Physics Syllabus (JEE Main)

Current Electricity Electrostatics Gravitation Kinematics Kinetic Theory of Gases Laws of Motion Magnetism & EMI Modern Physics Optics Oscillations & Waves Properties of Matter Rotational Motion Thermodynamics Units & Measurement Work, Energy & Power

Q. A 3 kg object is at rest on a frictionless surface. A force of 9 N is applied. What is the final velocity after 3 seconds?

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

First, find acceleration: a = F/m = 9 N / 3 kg = 3 m/s². Then, v = u + at = 0 + 3 m/s² * 3 s = 9 m/s.

Correct Answer: C — 3 m/s

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Q. A 3 kg object is at rest on a frictionless surface. If a force of 9 N is applied, what will be its velocity after 3 seconds?

A. 3 m/s
B. 6 m/s
C. 9 m/s
D. 12 m/s

Solution

First, find acceleration: a = F/m = 9 N / 3 kg = 3 m/s². Then, v = u + at = 0 + 3 m/s² * 3 s = 9 m/s.

Correct Answer: B — 6 m/s

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Q. A 3 kg object is at rest on a horizontal surface. If a force of 12 N is applied, what is the object's acceleration? (Assume no friction)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: C — 4 m/s²

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Q. A 3 kg object is at rest on a horizontal surface. If a horizontal force of 12 N is applied, what is the object's acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: B — 3 m/s²

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Q. A 3 kg object is at rest on a table. If a force of 15 N is applied horizontally, what is the object's acceleration?

A. 5 m/s²
B. 10 m/s²
C. 15 m/s²
D. 20 m/s²

Solution

Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: A — 5 m/s²

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Q. A 3 kg object is at rest on a table. If a horizontal force of 12 N is applied, what is the acceleration of the object?

A. 4 m/s²
B. 0 m/s²
C. 3 m/s²
D. 12 m/s²

Solution

Using F = ma, acceleration a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: A — 4 m/s²

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Q. A 3 kg object is dropped from a height of 12 m. What is the potential energy at the top?

A. 30 J
B. 36 J
C. 60 J
D. 120 J

Solution

Potential energy = mgh = 3 kg × 9.8 m/s² × 12 m = 352.8 J.

Correct Answer: D — 120 J

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Q. A 3 kg object is dropped from a height of 15 m. What is its potential energy at the top? (g = 9.8 m/s²)

A. 441 J
B. 294 J
C. 147 J
D. 0 J

Solution

Potential Energy (PE) = m * g * h = 3 kg * 9.8 m/s² * 15 m = 441 J

Correct Answer: B — 294 J

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Q. A 3 kg object is dropped from a height of 15 m. What is the potential energy at the top?

A. 30 J
B. 45 J
C. 60 J
D. 75 J

Solution

Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 15 m = 441 J.

Correct Answer: D — 75 J

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Q. A 3 kg object is dropped from a height of 5 m. What is the potential energy at the height?

A. 15 J
B. 30 J
C. 45 J
D. 60 J

Solution

Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 5 m = 147 J.

Correct Answer: B — 30 J

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Q. A 3 kg object is in free fall. What is the force acting on it due to gravity?

A. 3 N
B. 9 N
C. 30 N
D. 0 N

Solution

The force due to gravity is F = mg = 3 kg * 9.8 m/s² = 29.4 N, approximately 30 N.

Correct Answer: B — 9 N

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Q. A 3 kg object is lifted to a height of 4 m. What is the work done against gravity?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Work done = mgh = 3 * 9.8 * 4 = 117.6 J.

Correct Answer: B — 24 J

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Q. A 3 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)

A. 147 J
B. 294 J
C. 441 J
D. 588 J

Solution

Work done = mgh = 3 kg × 9.8 m/s² × 5 m = 147 J.

Correct Answer: B — 294 J

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Q. A 3 kg object is moving in a circular path of radius 2 m with a speed of 4 m/s. What is the centripetal force acting on it?

