Major Competitive Exams

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Q. A 1000 W heater operates for 3 hours. How much energy does it consume?

A. 3000 J
B. 1080000 J
C. 3600000 J
D. 1000 J

Solution

Energy consumed is E = P * t. Here, P = 1000 W and t = 3 hours = 10800 seconds. Thus, E = 1000 W * 10800 s = 10800000 J.

Correct Answer: C — 3600000 J

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Q. A 100W bulb operates at 220V. What is the resistance of the bulb? (2021)

A. 484Ω
B. 220Ω
C. 110Ω
D. 100Ω

Solution

Using P = V^2/R, we rearrange to find R = V^2/P = (220V)^2 / 100W = 484Ω.

Correct Answer: A — 484Ω

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Q. A 12 kg box is pulled with a force of 60 N at an angle of 30 degrees to the horizontal. What is the horizontal component of the force?

A. 30 N
B. 60 N
C. 51.96 N
D. 20 N

Solution

The horizontal component is F_horizontal = F * cos(θ) = 60 N * cos(30°) = 60 N * (√3/2) = 51.96 N.

Correct Answer: C — 51.96 N

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Q. A 12 kg object is at rest on a horizontal surface. What is the normal force acting on it?

A. 0 N
B. 12 N
C. 120 N
D. 100 N

Solution

The normal force equals the weight of the object: N = mg = 12 kg * 10 m/s² = 120 N.

Correct Answer: C — 120 N

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Q. A 12 kg object is at rest. A force of 36 N is applied to it. What is the acceleration of the object? (2021)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. A 12 kg object is at rest. A force of 36 N is applied to it. What will be its velocity after 3 seconds? (2020)

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

Acceleration = Force / Mass = 36 N / 12 kg = 3 m/s². Velocity = Initial velocity + (Acceleration × Time) = 0 + (3 m/s² × 3 s) = 9 m/s.

Correct Answer: C — 3 m/s

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Q. A 12 kg object is in free fall. What is the force acting on it due to gravity?

A. 12 N
B. 24 N
C. 36 N
D. 48 N

Solution

The force due to gravity is F = mg = 12 kg * 9.8 m/s² = 117.6 N (approximately 120 N).

Correct Answer: B — 24 N

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Q. A 12 kg object is moving with a velocity of 3 m/s. What is its momentum? (2019)

A. 36 kg·m/s
B. 12 kg·m/s
C. 9 kg·m/s
D. 24 kg·m/s

Solution

Momentum p = mv = 12 kg * 3 m/s = 36 kg·m/s.

Correct Answer: A — 36 kg·m/s

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Q. A 12 kg object is moving with a velocity of 5 m/s. What is its kinetic energy?

A. 150 J
B. 120 J
C. 100 J
D. 75 J

Solution

Kinetic energy KE = 0.5 * m * v² = 0.5 * 12 kg * (5 m/s)² = 150 J.

Correct Answer: B — 120 J

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Q. A 12 kg object is moving with a velocity of 5 m/s. What is its momentum?

A. 30 kg·m/s
B. 60 kg·m/s
C. 90 kg·m/s
D. 120 kg·m/s

Solution

Momentum p = mv = 12 kg * 5 m/s = 60 kg·m/s.

Correct Answer: B — 60 kg·m/s

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Q. A 12 kg object is pulled with a force of 24 N. If the object experiences a frictional force of 4 N, what is its acceleration?

A. 1.67 m/s²
B. 2 m/s²
C. 2.5 m/s²
D. 3 m/s²

Solution

Net force = 24 N - 4 N = 20 N. Acceleration a = F/m = 20 N / 12 kg = 1.67 m/s².

Correct Answer: B — 2 m/s²

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Q. A 12 kg object is pulled with a force of 48 N. If the frictional force is 12 N, what is the acceleration of the object? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 48 N - 12 N = 36 N. Acceleration a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 12 kg object is pushed with a force of 36 N. What is its acceleration? (2023)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, we find a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. A 12V battery is connected across a 4Ω resistor. What is the current flowing through the resistor? (2020)

A. 2A
B. 3A
C. 4A
D. 6A

Solution

Using Ohm's law, I = V/R = 12V / 4Ω = 3A.

