Let the first term be a and the common difference be d. From the equations a + d = 10 and a + 3d = 14, we can solve for a and find it to be 8.

Let the first term be a and the common difference be d. From the equations a + d = 8 and a + 3d = 14, solving gives a = 6.

Let the first term be a and the common difference be d. From the equations a + 2d = 12 and a + 6d = 24, we can find d = 3.

Let the first term be a and the common difference be d. From the equations a + 2d = 15 and a + 5d = 24, we can solve for d, which gives d = 3.

Let the first term be a and the common difference be d. From the equations a + 3d = 20 and a + 6d = 26, we can solve for a and find it to be 12.

Let the first term be a and the common difference be d. From the given terms, we have a + 4d = 20 and a + 9d = 35. Solving these gives a = 10.

The sum of the first n terms is given by S_n = n/2 * (2a + (n-1)d). Here, S_8 = 8/2 * (20 + 35) = 4 * 55 = 220.

Using the formula for the last term, 48 = 12 + (10-1)d. Solving gives d = 4.

Using the nth term formula, we have 40 = 4 + (10-1)d. Solving gives d = 4.

The nth term of an AP is given by a + (n-1)d. Here, a = 5, d = 3, and n = 10. So, the 10th term = 5 + (10-1) * 3 = 5 + 27 = 32.

Using the nth term formula, a + (n-1)d = 7 + 5*(-2) = 7 - 10 = -3.

Using the formula S_n = n/2 * (2a + (n-1)d), we have 100 = 10/2 * (2a + 9*2). Solving gives a = 10.

Using the formula S_n = n/2 * (2a + (n-1)d), we can substitute n = 10 and d = 5 to find a = 20.

Using the sum formula S_n = n/2 * (2a + (n-1)d), we have 50 = 5/2 * (10 + 4d). Solving gives d = 7.

Using the sum formula S_n = n/2 * (2a + (n-1)d), we have 50 = 5/2 * (2a + 8). Solving gives a = 10.

The sum of the first n terms is given by S_n = n/2 * (2a + (n-1)d). Here, 50 = 5/2 * (2a + 8). Solving gives a = 10.

Using the formula for the nth term: a_n = a + (n-1)d, we have 45 = 5 + 9d. Solving gives d = 4.

Herbivores are primary consumers as they feed directly on producers (plants).

Plants are primary producers as they convert sunlight into chemical energy through photosynthesis.

Power in an electric circuit is given by P = V * I. Here, P = 12 V * 3 A = 36 W.

Power in an electric circuit is given by P = V^2/R. If V is doubled, P becomes (2V)^2/R = 4V^2/R, which is quadrupled.

In an electrochemical cell, oxidation occurs at the anode.

In an endothermic reaction, the enthalpy of the products is higher than that of the reactants.

Range = Measured value ± Uncertainty = 200 g ± 5 g = 195 g to 205 g.

Total uncertainty = 3 * (0.5 m) = ±1.5 m.

Absolute error is the uncertainty in the measurement, which is ±0.2 kg.

Maximum possible error is equal to the uncertainty, which is ±0.2 V.

The absolute error is given as ±0.3 V.

The maximum possible error is the absolute uncertainty, which is ±0.5 V.

The absolute error is given directly as ±0.5 V.