Arithmetic Aptitude MCQ & Objective Questions
Arithmetic Aptitude is a crucial component of many school and competitive exams in India. Mastering this topic not only enhances your mathematical skills but also boosts your confidence in tackling objective questions. By practicing MCQs and important questions, you can significantly improve your exam preparation and scoring potential.
What You Will Practise Here
Basic operations: addition, subtraction, multiplication, and division
Fractions and decimals: conversions and calculations
Percentages: calculating and understanding percentage problems
Averages: finding mean, median, and mode
Ratios and proportions: solving ratio problems and direct/indirect proportions
Time, speed, and distance: understanding and applying related formulas
Simple and compound interest: calculating interests and their applications
Exam Relevance
Arithmetic Aptitude is a key area in various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect questions that test their understanding of basic arithmetic operations, problem-solving skills, and application of concepts in real-life scenarios. Common question patterns include direct calculations, word problems, and data interpretation, making it essential to be well-prepared.
Common Mistakes Students Make
Misunderstanding the question: Failing to read the problem carefully can lead to incorrect answers.
Calculation errors: Simple arithmetic mistakes can cost valuable marks.
Ignoring units: Not paying attention to units in word problems can lead to confusion.
Overlooking shortcuts: Not utilizing shortcuts and formulas can waste time during exams.
FAQs
Question: What are some effective ways to prepare for Arithmetic Aptitude MCQs?Answer: Regular practice with objective questions, reviewing key concepts, and taking timed quizzes can enhance your preparation.
Question: How can I improve my speed in solving Arithmetic Aptitude questions?Answer: Familiarizing yourself with common formulas and practicing under timed conditions can help improve your speed and accuracy.
Start solving practice MCQs today to test your understanding and strengthen your Arithmetic Aptitude skills. Remember, consistent practice is the key to success in your exams!
Q. If a person invests $5000 at a compound interest rate of 8% per annum, what will be the total amount after 3 years?
A.
$5920
B.
$6000
C.
$5934
D.
$5800
Show solution
Solution
Amount = 5000 * (1 + 0.08)^3 = 5000 * 1.259712 = $6298.56.
Correct Answer:
C
— $5934
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Q. If a person mixes two types of tea costing $20 and $30 per kg in the ratio 2:3, what is the cost price per kg of the mixture?
A.
$24
B.
$26
C.
$28
D.
$22
Show solution
Solution
Cost = (2*20 + 3*30) / (2 + 3) = (40 + 90) / 5 = 130 / 5 = $26.
Correct Answer:
B
— $26
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Q. If a person sells an article for $1200 at a profit of 20%, what was the cost price?
A.
$1000
B.
$1100
C.
$900
D.
$1200
Show solution
Solution
Cost Price = Selling Price / (1 + Profit%) = 1200 / 1.2 = $1000
Correct Answer:
A
— $1000
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Q. If a person spends 30% of his salary on rent and 20% on food, what percentage of his salary is left?
A.
50%
B.
40%
C.
30%
D.
60%
Show solution
Solution
Total expenditure = 30% + 20% = 50%. Salary left = 100% - 50% = 50%.
Correct Answer:
A
— 50%
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Q. If a person walks 5 km in 1 hour, how far will he walk in 3 hours at the same speed?
A.
10 km
B.
12 km
C.
15 km
D.
18 km
Show solution
Solution
Distance = Speed x Time = 5 km/h x 3 h = 15 km.
Correct Answer:
C
— 15 km
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Q. If a person walks 5 km in 1 hour, how long will it take to walk 20 km?
A.
3 hours
B.
4 hours
C.
5 hours
D.
6 hours
Show solution
Solution
Time = Distance / Speed = 20 km / (5 km/h) = 4 hours
Correct Answer:
C
— 5 hours
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Q. If a person walks at a speed of 4 km/h, how far can he walk in 3 hours?
A.
10 km
B.
12 km
C.
14 km
D.
15 km
Show solution
Solution
Distance = Speed × Time = 4 km/h × 3 h = 12 km.
Correct Answer:
B
— 12 km
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Q. If a person walks at a speed of 5 km/h, how long will it take to walk 15 km?
A.
2 hours
B.
3 hours
C.
4 hours
D.
5 hours
Show solution
Solution
Time = Distance / Speed = 15 km / 5 km/h = 3 hours.
Correct Answer:
B
— 3 hours
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Q. If a person works 8 hours a day and completes a task in 5 days, what is the total work done in hours?
A.
30 hours
B.
35 hours
C.
40 hours
D.
45 hours
Show solution
Solution
Total Work = Hours per Day * Days = 8 * 5 = 40 hours
Correct Answer:
C
— 40 hours
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Q. If a polynomial f(x) = x^2 - 4, what are its roots?
A.
-2, 2
B.
0, 4
C.
1, -1
D.
2, 2
Show solution
Solution
Setting f(x) = 0 gives x^2 - 4 = 0, so x = ±2.
Correct Answer:
A
— -2, 2
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Q. If a polynomial f(x) = x^2 - 4x + 4, what is f(2)?
Show solution
Solution
f(2) = 2^2 - 4*2 + 4 = 0.
