Q. A solid sphere of mass M and radius R rolls without slipping down an inclined plane of height h. What is the speed of the center of mass of the sphere at the bottom of the incline? (2021)
A.
√(2gh)
B.
√(3gh/2)
C.
√(gh)
D.
√(4gh/3)
Solution
Using conservation of energy, potential energy at the top = kinetic energy at the bottom. The total kinetic energy is the sum of translational and rotational kinetic energy. Thus, mgh = (1/2)mv^2 + (1/5)mv^2, leading to v = √(10gh/7).
Q. A solid sphere of mass M and radius R rolls without slipping down an inclined plane of height h. What is the speed of the center of mass of the sphere when it reaches the bottom? (2021)
A.
√(2gh)
B.
√(5gh/7)
C.
√(3gh/5)
D.
√(gh)
Solution
Using conservation of energy, potential energy at the top = kinetic energy at the bottom. The total kinetic energy is the sum of translational and rotational kinetic energy. Thus, v = √(5gh/7).
Q. A uniform rod of length L and mass M is pivoted at one end and allowed to fall under gravity. What is the angular acceleration of the rod just after it is released? (2019)
A.
g/L
B.
2g/L
C.
3g/L
D.
g/2L
Solution
The torque τ = Mg(L/2) and moment of inertia I = (1/3)ML². Using τ = Iα, we find α = 3g/2L.
Q. A uniform rod of length L and mass M is pivoted at one end and released from rest. What is the angular velocity of the rod just before it hits the ground? (2019)
A.
√(3g/L)
B.
√(2g/L)
C.
√(g/L)
D.
√(4g/L)
Solution
Using conservation of energy, potential energy at the top is converted to rotational kinetic energy at the bottom. The angular velocity ω can be found using the relation ω = √(3g/L).
Q. A uniform rod of length L and mass M is pivoted at one end and released from rest. What is the angular speed of the rod just before it hits the ground? (2019)
A.
√(3g/L)
B.
√(2g/L)
C.
√(g/L)
D.
√(4g/L)
Solution
Using conservation of energy, potential energy at the top converts to rotational kinetic energy at the bottom. The angular speed ω = √(3g/L).
Q. A wheel of radius R and mass M is rolling without slipping on a horizontal surface. If it has a linear speed v, what is its total kinetic energy? (2022)
A.
(1/2)Mv²
B.
(1/2)Mv² + (1/2)(Iω²)
C.
(1/2)Mv² + (1/2)(Mv²)
D.
(1/2)Mv² + (1/2)(Mv²/2)
Solution
The total kinetic energy is the sum of translational and rotational kinetic energy. K.E. = (1/2)Mv² + (1/2)(Iω²) where I = (1/2)MR² for a solid cylinder.
Q. A wheel of radius R is rolling without slipping on a horizontal surface. If the wheel has an angular velocity ω, what is the linear velocity of the center of the wheel? (2023)
A.
Rω
B.
ω/R
C.
ω
D.
2Rω
Solution
The linear velocity v of the center of the wheel is given by v = Rω.
Q. A wire of length L and diameter d is stretched by a force F. If the diameter is halved while keeping the length constant, what happens to the stress in the wire? (2022)
A.
It doubles
B.
It quadruples
C.
It remains the same
D.
It halves
Solution
Stress (σ) = Force (F) / Area (A). Halving the diameter increases the area by a factor of 4, thus stress quadruples.
Q. A wire of length L and diameter d is stretched by a force F. If the diameter is halved while keeping the length constant, what happens to the stress? (2020)
A.
It doubles
B.
It quadruples
C.
It halves
D.
It remains the same
Solution
Stress = Force / Area. Halving the diameter increases the area by a factor of 1/4, thus stress quadruples.
Q. A wire of length L and diameter d is stretched by a force F. If the diameter is doubled, what will be the new elongation if the same force is applied? (2019)
A.
L/4
B.
L/2
C.
L
D.
2L
Solution
Elongation is inversely proportional to the area. Doubling the diameter increases the area by a factor of 4, thus elongation becomes L/4.
The National Eligibility cum Entrance Test (NEET) is a crucial examination for aspiring medical students in India. Scoring well in NEET can open doors to prestigious medical colleges, making it essential for students to prepare effectively. Practicing NEET MCQs and objective questions not only enhances understanding but also boosts confidence, ensuring you are well-prepared for the exam. Engaging with practice questions helps identify important topics and improves your ability to tackle various question formats.
What You Will Practise Here
Human Anatomy and Physiology
Biochemistry and Molecular Biology
Genetics and Evolution
Plant and Animal Physiology
Ecology and Environment
Physics Concepts Relevant to Biology
Important NEET questions on Chemical Bonding and Reactions
Exam Relevance
NEET is aligned with the syllabus of CBSE and various State Boards, ensuring that the topics covered are relevant for both school exams and competitive tests like JEE. Common question patterns include multiple-choice questions that assess conceptual understanding and application of knowledge. By focusing on NEET objective questions, students can familiarize themselves with the exam format and improve their time management skills during the actual test.
Common Mistakes Students Make
Misinterpreting questions due to lack of careful reading.
Overlooking the importance of diagrams and visual aids in biology.
Neglecting to review basic concepts that are foundational for advanced topics.
Confusing similar terms and definitions, especially in biochemistry.
FAQs
Question: How can I improve my NEET MCQ solving skills? Answer: Regular practice with NEET MCQ questions and reviewing explanations for both correct and incorrect answers can significantly enhance your skills.
Question: Are there specific topics I should focus on for NEET preparation? Answer: Yes, focus on high-weightage topics like Human Physiology, Genetics, and Ecology, as they frequently appear in exams.
Start your journey towards success by solving NEET practice MCQs today! Test your understanding, identify your strengths and weaknesses, and prepare effectively for your upcoming exams.
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