Mechanics MCQ & Objective Questions
Mechanics is a fundamental branch of physics that plays a crucial role in various school and competitive exams. Understanding mechanics not only helps in grasping essential concepts but also enhances problem-solving skills. Practicing MCQs and objective questions in mechanics is vital for effective exam preparation, as it allows students to familiarize themselves with important questions and boosts their confidence in tackling exam challenges.
What You Will Practise Here
Newton's Laws of Motion
Work, Energy, and Power
Gravitation and its Applications
Motion in One and Two Dimensions
Rotational Motion and Dynamics
Fluid Mechanics and Properties of Matter
Simple Harmonic Motion
Exam Relevance
Mechanics is a significant topic in various examinations, including CBSE, State Boards, NEET, and JEE. Questions from mechanics often appear in different formats, such as numerical problems, conceptual questions, and application-based scenarios. Students can expect to encounter both direct and indirect questions that test their understanding of key concepts and their ability to apply formulas effectively. Familiarity with common question patterns in mechanics can greatly enhance performance in these exams.
Common Mistakes Students Make
Confusing the application of Newton's laws in different scenarios.
Misunderstanding the concepts of work and energy, particularly in non-conservative forces.
Overlooking the significance of vector quantities in motion problems.
Failing to apply the right formulas in rotational motion questions.
Neglecting the importance of free-body diagrams in solving mechanics problems.
FAQs
Question: What are some effective ways to prepare for mechanics MCQs?Answer: Regular practice of MCQs, understanding key concepts, and solving previous years' question papers can significantly improve your preparation.
Question: How can I improve my speed in solving mechanics objective questions?Answer: Time yourself while practicing and focus on mastering the formulas and concepts to enhance your speed and accuracy.
Now is the time to take charge of your learning! Dive into our collection of mechanics MCQs and practice questions to solidify your understanding and excel in your exams. Remember, consistent practice is the key to success!
Q. What is the force required to keep a 2 kg object moving in a circle of radius 1 m at a speed of 3 m/s?
A.
6 N
B.
9 N
C.
3 N
D.
12 N
Show solution
Solution
Centripetal force F = mv²/r = 2 kg * (3 m/s)² / 1 m = 18 N.
Correct Answer:
B
— 9 N
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Q. What is the formula for calculating the focal length of a lens?
A.
1/f = 1/v + 1/u
B.
f = v + u
C.
f = v - u
D.
1/f = v - u
Show solution
Solution
The lens formula is given by 1/f = 1/v + 1/u, where f is the focal length, v is the image distance, and u is the object distance.
Correct Answer:
A
— 1/f = 1/v + 1/u
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Q. What is the formula for calculating the force acting on an object?
A.
F = ma
B.
F = mv
C.
F = m/g
D.
F = mg
Show solution
Solution
The force acting on an object is calculated using Newton's second law, F = ma, where F is force, m is mass, and a is acceleration.
Correct Answer:
A
— F = ma
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Q. What is the formula for calculating the force exerted by an object?
A.
F = ma
B.
F = mv
C.
F = m/g
D.
F = p/v
Show solution
Solution
The force exerted by an object is calculated using Newton's second law, F = ma, where F is force, m is mass, and a is acceleration.
Correct Answer:
A
— F = ma
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Q. What is the formula for calculating the gravitational force between two masses?
A.
F = ma
B.
F = G(m1*m2)/r^2
C.
F = mv^2/r
D.
F = qE
Show solution
Solution
The gravitational force between two masses is given by Newton's law of universal gravitation: F = G(m1*m2)/r^2, where G is the gravitational constant.
Correct Answer:
B
— F = G(m1*m2)/r^2
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Q. What is the formula for centripetal force?
A.
F = mv^2/r
B.
F = ma
C.
F = G(m1*m2)/r^2
D.
F = qE
Show solution
Solution
The formula for centripetal force is F = mv^2/r, where m is mass, v is velocity, and r is the radius of the circular path.
Correct Answer:
A
— F = mv^2/r
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Q. What is the formula for the induced electromotive force (emf) in a coil when the magnetic flux changes?
A.
emf = -dΦ/dt
B.
emf = F/q
C.
emf = W/t
D.
emf = mv^2/r
Show solution
Solution
The induced emf in a coil is given by Faraday's law of electromagnetic induction, which states that emf = -dΦ/dt, where Φ is the magnetic flux.
