Q. What is the electric potential at a point 0.4 m away from a charge of +5 µC?
A.
45 V
B.
50 V
C.
55 V
D.
60 V
Show solution
Solution
V = k * q / r = (9 × 10^9) * (5 × 10^-6) / 0.4 = 112.5 V.
Correct Answer:
B
— 50 V
Learn More →
Q. What is the electric potential at a point due to a charge Q at a distance r? (2021)
A.
kQ/r
B.
kQr
C.
kQ/r^2
D.
0
Show solution
Solution
The electric potential (V) at a distance r from a point charge Q is given by V = kQ/r.
Correct Answer:
A
— kQ/r
Learn More →
Q. What is the electron configuration of Chromium?
A.
[Ar] 3d4 4s2
B.
[Ar] 3d5 4s1
C.
[Ar] 3d6 4s2
D.
[Ar] 3d3 4s2
Show solution
Solution
Chromium (Cr) has the electron configuration [Ar] 3d5 4s1 due to stability of half-filled d-orbitals.
Correct Answer:
B
— [Ar] 3d5 4s1
Learn More →
Q. What is the energy of a photon emitted when an electron transitions from n=3 to n=2 in a hydrogen atom? (Rydberg constant R = 1.097 x 10^7 m^-1) (2021)
A.
1.89 eV
B.
3.40 eV
C.
4.86 eV
D.
5.13 eV
Show solution
Solution
Energy = 13.6 eV * (1/n1^2 - 1/n2^2) = 13.6 * (1/2^2 - 1/3^2) = 3.40 eV.
Correct Answer:
B
— 3.40 eV
Learn More →
Q. What is the equation of a plane passing through the point (1, 2, 3) with normal vector (1, 1, 1)? (2022)
A.
x + y + z = 6
B.
x + y + z = 3
C.
x + y + z = 1
D.
x + y + z = 0
Show solution
Solution
Equation of the plane: 1(x-1) + 1(y-2) + 1(z-3) = 0 => x + y + z = 6.
Correct Answer:
A
— x + y + z = 6
Learn More →
Q. What is the equation of a plane passing through the point (1, 2, 3) with normal vector (2, -1, 3)? (2021)
A.
2x - y + 3z = 12
B.
2x + y - 3z = 0
C.
2x - y + 3z = 0
D.
2x + y + 3z = 12
Show solution
Solution
Equation of the plane: 2(x-1) - 1(y-2) + 3(z-3) = 0 simplifies to 2x - y + 3z = 12.
Correct Answer:
C
— 2x - y + 3z = 0
Learn More →
Q. What is the equation of the line parallel to y = 3x + 4 that passes through the point (2, 5)? (2022)
A.
y = 3x - 1
B.
y = 3x + 1
C.
y = 3x + 2
D.
y = 3x + 3
Show solution
Solution
Since parallel lines have the same slope, the equation is y - 5 = 3(x - 2) which simplifies to y = 3x + 1.
Correct Answer:
B
— y = 3x + 1
Learn More →
Q. What is the equation of the line parallel to y = 3x - 5 and passing through (2, 1)?
A.
y = 3x - 8
B.
y = 3x + 5
C.
y = 3x - 1
D.
y = 3x + 1
Show solution
Solution
Parallel lines have the same slope. The slope is 3. Using point-slope form: y - 1 = 3(x - 2) gives y = 3x - 8.
Correct Answer:
A
— y = 3x - 8
Learn More →
Q. What is the equation of the line parallel to y = 3x - 5 that passes through the point (2, 1)?
A.
y = 3x - 8
B.
y = 3x + 5
C.
y = 3x - 1
D.
y = 3x + 1
Show solution
Solution
Since the lines are parallel, they have the same slope. Using point-slope form: y - 1 = 3(x - 2) gives y = 3x - 8.
Correct Answer:
A
— y = 3x - 8
Learn More →
Q. What is the equation of the line passing through (0, 0) and (2, 4)? (2019)
A.
y = 2x
B.
y = x
C.
y = 4x
D.
y = 3x
Show solution
Solution
Slope = (4-0)/(2-0) = 2, so the equation is y = 2x.