A. 6 N
B. 12 N
C. 24 N
D. 36 N

Solution

Centripetal force F = mv²/r = 3 kg * (4 m/s)² / 2 m = 24 N.

Correct Answer: B — 12 N

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Q. A 3 kg object is moving in a straight line with a constant velocity of 5 m/s. What is the net force acting on the object?

A. 0 N
B. 3 N
C. 15 N
D. 5 N

Solution

Since the object is moving with constant velocity, the net force acting on it is 0 N.

Correct Answer: A — 0 N

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Q. A 3 kg object is moving with a speed of 10 m/s. What is its kinetic energy?

A. 150 J
B. 300 J
C. 450 J
D. 600 J

Solution

Kinetic energy = 0.5mv² = 0.5 * 3 * (10)² = 150 J.

Correct Answer: B — 300 J

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Q. A 3 kg object is moving with a speed of 10 m/s. What is its total mechanical energy?

A. 150 J
B. 300 J
C. 450 J
D. 600 J

Solution

Total mechanical energy = KE + PE. Assuming PE = 0, KE = 0.5mv² = 0.5 * 3 * (10)² = 150 J.

Correct Answer: B — 300 J

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Q. A 3 kg object is moving with a speed of 4 m/s. If a net work of 24 J is done on the object, what will be its final speed?

A. 4 m/s
B. 6 m/s
C. 8 m/s
D. 10 m/s

Solution

Initial kinetic energy = 0.5 × m × v^2 = 0.5 × 3 kg × (4 m/s)^2 = 24 J. Final kinetic energy = Initial + Work done = 24 J + 24 J = 48 J. Final speed = √(2 × KE/m) = √(2 × 48 J / 3 kg) = 6.93 m/s.

Correct Answer: C — 8 m/s

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Q. A 3 kg object is moving with a speed of 4 m/s. What is its kinetic energy?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Kinetic energy = 0.5mv² = 0.5 * 3 * (4)² = 24 J.

Correct Answer: B — 24 J

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Q. A 3 kg object is moving with a speed of 4 m/s. What is its total mechanical energy?

A. 24 J
B. 32 J
C. 48 J
D. 60 J

Solution

Total mechanical energy = KE + PE. Assuming it is at ground level, PE = 0. KE = 0.5mv² = 0.5 * 3 * (4)² = 24 J.

Correct Answer: B — 32 J

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Q. A 3 kg object is moving with a speed of 5 m/s. What is its kinetic energy?

A. 15 J
B. 25 J
C. 35 J
D. 45 J

Solution

Kinetic energy is given by KE = 0.5mv² = 0.5 * 3 * (5)² = 37.5 J, approximately 35 J.

Correct Answer: B — 25 J

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Q. A 3 kg object is moving with a velocity of 4 m/s. If a force of 12 N is applied in the opposite direction, what will be its velocity after 2 seconds?

A. 0 m/s
B. 2 m/s
C. 4 m/s
D. 6 m/s

Solution

Acceleration = F/m = -12 N / 3 kg = -4 m/s². Change in velocity = a * t = -4 m/s² * 2 s = -8 m/s. Final velocity = 4 m/s - 8 m/s = -4 m/s (object stops).

Correct Answer: B — 2 m/s

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Q. A 3 kg object is moving with a velocity of 4 m/s. If it comes to a stop, what is the work done by the friction force?

A. -24 J
B. -48 J
C. -12 J
D. -36 J

Solution

Work done by friction = - Kinetic Energy = - (0.5 × 3 kg × (4 m/s)²) = -24 J.

Correct Answer: B — -48 J

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Q. A 3 kg object is moving with a velocity of 4 m/s. What is its kinetic energy?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 3 kg × (4 m/s)² = 24 J.

Correct Answer: B — 24 J

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Q. A 3 kg object is moving with a velocity of 4 m/s. What is its momentum?

A. 6 kg·m/s
B. 12 kg·m/s
C. 9 kg·m/s
D. 15 kg·m/s

Solution

Momentum = mass × velocity = 3 kg × 4 m/s = 12 kg·m/s.

