Physics Syllabus (JEE Main)

Current Electricity Electrostatics Gravitation Kinematics Kinetic Theory of Gases Laws of Motion Magnetism & EMI Modern Physics Optics Oscillations & Waves Properties of Matter Rotational Motion Thermodynamics Units & Measurement Work, Energy & Power

Q. A 3 kg object is at rest on a frictionless surface. A force of 9 N is applied. What is the final velocity after 3 seconds?

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

First, find acceleration: a = F/m = 9 N / 3 kg = 3 m/s². Then, v = u + at = 0 + 3 m/s² * 3 s = 9 m/s.

Correct Answer: C — 3 m/s

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Q. A 3 kg object is at rest on a frictionless surface. If a force of 9 N is applied, what will be its velocity after 3 seconds?

A. 3 m/s
B. 6 m/s
C. 9 m/s
D. 12 m/s

Solution

First, find acceleration: a = F/m = 9 N / 3 kg = 3 m/s². Then, v = u + at = 0 + 3 m/s² * 3 s = 9 m/s.

Correct Answer: B — 6 m/s

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Q. A 3 kg object is at rest on a horizontal surface. If a force of 12 N is applied, what is the object's acceleration? (Assume no friction)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: C — 4 m/s²

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Q. A 3 kg object is at rest on a horizontal surface. If a horizontal force of 12 N is applied, what is the object's acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: B — 3 m/s²

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Q. A 3 kg object is at rest on a table. If a force of 15 N is applied horizontally, what is the object's acceleration?

A. 5 m/s²
B. 10 m/s²
C. 15 m/s²
D. 20 m/s²

Solution

Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: A — 5 m/s²

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Q. A 3 kg object is at rest on a table. If a horizontal force of 12 N is applied, what is the acceleration of the object?

A. 4 m/s²
B. 0 m/s²
C. 3 m/s²
D. 12 m/s²

Solution

Using F = ma, acceleration a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: A — 4 m/s²

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Q. A 3 kg object is dropped from a height of 12 m. What is the potential energy at the top?

A. 30 J
B. 36 J
C. 60 J
D. 120 J

Solution

Potential energy = mgh = 3 kg × 9.8 m/s² × 12 m = 352.8 J.

Correct Answer: D — 120 J

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Q. A 3 kg object is dropped from a height of 15 m. What is its potential energy at the top? (g = 9.8 m/s²)

A. 441 J
B. 294 J
C. 147 J
D. 0 J

Solution

Potential Energy (PE) = m * g * h = 3 kg * 9.8 m/s² * 15 m = 441 J

Correct Answer: B — 294 J

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Q. A 3 kg object is dropped from a height of 15 m. What is the potential energy at the top?

A. 30 J
B. 45 J
C. 60 J
D. 75 J

Solution

Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 15 m = 441 J.

Correct Answer: D — 75 J

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Q. A 3 kg object is dropped from a height of 5 m. What is the potential energy at the height?

A. 15 J
B. 30 J
C. 45 J
D. 60 J

Solution

Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 5 m = 147 J.

Correct Answer: B — 30 J

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Q. A 3 kg object is in free fall. What is the force acting on it due to gravity?

A. 3 N
B. 9 N
C. 30 N
D. 0 N

Solution

The force due to gravity is F = mg = 3 kg * 9.8 m/s² = 29.4 N, approximately 30 N.

Correct Answer: B — 9 N

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Q. A 3 kg object is lifted to a height of 4 m. What is the work done against gravity?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Work done = mgh = 3 * 9.8 * 4 = 117.6 J.

Correct Answer: B — 24 J

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Q. A 3 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)

A. 147 J
B. 294 J
C. 441 J
D. 588 J

Solution

Work done = mgh = 3 kg × 9.8 m/s² × 5 m = 147 J.

Correct Answer: B — 294 J

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Q. A 3 kg object is moving in a circular path of radius 2 m with a speed of 4 m/s. What is the centripetal force acting on it?

A. 6 N
B. 12 N
C. 24 N
D. 36 N

Solution

Centripetal force F = mv²/r = 3 kg * (4 m/s)² / 2 m = 24 N.

Correct Answer: B — 12 N

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Q. A 3 kg object is moving in a straight line with a constant velocity of 5 m/s. What is the net force acting on the object?

A. 0 N
B. 3 N
C. 15 N
D. 5 N

Solution

Since the object is moving with constant velocity, the net force acting on it is 0 N.

Correct Answer: A — 0 N

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Q. A 3 kg object is moving with a speed of 10 m/s. What is its kinetic energy?

A. 150 J
B. 300 J
C. 450 J
D. 600 J

Solution

Kinetic energy = 0.5mv² = 0.5 * 3 * (10)² = 150 J.

Correct Answer: B — 300 J

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Q. A 3 kg object is moving with a speed of 10 m/s. What is its total mechanical energy?

