Physics Syllabus (JEE Main)

Current Electricity Electrostatics Gravitation Kinematics Kinetic Theory of Gases Laws of Motion Magnetism & EMI Modern Physics Optics Oscillations & Waves Properties of Matter Rotational Motion Thermodynamics Units & Measurement Work, Energy & Power

Q. If a 10 kg object is dropped from a height of 20 m, what is its potential energy at the top? (1960)

A. 200 J
B. 1000 J
C. 500 J
D. 1500 J

Solution

Potential Energy (PE) = m * g * h = 10 kg * 9.8 m/s^2 * 20 m = 1960 J

Correct Answer: B — 1000 J

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Q. If a 10 kg object is dropped from a height of 5 m, what is the potential energy at that height?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Potential energy = mgh = 10 kg × 9.8 m/s² × 5 m = 490 J.

Correct Answer: B — 100 J

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Q. If a 10 kg object is in free fall, what is the force acting on it due to gravity?

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

The force due to gravity is F = mg = 10 kg * 9.8 m/s² = 98 N, which rounds to 100 N.

Correct Answer: B — 20 N

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Q. If a 10 kg object is moving with a velocity of 4 m/s, what is its kinetic energy?

A. 80 J
B. 40 J
C. 20 J
D. 160 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 10 * (4^2) = 80 J

Correct Answer: A — 80 J

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Q. If a 10 kg object is pulled with a force of 30 N, what is its acceleration?

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. If a 10 kg object is pulled with a force of 50 N, what is its acceleration?

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²

Solution

Using F = ma, a = F/m = 50 N / 10 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. If a 10 kg object is subjected to a net force of 30 N, what is the object's acceleration?

A. 3 m/s²
B. 2 m/s²
C. 1.5 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: A — 3 m/s²

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Q. If a 10 kg object is subjected to a net force of 30 N, what will be its acceleration?

A. 3 m/s²
B. 0.3 m/s²
C. 30 m/s²
D. 300 m/s²

Solution

Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: A — 3 m/s²

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Q. If a 10 kg object is subjected to a net force of 50 N, what is its acceleration?

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 15 m/s²

Solution

Using F = ma, acceleration a = F/m = 50 N / 10 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. If a 10 kg object is subjected to a net force of 50 N, what will be its acceleration?

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²

Solution

Using F = ma, acceleration a = F/m = 50 N / 10 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. If a 10 ohm resistor is connected to a 20V battery, what is the energy consumed in 5 seconds?

A. 20 J
B. 40 J
C. 10 J
D. 50 J

Solution

Power P = V^2 / R = 20^2 / 10 = 40 W. Energy = Power * time = 40 W * 5 s = 200 J.

Correct Answer: B — 40 J

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Q. If a 10 ohm resistor is connected to a 30V battery, what is the energy consumed in 5 seconds?

A. 15 J
B. 30 J
C. 75 J
D. 150 J

Solution

Power P = V^2 / R = (30V)^2 / 10 ohms = 90 W. Energy = Power * Time = 90 W * 5 s = 450 J.

Correct Answer: C — 75 J

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Q. If a 1000 kg car accelerates from rest to a speed of 20 m/s in 10 seconds, what is the average power output of the car's engine?

A. 2000 W
B. 4000 W
C. 6000 W
D. 8000 W

Solution

First, calculate the work done: W = 0.5 * m * v^2 = 0.5 * 1000 kg * (20 m/s)^2 = 200000 J. Then, power is P = W/t = 200000 J / 10 s = 20000 W.

Correct Answer: C — 6000 W

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Q. If a 1000 W heater is used for 3 hours, how much energy does it consume in kilowatt-hours?

A. 3 kWh
B. 2 kWh
C. 1 kWh
D. 0.5 kWh

Solution

Energy consumed in kilowatt-hours is calculated as E = P (kW) * t (h). Here, P = 1000 W = 1 kW and t = 3 hours. Thus, E = 1 kW * 3 h = 3 kWh.

Correct Answer: A — 3 kWh

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Q. If a 1000 W heater runs for 2 hours, how much energy does it consume?

A. 7200 J
B. 14400 J
C. 20000 J
D. 3600000 J

Solution

Energy = Power × Time = 1000 W × (2 × 3600 s) = 7200000 J.

Correct Answer: D — 3600000 J

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Q. If a 10Ω resistor is connected to a 20V battery, what is the power dissipated by the resistor?

A. 20W
B. 40W
C. 100W
D. 200W

Solution

Power (P) can be calculated using P = V^2/R. Here, P = 20V^2 / 10Ω = 400 / 10 = 40W.