Correct Answer:
A
— 0
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Q. If a polynomial f(x) = x^2 - 5x + 6, what are its roots?
A.
1 and 6
B.
2 and 3
C.
3 and 2
D.
5 and 1
Show solution
Solution
Factoring gives (x-2)(x-3) = 0, so roots are 2 and 3.
Correct Answer:
B
— 2 and 3
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Q. If a product is bought for $80 and sold for $100, what is the profit?
A.
$20
B.
$15
C.
$25
D.
$30
Show solution
Solution
Profit = Selling Price - Cost Price = 100 - 80 = $20.
Correct Answer:
A
— $20
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Q. If a product is marked at $150 and sold at a discount of 20%, what is the selling price?
A.
$120
B.
$130
C.
$140
D.
$110
Show solution
Solution
Discount = 20% of 150 = 0.20 * 150 = $30. Selling Price = Marked Price - Discount = 150 - 30 = $120.
Correct Answer:
A
— $120
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Q. If a product is marked at $250 and sold at a discount of 20%, what is the selling price?
A.
$200
B.
$210
C.
$220
D.
$230
Show solution
Solution
Selling Price = Marked Price - Discount = 250 - (20/100 * 250) = 250 - 50 = $200.
Correct Answer:
A
— $200
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Q. If a product is marked at $500 and sold at a discount of 10%, what is the selling price?
A.
$450
B.
$400
C.
$475
D.
$425
Show solution
Solution
Selling Price = Marked Price - Discount = 500 - (10% of 500) = 500 - 50 = $450.
Correct Answer:
C
— $475
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Q. If a product is sold for $120 after a profit of 20%, what was the cost price of the product?
A.
$80
B.
$90
C.
$100
D.
$110
Show solution
Solution
Let Cost Price = x. Then, 120 = x + 0.2x => 120 = 1.2x => x = 120/1.2 = $100.
Correct Answer:
A
— $80
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Q. If a product is sold for $150 after a loss of 10%, what was the cost price?
A.
$135
B.
$140
C.
$145
D.
$150
Show solution
Solution
Let Cost Price = x. Selling Price = x - 10% of x = 0.9x. 0.9x = 150. x = 150/0.9 = 166.67.
Correct Answer:
A
— $135
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Q. If a product is sold for $240 after a discount of 20%, what was the marked price?
A.
$300
B.
$280
C.
$250
D.
$320
Show solution
Solution
Let Marked Price = x. Selling Price = x - 20% of x = 0.8x. 0.8x = 240. x = 240/0.8 = 300.
Correct Answer:
A
— $300
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Q. If a product is sold for $80 after a discount of 20%, what was the original price?
A.
$90
B.
$100
C.
$110
D.
$120
Show solution
Solution
Let the original price be x. Then, x - 0.2x = 80, 0.8x = 80, x = 100.
Correct Answer:
B
— $100
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Q. If a runner completes a 10 km race in 50 minutes, what is his speed in km/h?
A.
10 km/h
B.
12 km/h
C.
14 km/h
D.
15 km/h
Show solution
Solution
Speed = Distance / Time = 10 km / (50/60) h = 12 km/h.
Correct Answer:
B
— 12 km/h
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Q. If a sequence is defined as a_n = 2n + 1, what is a_5?
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Solution
a_5 = 2(5) + 1 = 10 + 1 = 11.
Correct Answer:
A
— 9
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Q. If a sequence is defined as a_n = 3n + 1, what is a_4?
Show solution
Solution
a_4 = 3(4) + 1 = 12 + 1 = 13.
Correct Answer:
B
— 11
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Q. If a sequence is defined as a_n = 3n + 2, what is a_4?
Show solution
Solution
a_4 = 3(4) + 2 = 12 + 2 = 14.
Correct Answer:
B
— 14
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Q. If a sequence is defined by a_n = 2n + 1, what is a_4?
Show solution
Solution
a_4 = 2(4) + 1 = 8 + 1 = 9.
Correct Answer:
A
— 7
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Q. If a sequence is defined by a_n = 3n + 1, what is a_4?
Show solution
Solution
Substituting n = 4 gives a_4 = 3(4) + 1 = 12 + 1 = 13.
Correct Answer:
B
— 11
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Q. If a sequence is defined by a_n = 3n + 1, what is a_5?
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Solution
a_5 = 3(5) + 1 = 15 + 1 = 16.
Correct Answer:
A
— 14
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Q. If a sequence starts with 2 and each term is multiplied by 3, what is the 4th term?
A.
18
B.
54
C.
162
D.
486
Show solution
Solution
The sequence is 2, 6, 18, 54; the 4th term is 54.
Correct Answer:
C
— 162
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Q. If a shirt costs $40 and is sold for $50, what is the profit percentage?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Profit = Selling Price - Cost Price = 50 - 40 = 10. Profit Percentage = (10/40) * 100 = 25%.
Correct Answer:
B
— 25%
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Q. If a stock price increases from $40 to $50, what is the percentage increase?
A.
20%
B.
25%
C.
30%
D.
35%
Show solution
Solution
Percentage Increase = ((New Price - Old Price) / Old Price) * 100 = ((50 - 40) / 40) * 100 = 25%
Correct Answer:
B
— 25%
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