Mathematics (School) MCQ & Objective Questions
Mathematics is a crucial subject in school education, forming the foundation for various competitive exams. Mastering Mathematics (School) not only enhances problem-solving skills but also boosts confidence during exams. Practicing MCQs and objective questions is essential for effective exam preparation, as it helps students identify important questions and understand concepts clearly.
What You Will Practise Here
Number Systems and their properties
Algebraic Expressions and Equations
Geometry: Angles, Triangles, and Circles
Statistics and Probability concepts
Mensuration: Area, Volume, and Surface Area
Trigonometry basics and applications
Functions and Graphs
Exam Relevance
Mathematics (School) is a significant part of the curriculum for CBSE and State Boards, as well as competitive exams like NEET and JEE. Students can expect a variety of question patterns, including direct application of formulas, conceptual understanding, and problem-solving scenarios. Familiarity with MCQs in this subject can greatly enhance performance in both board and competitive examinations.
Common Mistakes Students Make
Misinterpreting the question, leading to incorrect answers.
Overlooking the importance of units in measurement-related problems.
Confusing similar formulas, especially in Geometry and Algebra.
Neglecting to check calculations, resulting in simple arithmetic errors.
Failing to understand the underlying concepts, which affects problem-solving ability.
FAQs
Question: How can I improve my speed in solving Mathematics (School) MCQs?Answer: Regular practice with timed quizzes and mock tests can significantly enhance your speed and accuracy.
Question: Are there any specific topics I should focus on for competitive exams?Answer: Focus on Algebra, Geometry, and Statistics, as these areas frequently appear in competitive exams.
Start your journey towards mastering Mathematics (School) today! Solve practice MCQs to test your understanding and prepare effectively for your exams. Remember, consistent practice leads to success!
Q. What is the area of a parallelogram with a base of 6 m and a height of 4 m?
A.
24 m²
B.
20 m²
C.
30 m²
D.
18 m²
Show solution
Solution
Area = base * height = 6 * 4 = 24 m².
Correct Answer:
A
— 24 m²
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Q. What is the area of a parallelogram with a base of 8 cm and a height of 3 cm?
A.
24 cm²
B.
30 cm²
C.
20 cm²
D.
18 cm²
Show solution
Solution
Area = base × height = 8 cm × 3 cm = 24 cm².
Correct Answer:
A
— 24 cm²
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Q. What is the area of a parallelogram with base 10 and height 5?
Show solution
Solution
The area of a parallelogram is calculated as base times height. Thus, area = 10 * 5 = 50.
Correct Answer:
C
— 50
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Q. What is the area of a polygon with vertices at (0, 0), (4, 0), (4, 3), (0, 3)?
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Solution
This is a rectangle with length 4 and width 3. Area = length * width = 4 * 3 = 12.
Correct Answer:
B
— 8
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Q. What is the area of a polygon with vertices at (1, 1), (4, 1), (4, 5), (1, 5)?
Show solution
Solution
The area of the polygon is length × width = (4 - 1) × (5 - 1) = 3 × 4 = 12.
Correct Answer:
C
— 16
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Q. What is the area of a rectangle with a length of 12 units and a width of 4 units?
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Solution
The area A of a rectangle is given by A = length * width. Here, A = 12 * 4 = 48.
Correct Answer:
A
— 48
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Q. What is the area of a rectangle with a length of 5 cm and a width of 3 cm?
A.
8 cm²
B.
15 cm²
C.
18 cm²
D.
20 cm²
Show solution
Solution
Area = length × width = 5 cm × 3 cm = 15 cm².
Correct Answer:
B
— 15 cm²
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Q. What is the area of a rectangle with a length of 5 units and a width of 3 units?
Show solution
Solution
The area of a rectangle is calculated using the formula A = length × width. Here, A = 5 × 3 = 15.
Correct Answer:
B
— 15
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Q. What is the area of a rectangle with a length of 8 cm and a width of 3 cm?
A.
24 cm²
B.
30 cm²
C.
20 cm²
D.
18 cm²
Show solution
Solution
Area = length * width = 8 cm * 3 cm = 24 cm².
Correct Answer:
A
— 24 cm²
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Q. What is the area of a rectangle with a length of 8 units and a width of 5 units?
A.
40 square units
B.
30 square units
C.
50 square units
D.
20 square units
Show solution
Solution
The area of a rectangle is given by A = length × width. Here, A = 8 × 5 = 40 square units.
Correct Answer:
A
— 40 square units
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Q. What is the area of a rectangle with length 10 units and width 4 units?
Show solution
Solution
The area of a rectangle is calculated as Area = length * width. Here, Area = 10 * 4 = 40.
Correct Answer:
A
— 40
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Q. What is the area of a rectangle with length 10 units and width 5 units?
Show solution
Solution
The area of a rectangle is calculated as Area = length * width. Here, Area = 10 * 5 = 50.
Correct Answer:
A
— 50
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Q. What is the area of a rectangle with length 5 cm and width 3 cm?
A.
15 cm²
B.
8 cm²
C.
10 cm²
D.
12 cm²
Show solution
Solution
Area = length × width = 5 cm × 3 cm = 15 cm².
Correct Answer:
A
— 15 cm²
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Q. What is the area of a rectangle with length 8 cm and width 5 cm?
A.
40 cm²
B.
30 cm²
C.
50 cm²
D.
