Q. How many grams are in 3 moles of glucose (C6H12O6)?
A.
180 g
B.
360 g
C.
540 g
D.
90 g
Show solution
Solution
Molar mass of glucose = 6*12 + 12*1 + 6*16 = 180 g/mol. Mass = moles x molar mass = 3 moles x 180 g/mol = 540 g.
Correct Answer:
B
— 360 g
Learn More →
Q. How many grams of CO2 are produced from the complete combustion of 1 mole of C3H8?
A.
44 g
B.
88 g
C.
132 g
D.
22 g
Show solution
Solution
C3H8 + 5O2 → 3CO2 + 4H2O. 1 mole of C3H8 produces 3 moles of CO2. Mass = 3 * 44 g = 132 g.
Correct Answer:
B
— 88 g
Learn More →
Q. How many grams of KCl are needed to prepare 0.5 moles of KCl solution?
A.
37.5 g
B.
74.5 g
C.
50 g
D.
100 g
Show solution
Solution
The molar mass of KCl is 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol. Therefore, 0.5 moles of KCl will weigh 0.5 x 74.5 g = 37.25 g.
Correct Answer:
B
— 74.5 g
Learn More →
Q. How many grams of KCl are needed to prepare 0.5 moles of KCl solution? (Molar mass of KCl = 74.5 g/mol)
A.
37.25 g
B.
74.5 g
C.
148.5 g
D.
18.5 g
Show solution
Solution
To find the mass, use the formula: mass = moles x molar mass. Thus, 0.5 moles x 74.5 g/mol = 37.25 g.
Correct Answer:
A
— 37.25 g
Learn More →
Q. How many grams of KCl are needed to prepare 0.5 moles of KCl?
A.
37.5 g
B.
45 g
C.
50 g
D.
60 g
Show solution
Solution
The molar mass of KCl is approximately 74.5 g/mol. Therefore, 0.5 moles of KCl will weigh 0.5 x 74.5 g = 37.25 g.
Correct Answer:
B
— 45 g
Learn More →
Q. How many grams of KCl can be produced from the reaction of 10 g of K with excess Cl2?
A.
74.5 g
B.
37.25 g
C.
148.5 g
D.
18.5 g
Show solution
Solution
10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.
Correct Answer:
A
— 74.5 g
Learn More →
Q. How many grams of NaOH are needed to neutralize 1 mole of HCl?
A.
40 g
B.
36.5 g
C.
58.5 g
D.
23 g
Show solution
Solution
The reaction between NaOH and HCl is 1:1. The molar mass of NaOH is 40 g/mol, so 1 mole of NaOH is needed, which weighs 40 g.
Correct Answer:
C
— 58.5 g
Learn More →
Q. How many grams of NaOH are needed to prepare 0.5 moles of NaOH solution?
A.
20 g
B.
40 g
C.
10 g
D.
30 g
Show solution
Solution
The molar mass of NaOH is 40 g/mol. Therefore, to prepare 0.5 moles, you need 0.5 x 40 g = 20 g.
Correct Answer:
B
— 40 g
Learn More →
Q. How many grams of NaOH are needed to prepare 0.5 moles of NaOH solution? (Molar mass of NaOH = 40 g/mol)
A.
20 g
B.
40 g
C.
10 g
D.
30 g
Show solution
Solution
To find the mass, use the formula: mass = moles × molar mass. Thus, 0.5 moles × 40 g/mol = 20 g.
Correct Answer:
A
— 20 g
Learn More →
Q. How many grams of solute are needed to prepare 0.5 L of a 1 M NaCl solution? (Molar mass of NaCl = 58.5 g/mol)
A.
29.25 g
B.
58.5 g
C.
14.625 g
D.
0.5 g
Show solution
Solution
Mass of solute = moles × molar mass = 1 mol × 58.5 g/mol = 58.5 g. For 0.5 L, it is 0.5 mol × 58.5 g/mol = 29.25 g.
Correct Answer:
A
— 29.25 g
Learn More →
Q. How many grams of solute are needed to prepare 2 L of a 1 M solution? (Molar mass = 58.5 g/mol)
A.
58.5 g
B.
117 g
C.
29.25 g
D.
145 g
Show solution
Solution
Grams of solute = moles x molar mass = 2 moles x 58.5 g/mol = 117 g.
Correct Answer:
B
— 117 g
Learn More →
Q. How many isomers does C4H10 have?
Show solution
Solution
C4H10 has 2 structural isomers: n-butane and isobutane.
Correct Answer:
B
— 2
Learn More →
Q. How many isomers does C5H12 have?
Show solution
Solution
C5H12 has 3 structural isomers: pentane, isopentane, and neopentane.
Correct Answer:
C
— 4
Learn More →
Q. How many molecules are present in 2 moles of water (H2O)?
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
3.011 x 10^23
D.
12.044 x 10^24
Show solution
Solution
Number of molecules = moles x Avogadro's number = 2 moles x 6.022 x 10^23 molecules/mole = 1.2044 x 10^24 molecules.
Correct Answer:
B
— 1.2044 x 10^24
Learn More →
Q. How many moles are in 1.5 kg of KCl?
Show solution
Solution
Molar mass of KCl = 39 + 35.5 = 74.5 g/mol. Number of moles = mass/molar mass = 1500 g / 74.5 g/mol ≈ 20.1 moles.
Correct Answer:
B
— 20
Learn More →
Q. How many moles are in 10 grams of NaOH?
A.
0.25
B.
0.5
C.
0.75
D.
1
Show solution
Solution
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol. Number of moles = mass/molar mass = 10 g / 40 g/mol = 0.25 moles.