Correct Answer:
A
— emf = -dΦ/dt
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Q. What is the formula for the period of a simple harmonic oscillator?
A.
T = 2π√(m/k)
B.
T = 2π√(k/m)
C.
T = 2π(m/k)
D.
T = 2π(k/m)
Show solution
Solution
The period T of a simple harmonic oscillator is given by T = 2π√(m/k), where m is the mass and k is the spring constant.
Correct Answer:
B
— T = 2π√(k/m)
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Q. What is the gravitational force between two 10 kg masses separated by 2 m?
A.
25 N
B.
50 N
C.
100 N
D.
200 N
Show solution
Solution
Using Newton's law of gravitation, F = G(m1*m2)/r² = (6.674×10⁻¹¹)(10 kg)(10 kg)/(2 m)² = 50 N.
Correct Answer:
B
— 50 N
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Q. What is the gravitational force between two 10 kg masses separated by 2 meters?
A.
0.25 N
B.
5 N
C.
10 N
D.
20 N
Show solution
Solution
Using Newton's law of gravitation, F = G(m1*m2)/r² = (6.674×10⁻¹¹)(10 kg * 10 kg) / (2 m)² = 0.25 N.
Correct Answer:
A
— 0.25 N
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Q. What is the gravitational force between two 10 kg masses separated by a distance of 2 meters?
A.
25 N
B.
50 N
C.
100 N
D.
20 N
Show solution
Solution
Using Newton's law of universal gravitation, F = G(m1*m2)/r², where G = 6.674 × 10⁻¹¹ N(m/kg)², F = (6.674 × 10⁻¹¹)(10)(10)/(2²) = 50 N.
Correct Answer:
B
— 50 N
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Q. What is the gravitational force between two 5 kg masses separated by a distance of 2 m?
A.
6.25 N
B.
12.5 N
C.
9.8 N
D.
0.5 N
Show solution
Solution
Using Newton's law of universal gravitation, F = G(m1*m2)/r², where G = 6.674×10⁻¹¹ N(m/kg)².
Correct Answer:
A
— 6.25 N
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Q. What is the gravitational force between two masses?
A.
F = G(m1m2)/r^2
B.
F = G(m1 + m2)/r^2
C.
F = G(m1 - m2)/r^2
D.
F = G(m1m2)r^2
Show solution
Solution
The gravitational force between two masses is given by Newton's law of gravitation: F = G(m1m2)/r^2.
Correct Answer:
A
— F = G(m1m2)/r^2
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Q. What is the gravitational force between two particles of masses m1 and m2 separated by a distance r?
A.
G * (m1 * m2) / r^2
B.
G * (m1 + m2) / r^2
C.
G * (m1 - m2) / r^2
D.
G * (m1 * m2) * r^2
Show solution
Solution
The gravitational force between two masses is given by Newton's law of gravitation, F = G * (m1 * m2) / r^2.
Correct Answer:
A
— G * (m1 * m2) / r^2
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Q. What is the gravitational potential energy of a 1 kg mass at a height of 10 m?
A.
10 J
B.
20 J
C.
30 J
D.
40 J
Show solution
Solution
Using the formula PE = m * g * h, where g = 10 m/s^2, PE = 1 kg * 10 m/s^2 * 10 m = 100 J.
Correct Answer:
A
— 10 J
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Q. What is the gravitational potential energy of an object at height h?
A.
PE = mgh
B.
PE = 1/2 mv^2
C.
PE = Fd
D.
PE = mv
Show solution
Solution
The gravitational potential energy of an object at height h is given by PE = mgh, where m is mass, g is the acceleration due to gravity, and h is height.
Correct Answer:
A
— PE = mgh
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Q. What is the kinetic energy of a 2 kg object moving at a speed of 3 m/s?
A.
9 J
B.
6 J
C.
12 J
D.
3 J
Show solution
Solution
Kinetic energy KE = 0.5mv² = 0.5 × 2 kg × (3 m/s)² = 9 J.
Correct Answer:
A
— 9 J
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Q. What is the kinetic energy of a 3 kg object moving at a speed of 5 m/s?
A.
37.5 J
B.
15 J
C.
7.5 J
D.
25 J
Show solution
Solution
Kinetic energy KE = 0.5mv² = 0.5 × 3 kg × (5 m/s)² = 37.5 J.
Correct Answer:
A
— 37.5 J
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Q. What is the kinetic energy of a 4 kg object moving at 3 m/s?
