General Aptitude

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General Aptitude

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General Aptitude MCQ & Objective Questions

General Aptitude is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your problem-solving skills but also boosts your confidence during exams. Practicing MCQs and objective questions helps you familiarize yourself with the exam format, identify important questions, and improve your overall performance in exam preparation.

What You Will Practise Here

Numerical Ability: Basic arithmetic, percentages, and ratios.
Logical Reasoning: Patterns, sequences, and analogies.
Data Interpretation: Reading charts, graphs, and tables.
Verbal Ability: Synonyms, antonyms, and comprehension.
Quantitative Aptitude: Algebra, geometry, and measurements.
Time and Work: Problems related to efficiency and time management.
Profit and Loss: Understanding financial transactions and calculations.

Exam Relevance

General Aptitude is a significant part of the curriculum for CBSE, State Boards, NEET, JEE, and various other competitive exams. Questions often focus on logical reasoning and quantitative skills, with patterns that include multiple-choice questions, fill-in-the-blanks, and problem-solving scenarios. Familiarity with these formats will help you tackle the exams with ease.

Common Mistakes Students Make

Misinterpreting questions due to lack of careful reading.
Overlooking units in numerical problems, leading to incorrect answers.
Rushing through calculations, resulting in simple arithmetic errors.
Neglecting to practice time management during mock tests.
Confusing similar concepts in logical reasoning sections.

FAQs

Question: What are General Aptitude MCQ questions?
Answer: General Aptitude MCQ questions are multiple-choice questions designed to test your reasoning, numerical, and analytical skills relevant to various exams.

Question: How can I improve my performance in General Aptitude objective questions?
Answer: Regular practice of important General Aptitude questions for exams, along with reviewing your mistakes, can significantly enhance your performance.

Don't wait any longer! Start solving practice MCQs today to test your understanding and boost your confidence for your upcoming exams. Every question you tackle brings you one step closer to success!

Arithmetic Aptitude Data Interpretation

Q. If the present value of a bill is Rs. 7200 and the bankers' discount is Rs. 800, what is the face value of the bill?

A. Rs. 8000
B. Rs. 7200
C. Rs. 6000
D. Rs. 5000

Solution

Face Value = Present Value + BD = 7200 + 800 = Rs. 8000.

Correct Answer: A — Rs. 8000

Q. If the present value of a sum is $4500 and the bankers discount is $500, what is the principal?

A. $5000
B. $5500
C. $6000
D. $6500

Solution

Principal = Present Value + Bankers Discount = 4500 + 500 = $5000.

Correct Answer: A — $5000

Q. If the present worth of a sum is $1200 and the banker's discount is $180 at 9% per annum, what is the time period?

A. 1 year
B. 2 years
C. 3 years
D. 4 years

Solution

Banker's Discount = P × R × T / 100. 180 = 1200 × 9 × T / 100. T = 2 years.

Correct Answer: B — 2 years

Q. If the present worth of a sum is $2000 and the true discount is $400, what is the rate of interest per annum for 2 years?

A. 5%
B. 10%
C. 15%
D. 20%

Solution

True Discount = Present Worth * Rate * Time / 100. 400 = 2000 * Rate * 2 / 100. Rate = (400 * 100) / (2000 * 2) = 10%.

Correct Answer: B — 10%

Q. If the present worth of a sum is $600 and the true discount is $100, what is the amount after 2 years at 10% per annum?

A. $700
B. $800
C. $900
D. $1000

Solution

Amount = Present Worth + True Discount = 600 + 100 = $700. Amount after 2 years = 700 * (1 + 0.10)^2 = $800.

Correct Answer: C — $900

Q. If the present worth of a sum is $600 and the true discount is $150 for 3 years, what is the rate of interest?

A. 5%
B. 6%
C. 7%
D. 8%

Solution

True Discount = Present Worth * Rate * Time / 100. Thus, 150 = 600 * r * 3 / 100. Solving gives r = 8%.

