Q. In the reaction 2H2 + O2 → 2H2O, how many grams of oxygen are required to react with 4 grams of hydrogen?
A.
16 g
B.
8 g
C.
4 g
D.
2 g
Show solution
Solution
First, calculate moles of H2: 4 g / 2 g/mol = 2 moles. From the reaction, 2 moles of H2 require 1 mole of O2. Therefore, 2 moles of O2 = 32 g.
Correct Answer:
B
— 8 g
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Q. In the reaction 2H2 + O2 → 2H2O, how many grams of water are produced from 4 grams of hydrogen?
A.
18 g
B.
36 g
C.
54 g
D.
72 g
Show solution
Solution
4 grams of H2 is 2 moles (4 g / 2 g/mol). According to the equation, 2 moles of H2 produce 2 moles of H2O, which is 36 g (2 moles x 18 g/mol).
Correct Answer:
B
— 36 g
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Q. In the reaction 2H2 + O2 → 2H2O, how many grams of water can be produced from 4 grams of hydrogen?
A.
36 g
B.
18 g
C.
72 g
D.
9 g
Show solution
Solution
4 g of H2 = 2 moles. 2 moles of H2 produce 2 moles of H2O = 2 * 18 g = 36 g.
Correct Answer:
A
— 36 g
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Q. In the reaction 2H2 + O2 → 2H2O, how many liters of H2O vapor are produced from 4 liters of H2?
A.
4 L
B.
8 L
C.
2 L
D.
6 L
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Solution
4 L of H2 produces 4 L of H2O vapor at STP.
Correct Answer:
B
— 8 L
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Q. In the reaction 2H2 + O2 → 2H2O, how many liters of water vapor are produced from 4 liters of hydrogen at STP?
A.
4 L
B.
8 L
C.
2 L
D.
6 L
Show solution
Solution
4 L of H2 produces 4 L of H2O since the ratio is 1:1.
Correct Answer:
B
— 8 L
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Q. In the reaction 2H2 + O2 → 2H2O, how many moles of O2 are required to completely react with 6 moles of H2?
A.
2 moles
B.
3 moles
C.
4 moles
D.
6 moles
Show solution
Solution
From the balanced equation, 2 moles of H2 require 1 mole of O2. Therefore, 6 moles of H2 will require (6/2) = 3 moles of O2.
Correct Answer:
B
— 3 moles
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Q. In the reaction 2H2 + O2 → 2H2O, how many moles of O2 are required to react with 6 moles of H2?
A.
3 moles
B.
4 moles
C.
6 moles
D.
2 moles
Show solution
Solution
According to the stoichiometry of the reaction, 2 moles of H2 require 1 mole of O2. Therefore, 6 moles of H2 will require (6/2) = 3 moles of O2.
Correct Answer:
A
— 3 moles
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Q. In the reaction 2H2 + O2 → 2H2O, how many moles of water are produced from 4 moles of hydrogen?
A.
2 moles
B.
4 moles
C.
6 moles
D.
8 moles
Show solution
Solution
According to the stoichiometry of the reaction, 2 moles of H2 produce 2 moles of H2O. Therefore, 4 moles of H2 will produce 4 moles of H2O.
Correct Answer:
B
— 4 moles
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Q. In the reaction 2H2 + O2 → 2H2O, if 3 moles of O2 are available, how many moles of H2 are required?
A.
3 moles
B.
6 moles
C.
1.5 moles
D.
4.5 moles
Show solution
Solution
According to the stoichiometry, 1 mole of O2 requires 2 moles of H2. Therefore, 3 moles of O2 will require 3 x 2 = 6 moles of H2.
Correct Answer:
B
— 6 moles
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Q. In the reaction 2H2 + O2 → 2H2O, if you start with 3 moles of O2, how many moles of H2 are required?
A.
3 moles
B.
6 moles
C.
1.5 moles
D.
4 moles
Show solution
Solution
According to the stoichiometry, 1 mole of O2 requires 2 moles of H2. Therefore, 3 moles of O2 will require 6 moles of H2.
Correct Answer:
B
— 6 moles
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Q. In the reaction 2H2 + O2 → 2H2O, what is the ratio of moles of hydrogen to moles of oxygen?
A.
1:1
B.
2:1
C.
2:2
D.
1:2
Show solution
Solution
The balanced equation shows that 2 moles of H2 react with 1 mole of O2, giving a ratio of 2:1.
Correct Answer:
B
— 2:1
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Q. In the reaction 2H2 + O2 → 2H2O, which element is oxidized?
Show solution
Solution
Oxygen (O) is oxidized as it goes from 0 in O2 to -2 in H2O.
Correct Answer:
B
— O
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Q. In the reaction 2Mg + O2 → 2MgO, which element is oxidized? (2021)
A.
Magnesium
B.
Oxygen
C.
Both Magnesium and Oxygen
D.
Neither Magnesium nor Oxygen
Show solution
Solution
Magnesium is oxidized as it loses electrons and its oxidation state increases from 0 to +2.
Correct Answer:
A
— Magnesium
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Q. In the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O, what is being oxidized? (2019)
A.
MnO4-
B.
C2O4^2-
C.
H+
D.
CO2
Show solution
Solution
C2O4^2- (oxalate ion) is being oxidized to CO2 in this reaction.
Correct Answer:
B
— C2O4^2-
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Q. In the reaction 2MnO4^- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O, what is the role of MnO4^-? (2023)
A.
Oxidizing agent
B.
Reducing agent
C.
Neutral agent
D.
Catalyst
Show solution
Solution
MnO4^- acts as an oxidizing agent as it gains electrons and is reduced to Mn^2+.