Correct Answer:
A
— y = 2x
Learn More →
Q. What is the equation of the line passing through (0, 0) with a slope of 3? (2021)
A.
y = 3x
B.
y = x/3
C.
y = 3/x
D.
y = 1/3x
Show solution
Solution
Equation of line: y = mx + c; here m = 3, c = 0 => y = 3x
Correct Answer:
A
— y = 3x
Learn More →
Q. What is the equation of the line passing through (2, 3) with a slope of 2? (2021)
A.
y = 2x - 1
B.
y = 2x + 1
C.
y = 2x + 3
D.
y = 2x - 3
Show solution
Solution
Using point-slope form: y - 3 = 2(x - 2) => y = 2x - 4 + 3 => y = 2x - 1.
Correct Answer:
B
— y = 2x + 1
Learn More →
Q. What is the equation of the line passing through the points (1, 2) and (3, 4)?
A.
y = x + 1
B.
y = 2x
C.
y = x + 2
D.
y = 2x - 2
Show solution
Solution
The slope m = (4 - 2) / (3 - 1) = 1. Using point-slope form, y - 2 = 1(x - 1) gives y = x + 1.
Correct Answer:
A
— y = x + 1
Learn More →
Q. What is the equation of the line passing through the points (1, 2) and (3, 6)?
A.
y = 2x
B.
y = 3x - 1
C.
y = x + 1
D.
y = 4x - 2
Show solution
Solution
The slope m = (6 - 2) / (3 - 1) = 2. Using point-slope form, y - 2 = 2(x - 1) gives y = 2x.
Correct Answer:
A
— y = 2x
Learn More →
Q. What is the equation of the line perpendicular to y = 3x + 1 that passes through (2, 3)?
A.
y = -1/3x + 4
B.
y = 3x - 3
C.
y = -3x + 9
D.
y = 1/3x + 2
Show solution
Solution
The slope of the perpendicular line is -1/3. Using point-slope form, we find y - 3 = -1/3(x - 2) which simplifies to y = -1/3x + 4.
Correct Answer:
A
— y = -1/3x + 4
Learn More →
Q. What is the equation of the line that passes through the origin and has a slope of -5?
A.
y = -5x
B.
y = 5x
C.
y = -x/5
D.
y = 5/x
Show solution
Solution
The equation of a line through the origin with slope m is y = mx. Thus, y = -5x.
Correct Answer:
A
— y = -5x
Learn More →
Q. What is the equation of the line that passes through the origin and has a slope of -1?
A.
y = -x
B.
y = x
C.
y = -2x
D.
y = 2x
Show solution
Solution
The equation of a line through the origin with slope m is y = mx. Thus, y = -1x or y = -x.
Correct Answer:
A
— y = -x
Learn More →
Q. What is the equation of the plane passing through the point (1, 2, 3) with normal vector (1, -1, 1)? (2023)
A.
x - y + z = 0
B.
x + y + z = 6
C.
x - y + z = 1
D.
x + y - z = 0
Show solution
Solution
Equation of the plane: 1(x-1) - 1(y-2) + 1(z-3) = 0 => x - y + z = 1.
Correct Answer:
C
— x - y + z = 1
Learn More →
Q. What is the equation of the plane passing through the points (1, 2, 3), (4, 5, 6), and (7, 8, 9)? (2021)
A.
0 = 0
B.
x + y + z = 12
C.
x + y + z = 10
D.
x + y + z = 9
Show solution
Solution
The points are collinear, hence the equation of the plane is 0 = 0.
Correct Answer:
A
— 0 = 0
Learn More →
Q. What is the equilibrium constant (K) for the dissociation of acetic acid (CH3COOH) in water? (2023)
A.
1.8 x 10^-5
B.
1.0
C.
10
D.
100
Show solution
Solution
The dissociation constant (K) for acetic acid is approximately 1.8 x 10^-5, indicating it is a weak acid.
Correct Answer:
A
— 1.8 x 10^-5
Learn More →
Q. What is the equilibrium constant (Kc) expression for the reaction: 2A + B ⇌ C?
A.
Kc = [C] / ([A]^2[B])
B.
Kc = [A]^2[B] / [C]
C.
Kc = [C] / [A]^2
D.