Correct Answer:
A
— 0.25
Learn More →
Q. How many moles are in 100 grams of CaCO3?
Show solution
Solution
Molar mass of CaCO3 = 40 + 12 + 3*16 = 100 g/mol. Number of moles = mass/molar mass = 100 g / 100 g/mol = 1 mole.
Correct Answer:
A
— 1
Learn More →
Q. How many moles are in 180 grams of water?
Show solution
Solution
Molar mass of H2O = 2*1 + 16 = 18 g/mol. Number of moles = 180 g / 18 g/mol = 10 moles.
Correct Answer:
A
— 1
Learn More →
Q. How many moles are in 200 grams of H2O?
A.
11.11
B.
10
C.
9
D.
8.89
Show solution
Solution
Molar mass of H2O = 18 g/mol. Number of moles = mass / molar mass = 200 g / 18 g/mol = 11.11 moles.
Correct Answer:
A
— 11.11
Learn More →
Q. How many moles are in 200 grams of H2SO4?
Show solution
Solution
Molar mass of H2SO4 = 2 + 32 + 16*4 = 98 g/mol. Number of moles = 200 g / 98 g/mol = 2.04 moles.
Correct Answer:
B
— 2
Learn More →
Q. How many moles are in 36 grams of water (H2O)?
Show solution
Solution
Molar mass of H2O = 2*1 + 16 = 18 g/mol. Number of moles = mass/molar mass = 36 g / 18 g/mol = 2 moles.
Correct Answer:
A
— 1
Learn More →
Q. How many moles are in 5.6 liters of a gas at STP?
Show solution
Solution
At STP, 1 mole of gas occupies 22.4 L. Number of moles = volume / molar volume = 5.6 L / 22.4 L/mole = 0.25 moles.
Correct Answer:
C
— 1
Learn More →
Q. How many moles are in 5.6 liters of an ideal gas at STP?
Show solution
Solution
At STP, 1 mole of gas occupies 22.4 L. Therefore, number of moles = 5.6 L / 22.4 L/mole = 0.25 moles.
Correct Answer:
B
— 0.5
Learn More →
Q. How many moles are in 50 grams of CaCO3?
Show solution
Solution
Molar mass of CaCO3 = 100 g/mol. Number of moles = mass / molar mass = 50 g / 100 g/mol = 0.5 moles.
Correct Answer:
B
— 1
Learn More →
Q. How many moles are in 50 grams of H2O?
A.
2.78
B.
1.39
C.
0.56
D.
3.06
Show solution
Solution
Molar mass of H2O = 2*1 + 16 = 18 g/mol. Number of moles = mass/molar mass = 50 g / 18 g/mol = 2.78 moles.
Correct Answer:
B
— 1.39
Learn More →
Q. How many moles are in 50 grams of NaOH?
Show solution
Solution
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol. Number of moles = mass/molar mass = 50 g / 40 g/mol = 1.25 moles.
Correct Answer:
B
— 0.5
Learn More →
Q. How many moles are in 50 grams of sodium (Na)?
A.
1.08
B.
2.5
C.
0.5
D.
0.25
Show solution
Solution
Molar mass of Na = 23 g/mol. Number of moles = mass / molar mass = 50 g / 23 g/mol ≈ 2.17 moles.
Correct Answer:
A
— 1.08
Learn More →
Q. How many moles are in 500 mL of a 2 M NaCl solution?
Show solution
Solution
Moles = molarity x volume (in L) = 2 M x 0.5 L = 1 mole.
Correct Answer:
B
— 1
Learn More →
Q. How many moles are in 88 grams of CH4?
Show solution
Solution
Molar mass of CH4 = 12 + 4*1 = 16 g/mol. Number of moles = mass/molar mass = 88 g / 16 g/mol = 5.5 moles.
Correct Answer:
B
— 2
Learn More →
Q. How many moles are in 88 grams of O2?
Show solution
Solution
Molar mass of O2 = 16*2 = 32 g/mol. Number of moles = mass/molar mass = 88 g / 32 g/mol = 2.75 moles.
Correct Answer:
B
— 2
Learn More →
Showing 121 to 150 of 2802 (94 Pages)
Chemistry Syllabus (JEE Main) MCQ & Objective Questions
The Chemistry Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances performance in objective questions and MCQs. Regular practice with these types of questions is essential for scoring better and mastering important topics.
What You Will Practise Here
Basic Concepts of Chemistry
Atomic Structure and Chemical Bonding
States of Matter: Gases and Liquids
Thermodynamics and Thermochemistry
Equilibrium: Chemical and Ionic
Redox Reactions and Electrochemistry
Hydrocarbons and Environmental Chemistry
Exam Relevance
The Chemistry syllabus is a significant part of CBSE, State Boards, NEET, and JEE exams. Questions from this syllabus often appear in various formats, including multiple-choice questions, assertion-reason type questions, and numerical problems. Familiarity with the common question patterns can greatly enhance your exam preparation and confidence.
Common Mistakes Students Make
Misunderstanding the periodic trends and their implications.
Confusing different types of chemical bonds and their properties.
Neglecting to balance redox reactions properly.
Overlooking the significance of units in thermodynamic calculations.
Failing to apply concepts of equilibrium in problem-solving.
FAQs
Question: What are the key topics I should focus on in the Chemistry syllabus for JEE Main?Answer: Focus on atomic structure, chemical bonding, thermodynamics, and equilibrium as they are frequently tested.
Question: How can I improve my performance in Chemistry MCQs?Answer: Regular practice with past papers and understanding concepts deeply will help you tackle MCQs effectively.
Start your journey towards mastering the Chemistry Syllabus (JEE Main) by solving practice MCQs today. Test your understanding and build confidence for your exams!