Correct Answer: A — 2A

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Q. A 12V battery is connected to a resistor of 4Ω. What is the current flowing through the circuit? (2022)

A. 2A
B. 3A
C. 4A
D. 1A

Solution

Using Ohm's law, I = V/R = 12V / 4Ω = 3A.

Correct Answer: A — 2A

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Q. A 15 kg box is pulled with a force of 60 N at an angle of 30° to the horizontal. What is the horizontal component of the force? (2022)

A. 30 N
B. 60 N
C. 51.96 N
D. 15 N

Solution

Horizontal component = F * cos(θ) = 60 N * cos(30°) = 60 N * (√3/2) = 51.96 N.

Correct Answer: C — 51.96 N

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Q. A 15 kg box is pushed with a force of 30 N. If the frictional force opposing the motion is 10 N, what is the acceleration of the box?

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Net force = applied force - friction = 30 N - 10 N = 20 N. Acceleration a = F/m = 20 N / 15 kg = 1.33 m/s².

Correct Answer: B — 2 m/s²

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Q. A 15 kg box is pushed with a force of 45 N. What is the acceleration of the box? (Assume no friction)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, we have a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. A 15 kg box is pushed with a force of 60 N on a rough surface with a frictional force of 15 N. What is the box's acceleration?

A. 3 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Net force = 60 N - 15 N = 45 N. Acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 4 m/s²

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Q. A 15 kg box is pushed with a force of 60 N. If the frictional force is 15 N, what is the acceleration of the box? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 60 N - 15 N = 45 N. Acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 15 kg box is pushed with a force of 60 N. If the frictional force is 20 N, what is the acceleration of the box?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = applied force - friction = 60 N - 20 N = 40 N. Acceleration a = F/m = 40 N / 15 kg = 2.67 m/s².

Correct Answer: B — 3 m/s²

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Q. A 15 kg cart is pushed with a force of 60 N. If the frictional force opposing the motion is 15 N, what is the acceleration of the cart?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 60 N - 15 N = 45 N. Using F = ma, a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 15 kg object is at rest on a horizontal surface. What is the normal force acting on it?

A. 0 N
B. 15 N
C. 150 N
D. 75 N

Solution

Normal force = weight = mg = 15 kg * 10 m/s² = 150 N.

Correct Answer: C — 150 N

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Q. A 15 kg object is at rest on a table. What is the force exerted by the table on the object?

A. 0 N
B. 15 N
C. 150 N
D. 10 N

Solution

The normal force equals the weight of the object: 15 kg * 10 m/s² = 150 N.

Correct Answer: C — 150 N

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Q. A 15 kg object is dropped from a height. What is the force acting on it due to gravity? (2023)

A. 15 N
B. 30 N
C. 45 N
D. 150 N

Solution

Using F = mg, where g = 9.8 m/s², we have F = 15 kg * 9.8 m/s² = 147 N, which rounds to 150 N.

Correct Answer: B — 30 N

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Q. A 15 kg object is in equilibrium. What is the net force acting on it?

A. 0 N
B. 15 N
C. 30 N
D. 45 N

Solution

In equilibrium, the net force acting on the object is 0 N.

Correct Answer: A — 0 N

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Q. A 15 kg object is lifted to a height of 4 m. What is the work done against gravity? (g = 9.8 m/s²) (2021)

A. 588 J
B. 5880 J
C. 392 J
D. 294 J

Solution

Work = mgh = 15 kg * 9.8 m/s² * 4 m = 588 J.

Correct Answer: A — 588 J

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Q. A 15 kg object is moving at a speed of 4 m/s. What is its kinetic energy?

A. 120 J
B. 240 J
C. 480 J
D. 60 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 15 kg × (4 m/s)² = 0.5 × 15 × 16 = 120 J.

Correct Answer: B — 240 J

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Q. A 15 kg object is moving with a velocity of 4 m/s. What is its momentum? (2019)

A. 60 kg m/s
B. 30 kg m/s
C. 45 kg m/s
D. 75 kg m/s

Solution

Momentum = mass × velocity = 15 kg × 4 m/s = 60 kg m/s.

Correct Answer: A — 60 kg m/s

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Q. A 15 kg object is pushed with a force of 45 N. What is the acceleration of the object?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Major Competitive Exams

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