Correct Answer: C — 7%

Q. If the present worth of a sum is $800 and the true discount is $200 for 2 years, what is the rate of interest?

A. 10%
B. 12.5%
C. 15%
D. 20%

Solution

True Discount = Present Worth * Rate * Time / 100. Thus, 200 = 800 * r * 2 / 100. Solving gives r = 12.5%.

Correct Answer: B — 12.5%

Q. If the price of a shirt is $40 and it is sold at a loss of 10%, what is the selling price?

A. $36
B. $38
C. $40
D. $42

Solution

Selling Price = Cost Price - Loss = 40 - (10% of 40) = 40 - 4 = $36

Correct Answer: A — $36

Q. If the price of a shirt is increased by 20% and then decreased by 20%, what is the net change in price?

A. 0%
B. 4%
C. 8%
D. 16%

Solution

Let the original price be 100. After 20% increase: 100 + 20 = 120. After 20% decrease: 120 - 24 = 96. Net change = (96 - 100)/100 × 100% = -4%.

Correct Answer: C — 8%

Q. If the principal amount is $2000 and the rate of interest is 5% per annum, what will be the simple interest for 3 years?

A. $300
B. $400
C. $500
D. $600

Solution

Simple Interest = (Principal * Rate * Time) / 100 = (2000 * 5 * 3) / 100 = $300.

Correct Answer: A — $300

Q. If the principal is $15000 and the bankers discount is $2250, what is the rate of interest?

A. 10%
B. 12%
C. 15%
D. 18%

Solution

Rate = (Bankers Discount × 100) / (Principal × Time) = (2250 × 100) / (15000 × 1) = 15%.

Correct Answer: A — 10%

Q. If the radius of a circle is 7 cm, what is its area? (Use π = 22/7)

A. 154 cm²
B. 44 cm²
C. 77 cm²
D. 88 cm²

Solution

Area = π × radius² = (22/7) × (7 cm)² = 154 cm².

Correct Answer: A — 154 cm²

Q. If the ratio of boys to girls in a class is 2:3 and there are 30 students in total, how many boys are there?

A. 12
B. 18
C. 15
D. 10

Solution

Let the number of boys be 2x and girls be 3x. Then, 2x + 3x = 30, which gives 5x = 30. Therefore, x = 6. Number of boys = 2x = 2 * 6 = 12.

Correct Answer: A — 12

Q. If the ratio of boys to girls in a class is 3:2 and there are 30 students, how many girls are there?

A. 10
B. 12
C. 18
D. 20

Solution

Let the number of boys be 3x and girls be 2x. Then, 3x + 2x = 30, which gives 5x = 30, so x = 6. Therefore, the number of girls is 2x = 12.

Correct Answer: B — 12

Q. If the ratio of boys to girls in a class is 3:2, how many boys are there if there are 20 girls?

A. 30
B. 25
C. 15
D. 20

Solution

Let the number of boys be 3x and girls be 2x. 2x = 20, so x = 10. Boys = 3x = 30.

Correct Answer: A — 30

Q. If the ratio of boys to girls in a class is 3:2, how many girls are there if there are 30 boys?

A. 20
B. 15
C. 25
D. 10

Solution

Let the number of girls be 2x and boys be 3x. 3x = 30, so x = 10. Number of girls = 2x = 20.

Correct Answer: A — 20

Q. If the ratio of boys to girls in a class is 3:2, what fraction of the class are boys?

A. 3/5
B. 2/5
C. 1/2
D. 1/3

Solution

Total parts = 3 + 2 = 5. Fraction of boys = 3/5.

Correct Answer: A — 3/5

Q. If the ratio of boys to girls in a class is 3:4 and there are 28 girls, how many boys are there?

A. 21
B. 24
C. 25
D. 30

Solution

Let the number of boys be 3x and girls be 4x. Given 4x = 28, we find x = 7. Thus, boys = 3x = 3*7 = 21.

Correct Answer: A — 21

Q. If the ratio of shares A to shares B is 3:2 and there are 150 shares in total, how many shares of A are there?

A. 90
B. 60
C. 75
D. 45

Solution

Let shares of A = 3x and shares of B = 2x. Then, 3x + 2x = 150, 5x = 150, x = 30. Therefore, shares of A = 3x = 90.

