
B
— Tollens' reagent
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Q. Which of the following compounds can exhibit both cis and trans isomerism?
A.
1-hexene
B.
2-hexene
C.
hexane
D.
cyclohexane
Show solution
Solution
2-hexene can exist in cis and trans forms due to the presence of a double bond.
Correct Answer:
B
— 2-hexene
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Q. Which of the following compounds can exhibit both geometric and optical isomerism?
A.
2-butene
B.
3-pentanol
C.
2-pentene
D.
1,2-dichloropropane
Show solution
Solution
3-pentanol has a chiral center and can also have geometric isomers due to the presence of a double bond.
Correct Answer:
B
— 3-pentanol
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Q. Which of the following compounds can exhibit both structural and geometric isomerism?
A.
Cis-2-butene
B.
1,3-butadiene
C.
Cyclohexane
D.
2-pentene
Show solution
Solution
1,3-butadiene can have structural isomers and also exhibit geometric isomerism due to its double bonds.
Correct Answer:
B
— 1,3-butadiene
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Q. Which of the following compounds can exhibit geometric isomerism?
A.
1-Butene
B.
2-Butene
C.
Cyclohexane
D.
Propane
Show solution
Solution
2-Butene can exhibit geometric isomerism due to the presence of a double bond with different groups attached.
Correct Answer:
B
— 2-Butene
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Q. Which of the following compounds can exhibit tautomeric isomerism?
A.
Acetone
B.
Ethanol
C.
Acetic acid
D.
Phenol
Show solution
Solution
Acetic acid can exist in two forms (keto and enol) and thus exhibits tautomeric isomerism.
Correct Answer:
C
— Acetic acid
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Q. Which of the following compounds can show cis-trans isomerism?
A.
1-hexene
B.
Cyclohexane
C.
2-hexene
D.
Propane
Show solution
Solution
2-hexene has a double bond and can have cis and trans configurations.
Correct Answer:
C
— 2-hexene
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Q. Which of the following compounds can show tautomeric isomerism?
A.
Acetone
B.
Ethanol
C.
Acetic acid
D.
Phenol
Show solution
Solution
Acetic acid can exist in keto and enol forms, thus showing tautomeric isomerism.
Correct Answer:
C
— Acetic acid
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Q. Which of the following compounds can undergo aldol condensation?
A.
Acetone
B.
Benzaldehyde
C.
Formaldehyde
D.
Ethyl acetate
Show solution
Solution
Acetone can undergo aldol condensation due to the presence of alpha-hydrogens.
Correct Answer:
A
— Acetone
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Q. Which of the following compounds can undergo elimination reaction to form an alkene?
A.
1-chloropropane
B.
2-chloropropane
C.
3-chloropropane
D.
chlorobenzene
Show solution
Solution
2-chloropropane can undergo elimination to form propene, while the others are less favorable for elimination.
Correct Answer:
B
— 2-chloropropane
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Q. Which of the following compounds can undergo Friedel-Crafts alkylation?
A.
Benzene
B.
Cyclohexane
C.
Ethylene
D.
Acetylene
Show solution
Solution
Benzene can undergo Friedel-Crafts alkylation, a reaction where an alkyl group is introduced to the aromatic ring.
Correct Answer:
A
— Benzene
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Chemistry Syllabus (JEE Main) MCQ & Objective Questions
The Chemistry Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances performance in objective questions and MCQs. Regular practice with these types of questions is essential for scoring better and mastering important topics.
What You Will Practise Here
Basic Concepts of Chemistry
Atomic Structure and Chemical Bonding
States of Matter: Gases and Liquids
Thermodynamics and Thermochemistry
Equilibrium: Chemical and Ionic
Redox Reactions and Electrochemistry
Hydrocarbons and Environmental Chemistry
Exam Relevance
The Chemistry syllabus is a significant part of CBSE, State Boards, NEET, and JEE exams. Questions from this syllabus often appear in various formats, including multiple-choice questions, assertion-reason type questions, and numerical problems. Familiarity with the common question patterns can greatly enhance your exam preparation and confidence.
Common Mistakes Students Make
Misunderstanding the periodic trends and their implications.
Confusing different types of chemical bonds and their properties.
Neglecting to balance redox reactions properly.
Overlooking the significance of units in thermodynamic calculations.
Failing to apply concepts of equilibrium in problem-solving.
FAQs
Question: What are the key topics I should focus on in the Chemistry syllabus for JEE Main?Answer: Focus on atomic structure, chemical bonding, thermodynamics, and equilibrium as they are frequently tested.
Question: How can I improve my performance in Chemistry MCQs?Answer: Regular practice with past papers and understanding concepts deeply will help you tackle MCQs effectively.
Start your journey towards mastering the Chemistry Syllabus (JEE Main) by solving practice MCQs today. Test your understanding and build confidence for your exams!