Arithmetic Aptitude for Competitive Exam Success

Arithmetic Aptitude

Approximation & Simplification Banking Awareness Cloze Test Data Interpretation - Caselets Data Sufficiency - Banking Type Error Detection - Grammar Financial Markets Basics Mixtures and Alligations Mixtures and Alligations - Common Mistakes Mixtures and Alligations - Practice Problems with Solutions Mixtures and Alligations - Shortcuts and Tricks Number Series Para Jumbles Problems on Trains and Boats Problems on Trains and Boats - Common Mistakes Problems on Trains and Boats - Practice Problems with Solutions Problems on Trains and Boats - Shortcuts and Tricks Profit and Loss Problems Profit and Loss Problems - Common Mistakes Profit and Loss Problems - Practice Problems with Solutions Profit and Loss Problems - Shortcuts and Tricks Quadratic Equations for Banking Ratio, Proportion and Partnership Ratio, Proportion and Partnership - Common Mistakes Ratio, Proportion and Partnership - Practice Problems with Solutions Ratio, Proportion and Partnership - Shortcuts and Tricks Reading Comprehension - Banking Level Sentence Improvement Simple and Compound Interest Simple and Compound Interest - Common Mistakes Simple and Compound Interest - Practice Problems with Solutions Simple and Compound Interest - Shortcuts and Tricks Time and Work Problems Time and Work Problems - Common Mistakes Time and Work Problems - Practice Problems with Solutions Time and Work Problems - Shortcuts and Tricks Time, Speed and Distance Time, Speed and Distance - Common Mistakes Time, Speed and Distance - Practice Problems with Solutions Time, Speed and Distance - Shortcuts and Tricks

Q. If a person invests $5000 at a compound interest rate of 8% per annum, what will be the total amount after 3 years?

A. $5920
B. $6000
C. $5934
D. $5800

Solution

Amount = 5000 * (1 + 0.08)^3 = 5000 * 1.259712 = $6298.56.

Correct Answer: C — $5934

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Q. If a person mixes two types of tea costing $20 and $30 per kg in the ratio 2:3, what is the cost price per kg of the mixture?

A. $24
B. $26
C. $28
D. $22

Solution

Cost = (2*20 + 3*30) / (2 + 3) = (40 + 90) / 5 = 130 / 5 = $26.

Correct Answer: B — $26

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Q. If a person sells an article for $1200 at a profit of 20%, what was the cost price?

A. $1000
B. $1100
C. $900
D. $1200

Solution

Cost Price = Selling Price / (1 + Profit%) = 1200 / 1.2 = $1000

Correct Answer: A — $1000

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Q. If a person spends 30% of his salary on rent and 20% on food, what percentage of his salary is left?

A. 50%
B. 40%
C. 30%
D. 60%

Solution

Total expenditure = 30% + 20% = 50%. Salary left = 100% - 50% = 50%.

Correct Answer: A — 50%

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Q. If a person walks 5 km in 1 hour, how far will he walk in 3 hours at the same speed?

A. 10 km
B. 12 km
C. 15 km
D. 18 km

Solution

Distance = Speed x Time = 5 km/h x 3 h = 15 km.

Correct Answer: C — 15 km

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Q. If a person walks 5 km in 1 hour, how long will it take to walk 20 km?

A. 3 hours
B. 4 hours
C. 5 hours
D. 6 hours

Solution

Time = Distance / Speed = 20 km / (5 km/h) = 4 hours

Correct Answer: C — 5 hours

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Q. If a person walks at a speed of 4 km/h, how far can he walk in 3 hours?

A. 10 km
B. 12 km
C. 14 km
D. 15 km

Solution

Distance = Speed × Time = 4 km/h × 3 h = 12 km.

Correct Answer: B — 12 km

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Q. If a person walks at a speed of 5 km/h, how long will it take to walk 15 km?

A. 2 hours
B. 3 hours
C. 4 hours
D. 5 hours

Solution

Time = Distance / Speed = 15 km / 5 km/h = 3 hours.

Correct Answer: B — 3 hours

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Q. If a person works 8 hours a day and completes a task in 5 days, what is the total work done in hours?

A. 30 hours
B. 35 hours
C. 40 hours
D. 45 hours

Solution

Total Work = Hours per Day * Days = 8 * 5 = 40 hours

Correct Answer: C — 40 hours

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Q. If a polynomial f(x) = x^2 - 4, what are its roots?

A. -2, 2
B. 0, 4
C. 1, -1
D. 2, 2

Solution

Setting f(x) = 0 gives x^2 - 4 = 0, so x = ±2.

Correct Answer: A — -2, 2

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Q. If a polynomial f(x) = x^2 - 4x + 4, what is f(2)?

A. 0
B. 1
C. 2
D. 4

Solution

f(2) = 2^2 - 4*2 + 4 = 0.

Correct Answer: A — 0

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Q. If a polynomial f(x) = x^2 - 5x + 6, what are its roots?