Correct Answer:
A
— Oxidizing agent
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Q. In the reaction 2MnO4⁻ + 5C2O4²⁻ + 16H⁺ → 2Mn²⁺ + 10CO2 + 8H2O, which species is reduced? (2019)
A.
MnO4⁻
B.
C2O4²⁻
C.
H⁺
D.
CO2
Show solution
Solution
In this reaction, MnO4⁻ is reduced to Mn²⁺ as it gains electrons.
Correct Answer:
A
— MnO4⁻
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Q. In the reaction 2Na + Cl2 → 2NaCl, how many grams of NaCl can be produced from 2 moles of Na? (2021)
A.
58.5 g
B.
117 g
C.
29.25 g
D.
146 g
Show solution
Solution
2 moles of Na produce 2 moles of NaCl. Molar mass of NaCl = 58.5 g/mol. Therefore, 2 moles of NaCl = 2 × 58.5 g = 117 g.
Correct Answer:
B
— 117 g
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Q. In the reaction 2Na + Cl2 → 2NaCl, how many grams of NaCl can be produced from 5 g of Na?
A.
10 g
B.
15 g
C.
20 g
D.
25 g
Show solution
Solution
5 g of Na = 0.217 moles. 2 moles of Na produce 2 moles of NaCl, so 0.217 moles of NaCl = 0.217 * 58.5 g = 12.7 g.
Correct Answer:
A
— 10 g
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Q. In the reaction 2Na + Cl2 → 2NaCl, how many grams of sodium chloride are produced from 4 moles of sodium? (2023)
A.
236 g
B.
118 g
C.
472 g
D.
59 g
Show solution
Solution
4 moles of Na produce 4 moles of NaCl. Molar mass of NaCl = 58.5 g/mol. Therefore, 4 × 58.5 = 236 g.
Correct Answer:
A
— 236 g
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Q. In the reaction 2Na + Cl2 → 2NaCl, how many moles of NaCl are produced from 4 moles of Na? (2023)
A.
2 moles
B.
4 moles
C.
6 moles
D.
8 moles
Show solution
Solution
From 2 moles of Na, 2 moles of NaCl are produced. Therefore, from 4 moles of Na, 4 moles of NaCl are produced.
Correct Answer:
B
— 4 moles
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Q. In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens if SO2 is removed from the system?
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Increase in temperature
Show solution
Solution
Removing SO2 will shift the equilibrium to the left to produce more SO2, according to Le Chatelier's principle.
Correct Answer:
B
— Shift to the left
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Q. In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens to the equilibrium if the volume of the container is decreased?
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Increase the rate of reaction
Show solution
Solution
Decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas, which is the right side (2 moles of SO3).
Correct Answer:
A
— Shift to the right
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Q. In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens to the equilibrium when the volume of the container is decreased? (2023)
A.
Equilibrium shifts to the left
B.
Equilibrium shifts to the right
C.
No change in equilibrium
D.
Equilibrium shifts to the side with more moles
Show solution
Solution
According to Le Chatelier's principle, decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas. In this case, the right side has 2 moles of SO3 compared to 3 moles on the left, so the equilibrium shifts to the right.
Correct Answer:
B
— Equilibrium shifts to the right
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Q. In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what is the effect of increasing the pressure on the equilibrium?
A.
Shift to the left
B.
Shift to the right
C.
No effect
D.
Depends on the temperature
Show solution
Solution
Increasing the pressure will shift the equilibrium towards the side with fewer moles of gas, which is the right side in this case (2 moles of SO3).
Correct Answer:
B
— Shift to the right
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Q. In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what is the effect of increasing the concentration of SO2?
A.
Shifts to the right
B.
Shifts to the left
C.
No effect
D.
Increases the rate of reaction
Show solution
Solution
Increasing the concentration of a reactant shifts the equilibrium position to the right, favoring the formation of products (SO3).
Correct Answer:
A
— Shifts to the right
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Q. In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if SO3 is removed from the system?
A.
Equilibrium shifts to the left
B.
Equilibrium shifts to the right
C.
No change
D.
Equilibrium constant increases
Show solution
Solution
Removing SO3 will shift the equilibrium to the right to produce more SO3, according to Le Chatelier's principle.
Correct Answer:
B
— Equilibrium shifts to the right
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Q. In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if the volume of the container is increased? (2023)
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Increase in temperature
Show solution
Solution
According to Le Chatelier's principle, increasing the volume of the container decreases the pressure. The equilibrium will shift towards the side with more moles of gas, which is the left side (2 moles of SO2 + 1 mole of O2).
Correct Answer:
B
— Shift to the left
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Q. In the reaction 3A + 2B → 4C, if 6 moles of A are used, how many moles of C will be produced?
A.
4 moles
B.
6 moles
C.
8 moles
D.
12 moles
Show solution
Solution
From the stoichiometry, 3 moles of A produce 4 moles of C. Therefore, 6 moles of A will produce (6 moles A) x (4 moles C / 3 moles A) = 8 moles of C.
Correct Answer:
C
— 8 moles
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Q. In the reaction 3H2 + N2 → 2NH3, how many moles of nitrogen are required to produce 6 moles of ammonia?
A.
3 moles
B.
2 moles
C.
1 mole
D.
4 moles
Show solution
Solution
According to the stoichiometry, 2 moles of NH3 require 1 mole of N2. Therefore, 6 moles of NH3 will require 3 moles of N2.
Correct Answer:
A
— 3 moles
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Q. In the reaction 3H2 + N2 → 2NH3, which element is oxidized?
Show solution
Solution
Hydrogen (H) is oxidized as it goes from an oxidation state of 0 to +1 in NH3.
Correct Answer:
A
— H
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