Diameter = 2 * radius = 2 * 9 cm = 18 cm.

Area = πr²; 50.24 = πr²; r² = 50.24/π; r ≈ 4 cm; Diameter = 2r = 8 cm.

Area = πr²; 50π = πr²; r² = 50; r = √50; Diameter = 2√50 ≈ 10 units.

Area = πr²; 78.5 = πr²; r² = 78.5/π; d = 2√(78.5/π) ≈ 10 cm.

The direction of the magnetic field around a straight conductor carrying current is counterclockwise when viewed from the positive end of the conductor.

The direction of the magnetic field inside a bar magnet is from the north pole to the south pole.

The discriminant is b² - 4ac = (-12)² - 4*3*12 = 144 - 144 = 0.

The discriminant is b² - 4ac = (-12)² - 4*3*9 = 0.

The discriminant is b² - 4ac = (-12)² - 4*4*9 = 144 - 144 = 0.

The discriminant is b² - 4ac = 6² - 4*1*9 = 0.

The distance from the center to a point on the circumference is the radius, which is 8 cm.

The distance from the center to any point on the circumference is always the radius, which is 15 cm.

The distance from the center to a point on the circumference is the radius, which is 12 cm.

The distance from the center to a point on the circumference is the radius, which is 10 cm.

Distance = |d1 - d2| / √(A² + B² + C²) = |5 - 10| / √(2² + 3² + (-1)²) = 5/√14.

Distance = |d1 - d2| / √(a² + b² + c²) = |4 - 10| / √(1² + 2² + 3²) = 6 / √14.

Distance = |(2 + 3 + 4 - 10) / √(1² + 1² + 1²)| = |(-1)/√3| = 1/√3.

Distance = √[(2 - (-1))² + (3 - (-1))²] = √[3² + 4²] = √25 = 5.

Distance = √[(2 - (-1))² + (3 - (-1))²] = √[3² + 4²] = √25 = 5.

Using the distance formula, d = √((5 - 2)² + (7 - 3)²) = √(9 + 16) = √25 = 5.

Distance = √[(7-3)² + (1-4)²] = √[4 + 9] = √13 ≈ 5.

Distance = √[(4-1)² + (5-2)² + (6-3)²] = √[3² + 3² + 3²] = √27 = 3√3.

Distance = |1 + 1 - 2| / √(1² + 1²) = 0 / √2 = 0.

Distance = |1 + 2 - 3| / √(1² + 1²) = |0| / √2 = 0, closest option is 1.

Distance = |1 + 2 - 5| / √(1² + 1²) = | -2 | / √2 = 2/√2 = √2.

Distance = |(1*2 + 1*3 - 5)| / √(1² + 1²) = |5 - 5| / √2 = 0

Distance = |(1*2 + 1*3 - 5)| / √(1² + 1²) = |5 - 5| / √2 = 0/√2 = 0

Distance = |3 + 4 - 5| / √(1² + 1²) = |2| / √2 = 2/√2 = √2.

A · B = (2)(4) + (3)(-1) = 8 - 3 = 5.

Inserting a dielectric material increases the capacitance of a capacitor by reducing the electric field within it.