Correct Answer: B — 40W

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Q. If a 10Ω resistor is connected to a 20V source, what is the energy consumed in 5 seconds?

A. 20J
B. 40J
C. 50J
D. 100J

Solution

Power P = V^2 / R = 20V^2 / 10Ω = 40W. Energy = Power * time = 40W * 5s = 200J.

Correct Answer: B — 40J

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Q. If a 12 kg object is moving with a constant velocity, what can be said about the net force acting on it?

A. It is zero
B. It is equal to its weight
C. It is equal to the applied force
D. It is increasing

Solution

An object moving with constant velocity has a net force of zero according to Newton's first law.

Correct Answer: A — It is zero

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Q. If a 12 kg object is pushed with a force of 48 N, what is the acceleration of the object?

A. 2 m/s²
B. 4 m/s²
C. 6 m/s²
D. 8 m/s²

Solution

Using F = ma, acceleration a = F/m = 48 N / 12 kg = 4 m/s².

Correct Answer: B — 4 m/s²

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Q. If a 12V battery is connected across a 4 ohm resistor, what is the current flowing through the resistor?

A. 2 A
B. 3 A
C. 4 A
D. 6 A

Solution

Using Ohm's law, I = V/R = 12V / 4Ω = 3 A.

Correct Answer: A — 2 A

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Q. If a 12V battery is connected across a 4 ohm resistor, what is the power dissipated in the resistor?

A. 12 W
B. 24 W
C. 36 W
D. 48 W

Solution

Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 144 / 4 = 36 W.

Correct Answer: B — 24 W

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Q. If a 12V battery is connected across a 4Ω resistor, what is the current flowing through the resistor?

A. 3A
B. 2A
C. 4A
D. 1A

Solution

Using Ohm's law, I = V/R = 12V / 4Ω = 3A.

Correct Answer: B — 2A

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Q. If a 12V battery is connected to a 4 ohm resistor, what is the power dissipated by the resistor?

A. 12 W
B. 24 W
C. 36 W
D. 48 W

Solution

Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 36 W.

Correct Answer: B — 24 W

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Q. If a 2 kg object is acted upon by a net force of 6 N, what is the object's acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we find a = F/m = 6 N / 2 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. If a 2 kg object is dropped from a height of 5 m, what is its speed just before it hits the ground? (g = 10 m/s²)

A. 10 m/s
B. 5 m/s
C. 15 m/s
D. 20 m/s

Solution

Using energy conservation: PE_initial = KE_final; m * g * h = 1/2 * m * v^2; v = sqrt(2gh) = sqrt(2 * 10 * 5) = 10 m/s

Correct Answer: A — 10 m/s

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Q. If a 2 kg object is dropped from a height of 5 m, what is its velocity just before it hits the ground? (g = 10 m/s²)

A. 10 m/s
B. 5 m/s
C. 15 m/s
D. 20 m/s

Solution

Using energy conservation, v = sqrt(2gh) = sqrt(2 * 10 * 5) = 10 m/s

Correct Answer: A — 10 m/s

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Q. If a 2 kg object is moving with a velocity of 3 m/s and a force of 6 N is applied in the opposite direction, what will be its final velocity after 2 seconds?

A. 0 m/s
B. 1 m/s
C. 2 m/s
D. 3 m/s

Solution

Net force = -6 N, acceleration = F/m = -6 N / 2 kg = -3 m/s². Final velocity = initial velocity + at = 3 m/s + (-3 m/s² * 2 s) = 0 m/s.

Correct Answer: B — 1 m/s

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Q. If a 2 kg object is pulled with a force of 10 N and experiences a frictional force of 4 N, what is its acceleration?

A. 3 m/s²
B. 5 m/s²
C. 2 m/s²
D. 1 m/s²

Solution

Net force = applied force - friction = 10 N - 4 N = 6 N. Acceleration a = F/m = 6 N / 2 kg = 3 m/s².

Correct Answer: A — 3 m/s²

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Q. If a 2 kg object is subjected to a net force of 6 N, what is its acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we have a = F/m = 6 N / 2 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. If a 3 kg object is in free fall, what is the force acting on it due to gravity?

A. 3 N
B. 9 N
C. 30 N
D. None of the above

Solution

Force due to gravity F = mg = 3 kg * 9.8 m/s² = 29.4 N, approximately 9 N for simplification.

Correct Answer: B — 9 N

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Physics Syllabus (JEE Main)

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