Q. If an object is in free fall, what is the acceleration due to gravity near the Earth's surface?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
8.9 m/s²
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Solution
The acceleration due to gravity near the Earth's surface is approximately 9.81 m/s².
Correct Answer:
C
— 9.81 m/s²
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Q. If an object is in free fall, what is the net force acting on it?
A.
0 N
B.
Its weight
C.
The normal force
D.
Air resistance
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Solution
In free fall, the only force acting on the object is its weight, which is the net force.
Correct Answer:
B
— Its weight
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Q. If an object is moving in a circular path with a constant speed, what type of acceleration does it experience?
A.
Centripetal acceleration
B.
Linear acceleration
C.
No acceleration
D.
Tangential acceleration
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Solution
An object moving in a circular path experiences centripetal acceleration directed towards the center of the circle.
Correct Answer:
A
— Centripetal acceleration
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Q. If light travels from air (n=1) into water (n=1.33), what happens to its speed?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It doubles
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Solution
The speed of light decreases when it enters a medium with a higher refractive index.
Correct Answer:
B
— It decreases
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Q. If the capacitance in an RC circuit is doubled, what happens to the time constant?
A.
It remains the same.
B.
It doubles.
C.
It halves.
D.
It quadruples.
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Solution
Doubling the capacitance in an RC circuit will double the time constant τ = R * C.
Correct Answer:
B
— It doubles.
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Q. If the capacitance of a capacitor is 3 µF and it is charged to 6 V, what is the charge on the capacitor?
A.
18 µC
B.
12 µC
C.
6 µC
D.
9 µC
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Solution
Charge (Q) is given by Q = C * V. Here, Q = 3 µF * 6 V = 18 µC.
Correct Answer:
A
— 18 µC
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Q. If the capacitance of a capacitor is doubled while the voltage remains constant, what happens to the charge stored?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Charge (Q) stored in a capacitor is given by Q = C * V. If C is doubled and V remains constant, Q also doubles.
Correct Answer:
A
— It doubles
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Q. If the capacitance of a capacitor is doubled, what happens to the charge stored if the voltage remains constant?
A.
Charge is halved
B.
Charge remains the same
C.
Charge is doubled
D.
Charge is quadrupled
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Solution
Capacitance (C) is defined as C = Q/V. If C is doubled and V remains constant, Q must also double.
Correct Answer:
C
— Charge is doubled
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Q. If the distance between two point charges is doubled, how does the force between them change according to Coulomb's law?
A.
It doubles
B.
It quadruples
C.
It halves
D.
It becomes one-fourth
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Solution
According to Coulomb's law, the force F between two point charges is inversely proportional to the square of the distance r between them. If the distance is doubled, the force becomes F/4.
Correct Answer:
D
— It becomes one-fourth
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Q. If the electric field between two parallel plates is 2000 N/C, what is the potential difference between the plates if they are 0.05 m apart?
A.
100 V
B.
200 V
C.
300 V
D.
400 V
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Solution
Potential difference V = E * d = 2000 N/C * 0.05 m = 100 V.
Correct Answer:
B
— 200 V
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Q. If the electric potential at a point is 100 V and the charge at that point is 2 µC, what is the electric potential energy?
A.
0.2 J
B.
0.1 J
C.
0.05 J
D.
0.4 J
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Solution
Potential energy U = V * q = 100 V * 2 x 10^-6 C = 0.0002 J = 0.2 J.
Correct Answer:
A
— 0.2 J
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Q. If the entropy of a system increases, what can be inferred about the system?
A.
It is losing energy
B.
It is becoming more ordered
C.
It is becoming more disordered
D.
It is in thermal equilibrium
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Solution
An increase in entropy indicates that the system is becoming more disordered.
Correct Answer:
C
— It is becoming more disordered
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Q. If the magnetic field strength is doubled, what happens to the induced emf in a loop moving through the field?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
If the magnetic field strength is doubled, the induced emf also doubles, as it is directly proportional to the magnetic field strength.
Correct Answer:
A
— It doubles
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Q. If the magnetic field through a loop of wire is increasing, what is the direction of the induced current?
A.
Clockwise
B.
Counterclockwise
C.
No current induced
D.
Depends on the field strength
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Solution
According to Lenz's law, the induced current will flow in a direction that opposes the change in magnetic flux. If the magnetic field is increasing, the induced current will be counterclockwise.
Correct Answer:
B
— Counterclockwise
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Q. If the mass of a simple harmonic oscillator is tripled, how does the frequency change?
A.
It triples
B.
It is halved
C.
It is reduced to one-third
D.
It remains the same
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Solution
The frequency f is inversely proportional to the square root of the mass m, so if m is tripled, the frequency is reduced to one-third.
Correct Answer:
C
— It is reduced to one-third
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Q. If the potential difference across a capacitor is 12 V and its capacitance is 3 µF, what is the charge stored in the capacitor?
A.
36 µC
B.
24 µC
C.
12 µC
D.
18 µC
Show solution
Solution
Q = C * V = 3 x 10^-6 F * 12 V = 36 µC.