A.
6 J
B.
12 J
C.
18 J
D.
24 J
Show solution
Solution
Kinetic energy KE = 0.5 * m * v² = 0.5 * 4 kg * (3 m/s)² = 18 J.
Correct Answer:
B
— 12 J
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Q. What is the kinetic energy of a 4 kg object moving at a speed of 2 m/s?
A.
8 J
B.
4 J
C.
16 J
D.
2 J
Show solution
Solution
Kinetic energy is calculated as KE = 0.5 × m × v², so KE = 0.5 × 4 kg × (2 m/s)² = 8 J.
Correct Answer:
A
— 8 J
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Q. What is the kinetic energy of a 5 kg object moving at a speed of 4 m/s?
A.
10 J
B.
20 J
C.
40 J
D.
80 J
Show solution
Solution
Kinetic Energy = 0.5 × m × v² = 0.5 × 5 kg × (4 m/s)² = 40 J.
Correct Answer:
B
— 20 J
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Q. What is the kinetic energy of a rotating rigid body?
A.
KE = 1/2 Iω^2
B.
KE = Iω
C.
KE = 1/2 mv^2
D.
KE = mvω
Show solution
Solution
The kinetic energy of a rotating rigid body is given by KE = 1/2 Iω^2, where I is the moment of inertia and ω is the angular velocity.
Correct Answer:
A
— KE = 1/2 Iω^2
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Q. What is the kinetic energy of an object with a mass of 2 kg moving at a speed of 3 m/s?
A.
9 J
B.
6 J
C.
3 J
D.
0 J
Show solution
Solution
Kinetic energy is calculated as KE = 0.5 * m * v². Here, KE = 0.5 * 2 kg * (3 m/s)² = 9 J.
Correct Answer:
A
— 9 J
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Q. What is the kinetic energy of an object with a mass of 2 kg moving at a velocity of 3 m/s?
A.
3 J
B.
6 J
C.
9 J
D.
12 J
Show solution
Solution
Kinetic energy is calculated using the formula KE = 1/2 mv². Here, KE = 1/2 * 2 kg * (3 m/s)² = 9 J.
Correct Answer:
C
— 9 J
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Q. What is the kinetic energy of an object with a mass of 3 kg moving at a speed of 4 m/s?
A.
12 J
B.
24 J
C.
6 J
D.
48 J
Show solution
Solution
Kinetic energy is calculated using KE = 1/2 mv². Here, KE = 1/2 * 3 kg * (4 m/s)² = 24 J.
Correct Answer:
B
— 24 J
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Q. What is the moment of inertia for a solid cylinder about its central axis?
A.
1/2 m r^2
B.
m r^2
C.
1/3 m r^2
D.
m r
Show solution
Solution
The moment of inertia for a solid cylinder about its central axis is given by I = 1/2 m r^2.
Correct Answer:
A
— 1/2 m r^2
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Q. What is the moment of inertia for a solid cylinder rotating about its central axis?
A.
1/2 m r²
B.
m r²
C.
2/5 m r²
D.
1/3 m r²
Show solution
Solution
The moment of inertia for a solid cylinder rotating about its central axis is given by I = 1/2 m r², where m is mass and r is radius.
Correct Answer:
A
— 1/2 m r²
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Q. What is the moment of inertia of a solid cylinder about its central axis?
A.
1/2 m r^2
B.
1/3 m r^2
C.
m r^2
D.
m r^2 / 2
Show solution
Solution
The moment of inertia of a solid cylinder about its central axis is given by I = 1/2 m r^2.
Correct Answer:
A
— 1/2 m r^2
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Q. What is the momentum of a 10 kg object moving at 3 m/s?
A.
30 kg·m/s
B.
10 kg·m/s
C.
3 kg·m/s
D.
0 kg·m/s
Show solution
Solution
Momentum p = mv = 10 kg * 3 m/s = 30 kg·m/s.
Correct Answer:
A
— 30 kg·m/s
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Q. What is the momentum of a 2 kg object moving at a velocity of 3 m/s?
A.
6 kg·m/s
B.
5 kg·m/s
C.
3 kg·m/s
D.
2 kg·m/s
Show solution
Solution
Momentum is calculated as p = m × v, so p = 2 kg × 3 m/s = 6 kg·m/s.
Correct Answer:
A
— 6 kg·m/s
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