Kc = [A]^2 / ([B][C])
Show solution
Solution
The equilibrium constant Kc is defined as the ratio of the concentration of products to the concentration of reactants, each raised to the power of their coefficients in the balanced equation. For the reaction 2A + B ⇌ C, Kc = [C] / ([A]^2[B]).
Correct Answer:
A
— Kc = [C] / ([A]^2[B])
Learn More →
Q. What is the equilibrium constant (Kc) for the reaction 2A + B ⇌ C? (2022)
A.
Kc = [C] / ([A]^2[B])
B.
Kc = [A]^2[B] / [C]
C.
Kc = [B] / ([A]^2[C])
D.
Kc = [C] / ([B][A])
Show solution
Solution
The equilibrium constant Kc is defined as the concentration of the products raised to the power of their coefficients divided by the concentration of the reactants raised to the power of their coefficients. For the reaction 2A + B ⇌ C, Kc = [C] / ([A]^2[B]).
Correct Answer:
A
— Kc = [C] / ([A]^2[B])
Learn More →
Q. What is the equilibrium constant (Kc) for the reaction: A + B ⇌ C + D? (2022)
A.
Kc = [C][D]/[A][B]
B.
Kc = [A][B]/[C][D]
C.
Kc = [C][D][A][B]
D.
Kc = [A][B][C][D]
Show solution
Solution
The equilibrium constant Kc is defined as the ratio of the concentrations of the products to the reactants, each raised to the power of their coefficients in the balanced equation.
Correct Answer:
A
— Kc = [C][D]/[A][B]
Learn More →
Q. What is the equilibrium constant (Kc) for the reaction: N2(g) + 3H2(g) ⇌ 2NH3(g)? (2022) 2022
A.
1.0 × 10^-5
B.
1.0 × 10^-2
C.
1.0 × 10^2
D.
1.0 × 10^5
Show solution
Solution
The equilibrium constant Kc for the formation of ammonia from nitrogen and hydrogen is typically around 1.0 × 10^5 at standard conditions.
Correct Answer:
D
— 1.0 × 10^5
Learn More →
Q. What is the equivalent resistance of two 4Ω resistors in parallel? (2019)
Show solution
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/4 = 1/2, thus R_eq = 2Ω.
Correct Answer:
A
— 2Ω
Learn More →
Q. What is the equivalent resistance of two resistors of 4Ω and 12Ω in parallel? (2022)
Show solution
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/12 = 1/3, so R_eq = 3Ω.
Correct Answer:
A
— 3Ω
Learn More →
Q. What is the escape velocity from the surface of a planet with a radius of 4,000 km and a mass of 6 × 10^24 kg? (G = 6.67 × 10^-11 N m²/kg²)
A.
10,000 m/s
B.
11,200 m/s
C.
12,000 m/s
D.
13,000 m/s
Show solution
Solution
Escape velocity = √(2GM/R) = √(2 * 6.67 × 10^-11 * 6 × 10^24 / 4 × 10^6) = 11,200 m/s
Correct Answer:
B
— 11,200 m/s
Learn More →
Q. What is the escape velocity from the surface of the Earth? (g = 9.8 m/s², R = 6.4 × 10^6 m)
A.
11.2 km/s
B.
9.8 km/s
C.
7.9 km/s
D.
15 km/s
Show solution
Solution
Escape velocity (v) = √(2gR) = √(2 * 9.8 * 6.4 × 10^6) ≈ 11.2 km/s
Correct Answer:
A
— 11.2 km/s
Learn More →
Q. What is the escape velocity from the surface of the Earth? (R = 6.4 × 10^6 m, g = 9.8 m/s²)
A.
11.2 km/s
B.
9.8 km/s
C.
7.9 km/s
D.
12.0 km/s
Show solution
Solution
Escape velocity v = √(2gR) = √(2 * 9.8 * 6.4 × 10^6) ≈ 11.2 km/s.
Correct Answer:
A
— 11.2 km/s
Learn More →
Q. What is the expected major product when 2-bromobutane undergoes elimination reaction?
A.
But-1-ene
B.
But-2-ene
C.
But-3-ene
D.
Butane
Show solution
Solution
The major product of the elimination reaction of 2-bromobutane is But-2-ene due to the formation of the more stable alkene.
Correct Answer:
B
— But-2-ene
Learn More →
Showing 1651 to 1680 of 2530 (85 Pages)