A. 1 and 6
B. 2 and 3
C. 3 and 2
D. 5 and 1

Solution

Factoring gives (x-2)(x-3) = 0, so roots are 2 and 3.

Correct Answer: B — 2 and 3

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Q. If a product is bought for $80 and sold for $100, what is the profit?

A. $20
B. $15
C. $25
D. $30

Solution

Profit = Selling Price - Cost Price = 100 - 80 = $20.

Correct Answer: A — $20

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Q. If a product is marked at $150 and sold at a discount of 20%, what is the selling price?

A. $120
B. $130
C. $140
D. $110

Solution

Discount = 20% of 150 = 0.20 * 150 = $30. Selling Price = Marked Price - Discount = 150 - 30 = $120.

Correct Answer: A — $120

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Q. If a product is marked at $250 and sold at a discount of 20%, what is the selling price?

A. $200
B. $210
C. $220
D. $230

Solution

Selling Price = Marked Price - Discount = 250 - (20/100 * 250) = 250 - 50 = $200.

Correct Answer: A — $200

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Q. If a product is marked at $500 and sold at a discount of 10%, what is the selling price?

A. $450
B. $400
C. $475
D. $425

Solution

Selling Price = Marked Price - Discount = 500 - (10% of 500) = 500 - 50 = $450.

Correct Answer: C — $475

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Q. If a product is sold for $120 after a profit of 20%, what was the cost price of the product?

A. $80
B. $90
C. $100
D. $110

Solution

Let Cost Price = x. Then, 120 = x + 0.2x => 120 = 1.2x => x = 120/1.2 = $100.

Correct Answer: A — $80

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Q. If a product is sold for $150 after a loss of 10%, what was the cost price?

A. $135
B. $140
C. $145
D. $150

Solution

Let Cost Price = x. Selling Price = x - 10% of x = 0.9x. 0.9x = 150. x = 150/0.9 = 166.67.

Correct Answer: A — $135

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Q. If a product is sold for $240 after a discount of 20%, what was the marked price?

A. $300
B. $280
C. $250
D. $320

Solution

Let Marked Price = x. Selling Price = x - 20% of x = 0.8x. 0.8x = 240. x = 240/0.8 = 300.

Correct Answer: A — $300

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Q. If a product is sold for $80 after a discount of 20%, what was the original price?

A. $90
B. $100
C. $110
D. $120

Solution

Let the original price be x. Then, x - 0.2x = 80, 0.8x = 80, x = 100.

Correct Answer: B — $100

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Q. If a runner completes a 10 km race in 50 minutes, what is his speed in km/h?

A. 10 km/h
B. 12 km/h
C. 14 km/h
D. 15 km/h

Solution

Speed = Distance / Time = 10 km / (50/60) h = 12 km/h.

Correct Answer: B — 12 km/h

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Q. If a sequence is defined as a_n = 2n + 1, what is a_5?

A. 9
B. 10
C. 11
D. 12

Solution

a_5 = 2(5) + 1 = 10 + 1 = 11.

Correct Answer: A — 9

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Q. If a sequence is defined as a_n = 3n + 1, what is a_4?

A. 10
B. 11
C. 12
D. 13

Solution

a_4 = 3(4) + 1 = 12 + 1 = 13.

Correct Answer: B — 11

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Q. If a sequence is defined as a_n = 3n + 2, what is a_4?

A. 10
B. 14
C. 12
D. 8

Solution

a_4 = 3(4) + 2 = 12 + 2 = 14.

Correct Answer: B — 14

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Q. If a sequence is defined by a_n = 2n + 1, what is a_4?

A. 7
B. 8
C. 9
D. 10

Solution

a_4 = 2(4) + 1 = 8 + 1 = 9.

Correct Answer: A — 7

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Q. If a sequence is defined by a_n = 3n + 1, what is a_4?

A. 10
B. 11
C. 12
D. 13

Solution

Substituting n = 4 gives a_4 = 3(4) + 1 = 12 + 1 = 13.

Correct Answer: B — 11

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Q. If a sequence is defined by a_n = 3n + 1, what is a_5?

A. 14
B. 15
C. 16
D. 17

Solution

a_5 = 3(5) + 1 = 15 + 1 = 16.

Correct Answer: A — 14

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Q. If a sequence starts with 2 and each term is multiplied by 3, what is the 4th term?

A. 18
B. 54
C. 162
D. 486

Solution

The sequence is 2, 6, 18, 54; the 4th term is 54.

Correct Answer: C — 162

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Q. If a shirt costs $40 and is sold for $50, what is the profit percentage?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Profit = Selling Price - Cost Price = 50 - 40 = 10. Profit Percentage = (10/40) * 100 = 25%.

Correct Answer: B — 25%

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Q. If a stock price increases from $40 to $50, what is the percentage increase?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

Percentage Increase = ((New Price - Old Price) / Old Price) * 100 = ((50 - 40) / 40) * 100 = 25%

Correct Answer: B — 25%

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Arithmetic Aptitude

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