The impedance (Z) is calculated using Z = √(R^2 + (X_L)^2). The inductive reactance X_L = 2πfL, where L = 3Ω. Therefore, Z = √(4^2 + 3^2) = √(16 + 9) = √25 = 5Ω.

Z = R + jX = 4Ω + j18Ω; |Z| = √(4^2 + 18^2) = √(16 + 324) = √340 = 18.44Ω.

Impedance in series is Z = R + jXL. If XL = 2π(50)(L) = 4Ω, then Z = 6Ω + j4Ω. The magnitude is √(6² + 4²) = 7.21Ω.

Impedance (Z) is calculated using the formula Z = √(R^2 + X^2), so Z = √(3^2 + 4^2) = 5 ohms.

In a purely resistive circuit, the impedance (Z) is equal to the resistance (R), as there is no reactance involved.

In = V / R_parallel = 15V / (1/(1/5 + 1/10)) = 15V / (10/3) = 4.5A.

In = Vsource / R = 15V / 5Ω = 3A.

The Norton equivalent current (I_N) is calculated as I_N = V/R = 20 V / 10 ohms = 2 A.

Norton current I_N = V / R = 20V / 10Ω = 2A.

The Norton equivalent current is the short-circuit current, which can be calculated as I = V / R = 20V / 10Ω = 2A.

Norton current I_N = V / R = 12V / 4Ω = 3A.

The Norton current (I_N) is calculated using I_N = V_th / R_load. Thus, I_N = 10V / 5Ω = 2A.

Norton current I_N = V_TH / R_L = 12V / 4Ω = 3A.

The Norton equivalent current is defined as the current that flows through a short circuit placed across the terminals of the circuit.

Norton current I_N = V / R = 12V / 4Ω = 3 A.

The Norton equivalent circuit is represented by a single current source in parallel with a resistance, simplifying the analysis of the circuit.

In a purely capacitive circuit, the current leads the voltage by 90 degrees.

In a purely resistive AC circuit, the voltage and current are in phase, meaning the phase difference is 0 degrees.

Power P = I² * R = (2A)² * 10Ω = 4A² * 10Ω = 40W.

Power (P) is calculated using the formula P = V * I. Therefore, P = 12 V * 3 A = 36 W.

Power (P) is calculated as P = V * I, so P = 120 V * 10 A = 1200 W.

Power (P) is calculated as P = V * I = 120 V * 3 A = 360 W.

Power P = V * I = 120V * 3A = 360W.

Power (P) can be calculated using P = I^2 * R. Therefore, P = (2A)^2 * 10Ω = 4 * 10 = 40W.

Power (P) is calculated using P = I^2 * R. Therefore, P = (2A)^2 * 10Ω = 4 * 10 = 40W.

Power P = I^2 * R = (2A)^2 * 10Ω = 4 * 10 = 40 W.

The power factor in an AC circuit with a purely resistive load is 1, indicating that all the power is being used effectively.

The power factor is defined as the ratio of real power (P) to apparent power (S) in an AC circuit, indicating how effectively the current is being converted into useful work.

The power factor is defined as the cosine of the phase angle between voltage and current. In a purely resistive circuit, this angle is 0 degrees, so the power factor is 1.

Ohm's Law states that the voltage (V) across a conductor is directly proportional to the current (I) flowing through it, with the resistance (R) being the constant of proportionality.