Total balls = 4 + 6 = 10. Probability of black ball = 6/10 = 3/5.

Total balls = 4 + 6 = 10. Probability of black ball = 6/10 = 3/5.

Total balls = 5 + 3 = 8. Probability of black ball = 3/8.

Total balls = 5 + 3 = 8. Probability of black ball = 3/8.

Capacitance (C) is given by C = Q/V. Here, C = 5μC / 10V = 0.5μF.

When the plates of a disconnected capacitor are moved apart, the capacitance decreases, leading to an increase in potential difference.

Capacitance C is given by C = Q/V. Here, C = 24μC / 12V = 2μF.

The capacitance C is defined as C = Q/V.

Charge (Q) = Capacitance (C) × Voltage (V) = 4 µF × 12 V = 48 µC.

Capacitance (C) = Charge (Q) / Voltage (V) = 6 µC / 12 V = 0.5 µF.

When the distance is doubled, the potential difference across the capacitor also doubles, resulting in 24V.

Once disconnected, the charge remains constant. Doubling the area increases capacitance but does not change the potential difference since the charge is fixed.

When the distance between the plates is doubled, the capacitance decreases, which causes the voltage to double since Q remains constant.

Capacitive reactance XC = 1/(2πfC) = 1/(2π*50*10e-6) ≈ 318.3Ω.

Capacitive reactance Xc = 1/(ωC) where ω = 2πf. Calculate Xc.

If the charge is removed, the potential difference across the capacitor becomes 0 volts.

The charge Q stored in a capacitor is given by Q = CV.

The capacitive reactance is given by XC = 1/(2πfC).

Using the equation of motion: s = ut + (1/2)at². Here, u = 0, a = 2 m/s², t = 5 s. So, s = 0 + (1/2)(2)(5²) = 25 m.

Using the formula v = u + at, where u = 0, a = 2 m/s², and t = 5 s, we get v = 0 + 2 * 5 = 10 m/s.

Acceleration is calculated using the formula a = (final velocity - initial velocity) / time. Here, a = (20 m/s - 0 m/s) / 5 s = 4 m/s².

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200000 J.

Work Done = Change in Kinetic Energy = 1/2 * m * (v^2 - u^2) = 1/2 * 1000 kg * (20 m/s)^2 = 200,000 J

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200,000 J.

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200000 J.

Acceleration (a) = (final velocity - initial velocity) / time = (30 m/s - 0) / 10 s = 3 m/s².

Average Force = Work done / Distance = 5000 J / 100 m = 50 N

Using the formula: acceleration = (final velocity - initial velocity) / time. Acceleration = (0 - 15) / 5 = -3 m/s².

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, acceleration = (0 - 30) / 6 = -5 m/s². Distance = 30 * 6 + 0.5 * (-5) * 6^2 = 180 - 90 = 90 m.

Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (20 m/s)² = 200,000 J.