Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. A football field is 100 meters long and 64 meters wide. What is the area of the field in square meters? (2019)

A. 6400
B. 10000
C. 8000
D. 6000

Solution

Area = length × width = 100 m × 64 m = 6400 square meters.

Correct Answer: A — 6400

Q. A football field is 100 meters long and 64 meters wide. What is the perimeter of the field? (2023)

A. 328 m
B. 264 m
C. 200 m
D. 300 m

Solution

Perimeter = 2(Length + Width) = 2(100 m + 64 m) = 2 * 164 m = 328 m.

Correct Answer: A — 328 m

Q. A football match lasts for 90 minutes. If a player plays for 60 minutes, what fraction of the match did he play? (2019)

A. 1/2
B. 2/3
C. 3/4
D. 5/6

Solution

The fraction of the match played is 60 minutes out of 90 minutes, which is 60/90 = 2/3.

Correct Answer: B — 2/3

Q. A football match lasts for 90 minutes. If a player runs at an average speed of 8 km/h, how far does he run in the entire match? (2019)

A. 10 km
B. 12 km
C. 14 km
D. 15 km

Solution

Distance = Speed × Time. Time in hours = 90/60 = 1.5 hours. Distance = 8 km/h × 1.5 h = 12 km.

Correct Answer: B — 12 km

Q. A football match lasts for 90 minutes. If a player runs at an average speed of 8 km/h, how far does he run during the match? (2019)

A. 10 km
B. 12 km
C. 8 km
D. 6 km

Solution

Distance = Speed × Time. Time in hours = 90/60 = 1.5 hours. Distance = 8 km/h × 1.5 h = 12 km.

Correct Answer: C — 8 km

Q. A football team has a win rate of 40%. If they played 30 matches, how many matches did they win? (2020)

A. 10
B. 12
C. 15
D. 8

Solution

Matches won = 40% of 30 = 0.4 * 30 = 12.

Correct Answer: A — 10

Q. A football team has a win rate of 60%. If they play 50 matches, how many matches do they win? (2019)

A. 25
B. 30
C. 35
D. 40

Solution

Number of matches won = 60% of 50 = 0.6 * 50 = 30 matches.

Correct Answer: B — 30

Q. A football team wins 70% of its matches. If they played 30 matches, how many matches did they win? (2022)

A. 20
B. 21
C. 22
D. 23

Solution

Matches won = 70% of 30 = 0.7 * 30 = 21 matches.

Correct Answer: A — 20

Q. A force is measured as 100 N with an uncertainty of ±2 N. What is the maximum possible value of the force?

A. 102 N
B. 98 N
C. 100 N
D. 104 N

Solution

Maximum possible value = measured value + uncertainty = 100 + 2 = 102 N.

Correct Answer: A — 102 N

Q. A force is measured as 50 N with an uncertainty of ±1 N. What is the percentage uncertainty in the force measurement?

A. 2%
B. 1%
C. 0.5%
D. 0.1%

Solution

Percentage uncertainty = (absolute uncertainty / measured value) * 100 = (1 / 50) * 100 = 2%.

Correct Answer: B — 1%

Q. A force is measured as 50 N with an uncertainty of ±2 N. What is the percentage uncertainty in the force measurement?

A. 4%
B. 2%
C. 1%
D. 5%

Solution

Percentage uncertainty = (absolute uncertainty / measured value) * 100 = (2 / 50) * 100 = 4%.

Correct Answer: A — 4%

Q. A force is measured as 50 N with an uncertainty of ±2 N. What is the relative uncertainty in this force measurement?

A. 0.04
B. 0.02
C. 0.01
D. 0.05

Solution

Relative uncertainty = (absolute uncertainty / measured value) = 2 / 50 = 0.04 or 4%.

Correct Answer: B — 0.02

Q. A force of 10 N is applied at a distance of 0.5 m from the pivot point. What is the torque about the pivot?

A. 2.0 Nm
B. 5.0 Nm
C. 10.0 Nm
D. 20.0 Nm

Solution

Torque (τ) = Force (F) × Distance (d) = 10 N × 0.5 m = 5 Nm.

Correct Answer: A — 2.0 Nm

Q. A force of 10 N is applied at a distance of 2 m from the pivot point. What is the torque about the pivot?

A. 5 Nm
B. 10 Nm
C. 20 Nm
D. 15 Nm

Solution

Torque = Force × Distance = 10 N × 2 m = 20 Nm.