Correct Answer: A — 90

Q. If the ratio of shares A to shares B is 3:2 and there are 60 shares in total, how many shares of A are there?

A. 30
B. 36
C. 24
D. 20

Solution

Let shares of A = 3x and shares of B = 2x. Then, 3x + 2x = 60, 5x = 60, x = 12. Therefore, shares of A = 3x = 36.

Correct Answer: A — 30

Q. If the ratio of shares A to shares B is 3:2 and there are 60 shares of A, how many shares of B are there?

A. 40
B. 30
C. 20
D. 50

Solution

Let the number of shares of B be x. Then, 3/2 = 60/x => x = (2/3) * 60 = 40 shares of B.

Correct Answer: A — 40

Q. If the ratio of the ages of A and B is 3:4 and the sum of their ages is 56 years, what is the age of A?

A. 24 years
B. 28 years
C. 32 years
D. 36 years

Solution

Let A's age be 3x and B's age be 4x. Then, 3x + 4x = 56. Solving gives x = 8, so A's age = 3x = 24 years.

Correct Answer: A — 24 years

Q. If the ratio of the ages of A and B is 4:5 and A is 20 years old, how old is B?

A. 25
B. 30
C. 35
D. 40

Solution

If A's age is 4x and B's age is 5x, then 4x = 20 => x = 5. Therefore, B's age = 5x = 25.

Correct Answer: A — 25

Q. If the ratio of the lengths of two sides of a triangle is 3:4 and the perimeter is 70 cm, what is the length of the shorter side?

A. 21
B. 24
C. 18
D. 30

Solution

Let the sides be 3x and 4x. Then, 3x + 4x = 70, 7x = 70, x = 10. Therefore, the shorter side = 3x = 3*10 = 30.

Correct Answer: A — 21

Q. If the ratio of the number of apples to oranges is 3:5 and there are 40 oranges, how many apples are there?

A. 24
B. 30
C. 20
D. 32

Solution

Let apples be 3x and oranges be 5x. Given 5x = 40, x = 8. Therefore, apples = 3x = 3*8 = 24.

Correct Answer: A — 24

Q. If the ratio of the price of stock A to stock B is 3:5 and stock A costs $90, what is the cost of stock B?

A. $120
B. $150
C. $180
D. $200

Solution

Let the cost of stock B be x. Then, 3/5 = 90/x => x = (90 * 5) / 3 = $150

Correct Answer: B — $150

Q. If the ratio of the speeds of two cars is 5:7 and the faster car travels 140 km in 2 hours, how far does the slower car travel in the same time?

A. 100
B. 120
C. 140
D. 160

Solution

Let the speeds be 5x and 7x. Faster car's speed = 70 km/h. Slower car's speed = (5/7)*70 = 50 km/h. Distance = speed * time = 50 * 2 = 100 km.

Correct Answer: B — 120

Q. If the ratio of the speeds of two trains is 5:7 and the faster train travels 140 km in an hour, how far does the slower train travel in the same time?

A. 100
B. 120
C. 140
D. 160

Solution

Let the speeds be 5x and 7x. Given 7x = 140, x = 20. Therefore, slower train speed = 5x = 5*20 = 100 km.

Correct Answer: B — 120

Q. If the ratio of the speeds of two trains is 5:7 and the faster train travels 280 km in 4 hours, how far does the slower train travel in the same time?

A. 200
B. 240
C. 280
D. 320

Solution

Speed of faster train = 280/4 = 70 km/h. Speed of slower train = (5/7)*70 = 50 km/h. Distance = speed * time = 50*4 = 200 km.

Correct Answer: B — 240

Q. If the ratio of two numbers is 5:6 and their difference is 11, what are the two numbers?

A. 25, 30
B. 20, 25
C. 15, 20
D. 10, 15

Solution

Let the numbers be 5x and 6x. Then, 6x - 5x = 11, x = 11. The numbers are 5*11 = 55 and 6*11 = 66.

Correct Answer: A — 25, 30

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