20 cm²
Show solution
Solution
Area = length × width = 8 cm × 5 cm = 40 cm².
Correct Answer:
A
— 40 cm²
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Q. What is the area of a rectangle with length 8 units and width 3 units?
Show solution
Solution
The area of a rectangle is given by the formula Area = length * width. Here, Area = 8 * 3 = 24.
Correct Answer:
A
— 24
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Q. What is the area of a rectangle with vertices at (1, 1), (1, 4), (5, 1), and (5, 4)?
Show solution
Solution
Length = 5 - 1 = 4, Width = 4 - 1 = 3. Area = length * width = 4 * 3 = 12.
Correct Answer:
A
— 12
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Q. What is the area of a rectangle with vertices at (1, 2), (1, 5), (4, 2), and (4, 5)?
Show solution
Solution
The length is 4 - 1 = 3 and the width is 5 - 2 = 3. Area = length * width = 3 * 3 = 9.
Correct Answer:
C
— 12
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Q. What is the area of a rectangle with vertices at (1, 2), (1, 5), (4, 5), and (4, 2)?
Show solution
Solution
The area of a rectangle is calculated as length times width. The length is 4 - 1 = 3 and the width is 5 - 2 = 3. Therefore, area = 3 * 3 = 9.
Correct Answer:
C
— 12
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Q. What is the area of a regular hexagon with a side length of 4 cm?
A.
32√3 cm²
B.
24 cm²
C.
48 cm²
D.
16√3 cm²
Show solution
Solution
Area = (3√3/2) * side² = (3√3/2) * 4² = 24√3 cm².
Correct Answer:
A
— 32√3 cm²
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Q. What is the area of a regular hexagon with a side length of 4?
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Solution
The area of a regular hexagon can be calculated using the formula A = (3√3/2) * side^2. Thus, A = (3√3/2) * 4^2 = 48.
Correct Answer:
B
— 48
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Q. What is the area of a rhombus with diagonals of 8 cm and 6 cm?
A.
24 cm²
B.
30 cm²
C.
36 cm²
D.
48 cm²
Show solution
Solution
Area = (d1 × d2) / 2 = (8 cm × 6 cm) / 2 = 24 cm².
Correct Answer:
A
— 24 cm²
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Q. What is the area of a rhombus with diagonals of lengths 10 and 6?
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Solution
Area = (d1 * d2) / 2 = (10 * 6) / 2 = 30.
Correct Answer:
A
— 30
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Q. What is the area of a rhombus with diagonals of lengths 8 and 6?
Show solution
Solution
Area = (d1 * d2) / 2 = (8 * 6) / 2 = 24.
Correct Answer:
A
— 24
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Q. What is the area of a sector of a circle with a radius of 10 cm and a central angle of 60 degrees?
A.
50π/3 cm²
B.
100π/3 cm²
C.
25π cm²
D.
20π cm²
Show solution
Solution
Area of sector = (θ/360) * πr²; = (60/360) * π(10)² = (1/6) * 100π = 50π/3 cm².
Correct Answer:
A
— 50π/3 cm²
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Q. What is the area of a sector of a circle with a radius of 10 cm and a central angle of 90 degrees?
A.
25π cm²
B.
50π cm²
C.
75π cm²
D.
100π cm²
Show solution
Solution
Area of sector = (θ/360) * πr² = (90/360) * π(10)² = (1/4) * 100π = 25π cm².
Correct Answer:
A
— 25π cm²
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Q. What is the area of a sector of a circle with a radius of 4 cm and a central angle of 60 degrees?
A.
8π/3 cm²
B.
4π/3 cm²
C.
2π cm²
D.
16π/3 cm²
Show solution
Solution
Area of sector = (θ/360) * πr² = (60/360) * π(4)² = (1/6) * 16π = 8π/3 cm².
Correct Answer:
A
— 8π/3 cm²
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Q. What is the area of a sector of a circle with a radius of 5 cm and a central angle of 120 degrees?
A.
25π/3 cm²
B.
10π cm²
C.
15π/2 cm²
D.
20π/3 cm²
Show solution
Solution
Area of sector = (θ/360) * πr² = (120/360) * π(5)² = (1/3) * 25π = 25π/3 cm².
Correct Answer:
A
— 25π/3 cm²
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Q. What is the area of a sector of a circle with a radius of 5 cm and a central angle of 90 degrees?
A.
6.25 cm²
B.
12.25 cm²
C.
19.63 cm²
D.
25.00 cm²
Show solution
Solution
Area of sector = (θ/360) * πr² = (90/360) * π(5)² = (1/4) * 25π ≈ 6.25 cm².
Correct Answer:
A
— 6.25 cm²
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Q. What is the area of a sector of a circle with a radius of 6 cm and a central angle of 90°?
A.
9π cm²
B.
12π cm²
C.
18π cm²
D.
36π cm²
Show solution
Solution
Area of sector = (θ/360) * πr² = (90/360) * π(6)² = (1/4) * 36π = 9π cm².
Correct Answer:
A
— 9π cm²
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Q. What is the area of a sector of a circle with a radius of 6 cm and a central angle of 60 degrees?
A.
6π cm²
B.
12π cm²
C.
3π cm²
D.
9π cm²
Show solution
Solution
Area of sector = (θ/360) * πr² = (60/360) * π(6)² = 12π cm².
Correct Answer:
B
— 12π cm²
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