Correct Answer: B — 12 kg·m/s

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Q. A 3 kg object is moving with a velocity of 6 m/s. What is its kinetic energy?

A. 54 J
B. 36 J
C. 18 J
D. 72 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 3 * (6^2) = 54 J

Correct Answer: B — 36 J

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Q. A 3 kg object is pushed with a force of 12 N over a distance of 4 m. If the object starts from rest, what is its final speed? (Assume no friction)

A. 2 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s

Solution

Work done = Force × Distance = 12 N × 4 m = 48 J. Kinetic energy = 0.5 × mass × v²; 48 J = 0.5 × 3 kg × v²; v² = 32; v = 4 m/s.

Correct Answer: C — 4 m/s

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Q. A 3 kg object is pushed with a force of 12 N over a distance of 4 m. What is the net work done if friction does 8 J of work?

A. 28 J
B. 32 J
C. 36 J
D. 40 J

Solution

Net work done = Work done by force - Work done against friction = (12 N × 4 m) - 8 J = 48 J - 8 J = 40 J.

Correct Answer: B — 32 J

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Q. A 3 kg object is pushed with a force of 15 N over a distance of 4 m. If the object experiences a frictional force of 3 N, what is the net work done on the object?

A. 48 J
B. 60 J
C. 72 J
D. 84 J

Solution

Net force = Applied force - Friction = 15 N - 3 N = 12 N. Work done = Net force × Distance = 12 N × 4 m = 48 J.

Correct Answer: B — 60 J

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Q. A 3 kg object is pushed with a force of 15 N over a distance of 4 m. What is the work done on the object?

A. 30 J
B. 45 J
C. 60 J
D. 75 J

Solution

Work done = Force × Distance = 15 N × 4 m = 60 J.

Correct Answer: C — 60 J

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Physics Syllabus (JEE Main) MCQ & Objective Questions

The Physics Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances problem-solving skills through practice. Engaging with MCQs and objective questions is essential for effective exam preparation, as it allows students to identify important questions and strengthen their knowledge base.

What You Will Practise Here

Mechanics: Laws of Motion, Work, Energy, and Power
Thermodynamics: Laws of Thermodynamics, Heat Transfer
Waves and Oscillations: Simple Harmonic Motion, Wave Properties
Electromagnetism: Electric Fields, Magnetic Fields, and Circuits
Optics: Reflection, Refraction, and Optical Instruments
Modern Physics: Quantum Theory, Atomic Models, and Nuclear Physics
Fluid Mechanics: Properties of Fluids, Bernoulli's Principle

Exam Relevance

The Physics Syllabus (JEE Main) is integral to various examinations, including CBSE, State Boards, and competitive exams like NEET and JEE. Questions often focus on conceptual understanding and application of theories. Common patterns include numerical problems, conceptual MCQs, and assertion-reason type questions, which test both knowledge and analytical skills.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers.
Neglecting units and dimensions in calculations.
Overlooking the significance of diagrams in understanding concepts.
Confusing similar concepts, such as velocity and acceleration.
Failing to apply formulas correctly in different contexts.

FAQs

Question: What are the key topics in the Physics Syllabus for JEE Main?
Answer: Key topics include Mechanics, Thermodynamics, Waves, Electromagnetism, Optics, Modern Physics, and Fluid Mechanics.

Question: How can I improve my performance in Physics MCQs?
Answer: Regular practice of MCQs, understanding concepts deeply, and revising important formulas can significantly enhance your performance.

Start solving practice MCQs today to test your understanding of the Physics Syllabus (JEE Main). This will not only boost your confidence but also prepare you effectively for your upcoming exams. Remember, consistent practice is the key to success!

Physics Syllabus (JEE Main)

Physics Syllabus (JEE Main) MCQ & Objective Questions

What You Will Practise Here

Exam Relevance

Common Mistakes Students Make

FAQs

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