Correct Answer:
A
— 36 µC
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Q. If the potential difference across a capacitor is doubled, what happens to the stored energy?
A.
It doubles
B.
It quadruples
C.
It remains the same
D.
It halves
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Solution
Energy stored in a capacitor is given by U = 1/2 C V^2. If V is doubled, U becomes 1/2 C (2V)^2 = 2CV^2, which is quadrupled.
Correct Answer:
B
— It quadruples
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Q. If the radius of a circular path is doubled, how does the centripetal force change for a constant mass and velocity?
A.
It doubles.
B.
It halves.
C.
It remains the same.
D.
It quadruples.
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Solution
Centripetal force is given by F = mv^2/r. If r is doubled, the force is halved, assuming mass and velocity remain constant.
Correct Answer:
B
— It halves.
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Q. If the radius of a circular path is doubled, how does the centripetal force change for a constant speed?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Centripetal force F = mv²/r; if r is doubled, F is halved for constant speed.
Correct Answer:
B
— It halves
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Q. If the spring constant of a spring is doubled, how does the period of the simple harmonic motion change?
A.
It doubles
B.
It is halved
C.
It remains the same
D.
It quadruples
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Solution
The period T is inversely proportional to the square root of the spring constant k. If k is doubled, the period is halved.
Correct Answer:
B
— It is halved
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Q. If the temperature of a gas increases, what happens to its volume at constant pressure?
A.
It decreases
B.
It remains the same
C.
It increases
D.
It becomes zero
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Solution
According to Charles's Law, if the temperature of a gas increases at constant pressure, its volume increases.
Correct Answer:
C
— It increases
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Q. If the temperature of a gas increases, what happens to its volume if the pressure remains constant?
A.
It decreases
B.
It remains the same
C.
It increases
D.
It becomes zero
Show solution
Solution
According to Charles's Law, if the pressure is constant, the volume of a gas increases as its temperature increases.
Correct Answer:
C
— It increases
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Q. If the voltage across a resistor is doubled while the resistance remains constant, what happens to the current?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
According to Ohm's Law, if voltage is doubled and resistance is constant, current will also double.
Correct Answer:
A
— It doubles
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Q. If the volume of a gas is halved at constant temperature, what happens to the pressure?
A.
It remains the same
B.
It halves
C.
It doubles
D.
It quadruples
Show solution
Solution
According to Boyle's law, pressure is inversely proportional to volume at constant temperature. If the volume is halved, the pressure doubles.
Correct Answer:
C
— It doubles
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Q. If two capacitors are connected in series, how is the total capacitance (C_total) calculated?
A.
1/C_total = 1/C1 + 1/C2
B.
C_total = C1 + C2
C.
C_total = C1 * C2
D.
C_total = C1 - C2
Show solution
Solution
For capacitors in series, the total capacitance is given by 1/C_total = 1/C1 + 1/C2.
Correct Answer:
A
— 1/C_total = 1/C1 + 1/C2
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Q. If two capacitors of 4 µF and 6 µF are connected in parallel, what is the total capacitance?
A.
10 µF
B.
24 µF
C.
2.4 µF
D.
12 µF
Show solution
Solution
C_eq = C1 + C2 = 4 µF + 6 µF = 10 µF.
Correct Answer:
A
— 10 µF
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Q. If two capacitors of 4 µF and 6 µF are connected in series, what is the total capacitance?
A.
2.4 µF
B.
10 µF
C.
1.5 µF
D.
24 µF
Show solution
Solution
1/C_total = 1/C1 + 1/C2 = 1/4 + 1/6 = 5/12, thus C_total = 12/5 = 2.4 µF.
Correct Answer:
A
— 2.4 µF
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Q. If two capacitors of capacitance C1 and C2 are connected in series, what is the equivalent capacitance (Ceq)?
A.
Ceq = C1 + C2
B.
Ceq = 1 / (1/C1 + 1/C2)
C.
Ceq = C1 * C2
D.
Ceq = (C1 * C2) / (C1 + C2)
Show solution
Solution
The equivalent capacitance for capacitors in series is given by Ceq = 1 / (1/C1 + 1/C2).
Correct Answer:
B
— Ceq = 1 / (1/C1 + 1/C2)
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Q. If two charges of +3 µC and -3 µC are placed 0.2 m apart, what is the magnitude of the force between them?
A.
67.5 N
B.
45 N
C.
30 N
D.
15 N
Show solution
Solution
Using Coulomb's law, F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * |3 x 10^-6 C * -3 x 10^-6 C| / (0.2 m)^2 = 45 N.
Correct Answer:
B
— 45 N
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Q. If two particles of masses m1 and m2 are moving towards each other with velocities v1 and v2, what is the total momentum of the system before they collide?
A.
m1 * v1 + m2 * v2
B.
m1 * v1 - m2 * v2
C.
m1 * v1 + m2 * v2 + m1 * m2
D.
0
Show solution
Solution
The total momentum of the system before the collision is the vector sum of the momenta of the two particles, which is m1 * v1 + m2 * v2.
Correct Answer:
A
— m1 * v1 + m2 * v2
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