A. 150 J
B. 300 J
C. 450 J
D. 600 J

Solution

Total mechanical energy = KE + PE. Assuming PE = 0, KE = 0.5mv² = 0.5 * 3 * (10)² = 150 J.

Correct Answer: B — 300 J

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Q. A 3 kg object is moving with a speed of 4 m/s. If a net work of 24 J is done on the object, what will be its final speed?

A. 4 m/s
B. 6 m/s
C. 8 m/s
D. 10 m/s

Solution

Initial kinetic energy = 0.5 × m × v^2 = 0.5 × 3 kg × (4 m/s)^2 = 24 J. Final kinetic energy = Initial + Work done = 24 J + 24 J = 48 J. Final speed = √(2 × KE/m) = √(2 × 48 J / 3 kg) = 6.93 m/s.

Correct Answer: C — 8 m/s

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Q. A 3 kg object is moving with a speed of 4 m/s. What is its kinetic energy?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Kinetic energy = 0.5mv² = 0.5 * 3 * (4)² = 24 J.

Correct Answer: B — 24 J

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Q. A 3 kg object is moving with a speed of 4 m/s. What is its total mechanical energy?

A. 24 J
B. 32 J
C. 48 J
D. 60 J

Solution

Total mechanical energy = KE + PE. Assuming it is at ground level, PE = 0. KE = 0.5mv² = 0.5 * 3 * (4)² = 24 J.

Correct Answer: B — 32 J

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Q. A 3 kg object is moving with a speed of 5 m/s. What is its kinetic energy?

A. 15 J
B. 25 J
C. 35 J
D. 45 J

Solution

Kinetic energy is given by KE = 0.5mv² = 0.5 * 3 * (5)² = 37.5 J, approximately 35 J.

Correct Answer: B — 25 J

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Q. A 3 kg object is moving with a velocity of 4 m/s. If a force of 12 N is applied in the opposite direction, what will be its velocity after 2 seconds?

A. 0 m/s
B. 2 m/s
C. 4 m/s
D. 6 m/s

Solution

Acceleration = F/m = -12 N / 3 kg = -4 m/s². Change in velocity = a * t = -4 m/s² * 2 s = -8 m/s. Final velocity = 4 m/s - 8 m/s = -4 m/s (object stops).

Correct Answer: B — 2 m/s

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Q. A 3 kg object is moving with a velocity of 4 m/s. If it comes to a stop, what is the work done by the friction force?

A. -24 J
B. -48 J
C. -12 J
D. -36 J

Solution

Work done by friction = - Kinetic Energy = - (0.5 × 3 kg × (4 m/s)²) = -24 J.

Correct Answer: B — -48 J

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Q. A 3 kg object is moving with a velocity of 4 m/s. What is its kinetic energy?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 3 kg × (4 m/s)² = 24 J.

Correct Answer: B — 24 J

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Q. A 3 kg object is moving with a velocity of 4 m/s. What is its momentum?

A. 6 kg·m/s
B. 12 kg·m/s
C. 9 kg·m/s
D. 15 kg·m/s

Solution

Momentum = mass × velocity = 3 kg × 4 m/s = 12 kg·m/s.

Correct Answer: B — 12 kg·m/s

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Q. A 3 kg object is moving with a velocity of 6 m/s. What is its kinetic energy?

A. 54 J
B. 36 J
C. 18 J
D. 72 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 3 * (6^2) = 54 J

Correct Answer: B — 36 J

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Q. A 3 kg object is pushed with a force of 12 N over a distance of 4 m. If the object starts from rest, what is its final speed? (Assume no friction)

A. 2 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s

Solution

Work done = Force × Distance = 12 N × 4 m = 48 J. Kinetic energy = 0.5 × mass × v²; 48 J = 0.5 × 3 kg × v²; v² = 32; v = 4 m/s.

Correct Answer: C — 4 m/s

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Q. A 3 kg object is pushed with a force of 12 N over a distance of 4 m. What is the net work done if friction does 8 J of work?

A. 28 J
B. 32 J
C. 36 J
D. 40 J

Solution

Net work done = Work done by force - Work done against friction = (12 N × 4 m) - 8 J = 48 J - 8 J = 40 J.

Correct Answer: B — 32 J

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Q. A 3 kg object is pushed with a force of 15 N over a distance of 4 m. If the object experiences a frictional force of 3 N, what is the net work done on the object?

A. 48 J
B. 60 J
C. 72 J
D. 84 J

Solution

Net force = Applied force - Friction = 15 N - 3 N = 12 N. Work done = Net force × Distance = 12 N × 4 m = 48 J.

Correct Answer: B — 60 J

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Q. A 3 kg object is pushed with a force of 15 N over a distance of 4 m. What is the work done on the object?

A. 30 J
B. 45 J
C. 60 J
D. 75 J

Solution

Work done = Force × Distance = 15 N × 4 m = 60 J.

Correct Answer: C — 60 J

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Physics Syllabus (JEE Main)

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