Correct Answer: C — 20 Nm

Q. A force of 10 N is applied at a distance of 2 m from the pivot point. What is the torque about the pivot point?

A. 5 Nm
B. 10 Nm
C. 20 Nm
D. 15 Nm

Solution

Torque = Force × Distance = 10 N × 2 m = 20 Nm.

Correct Answer: C — 20 Nm

Q. A force of 10 N is applied at an angle of 60 degrees to a lever arm of 2 m. What is the torque about the pivot?

A. 10 Nm
B. 17.32 Nm
C. 20 Nm
D. 5 Nm

Solution

Torque = Force × Distance × sin(60°) = 10 N × 2 m × (√3/2) = 17.32 Nm.

Correct Answer: B — 17.32 Nm

Q. A force of 10 N is applied to a 2 kg object at rest. What is the final velocity of the object after 5 seconds?

A. 2 m/s
B. 5 m/s
C. 10 m/s
D. 15 m/s

Solution

Using F = ma, a = F/m = 10 N / 2 kg = 5 m/s². Final velocity v = u + at = 0 + 5 * 5 = 25 m/s.

Correct Answer: B — 5 m/s

Q. A force of 10 N is applied to a 2 kg object. What is the net force acting on the object if it is also experiencing a frictional force of 4 N?

A. 6 N
B. 10 N
C. 14 N
D. 4 N

Solution

Net force = applied force - frictional force = 10 N - 4 N = 6 N.

Correct Answer: A — 6 N

Q. A force of 10 N is applied to a 2 kg object. What is the object's acceleration?

A. 5 m/s²
B. 10 m/s²
C. 2 m/s²
D. 20 m/s²

Solution

Using F = ma, acceleration a = F/m = 10 N / 2 kg = 5 m/s².

Correct Answer: A — 5 m/s²

Q. A force of 10 N is applied to a 2 kg object. What is the resulting acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we have a = F/m = 10 N / 2 kg = 5 m/s².

Correct Answer: A — 2 m/s²

Q. A force of 10 N is applied to an object, causing it to accelerate at 2 m/s². What is the mass of the object? (2020)

A. 5 kg
B. 10 kg
C. 15 kg
D. 20 kg

Solution

Using F = ma, mass m = F/a = 10 N / 2 m/s² = 5 kg.

Correct Answer: A — 5 kg

Q. A force of 10 N is applied to move a box 5 m across a floor. What is the work done on the box?

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done = Force × Distance = 10 N × 5 m = 50 J

Correct Answer: B — 20 J

Q. A force of 10 N is applied to move a box 5 m across a floor. What is the work done by the force?

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done = Force × Distance = 10 N × 5 m = 50 J

Correct Answer: B — 20 J

Q. A force of 10 N is applied to move a box 5 m across a frictionless surface. What is the work done on the box? (2021)

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done (W) = Force (F) × Distance (d) = 10 N × 5 m = 50 J.

Correct Answer: B — 20 J

Q. A force of 10 N is applied to move a box 5 m along a horizontal surface. What is the work done by the force? (2021)

A. 20 J
B. 50 J
C. 10 J
D. 5 J

Solution

Work done = Force × Distance = 10 N × 5 m = 50 J

Correct Answer: B — 50 J

Q. A force of 10 N is applied to move an object 5 m in the direction of the force. What is the work done by the force?

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done (W) = Force (F) × Distance (d) × cos(θ). Here, θ = 0° (force and displacement are in the same direction). W = 10 N × 5 m × cos(0°) = 10 N × 5 m = 50 J.

Correct Answer: B — 20 J

Q. A force of 10 N is applied to move an object 5 m in the direction of the force. What is the work done? (2021)

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done = Force × Distance = 10 N × 5 m = 50 J

Correct Answer: B — 20 J

Q. A force of 10 N is applied to move an object 5 m in the direction of the force. What is the work done on the object?

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done (W) = Force (F) × Distance (d) × cos(θ). Here, θ = 0° (force and displacement are in the same direction). W = 10 N × 5 m × cos(0°) = 10 N × 5 m = 50 J.

Correct Answer: B — 20 J

Q. A force of 10 N is applied to move an object 5 m. What is the work done? (2023)

A. 50 J
B. 10 J
C. 5 J
D. 20 J

Solution

Work done = Force × Distance = 10 N × 5 m = 50 J.

Correct Answer: A — 50 J

Q. A force of 100 N is applied to a 50 kg object. What is the acceleration of the object? (2022)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Acceleration = Force / Mass = 100 N / 50 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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