Physics Syllabus (JEE Main)

Current Electricity Electrostatics Gravitation Kinematics Kinetic Theory of Gases Laws of Motion Magnetism & EMI Modern Physics Optics Oscillations & Waves Properties of Matter Rotational Motion Thermodynamics Units & Measurement Work, Energy & Power

Q. How many significant figures are in the number 0.007890?

A. 3
B. 4
C. 5
D. 6

Solution

The significant figures are 7, 8, 9, and the trailing zero counts.

Correct Answer: C — 5

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Q. How many significant figures are in the number 100.0?

A. 1
B. 2
C. 3
D. 4

Solution

The trailing zero after the decimal point counts as a significant figure.

Correct Answer: D — 4

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Q. How many significant figures are in the number 1002?

A. 2
B. 3
C. 4
D. 1

Solution

All non-zero digits are significant, so 1002 has 4 significant figures.

Correct Answer: C — 4

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Q. How many significant figures are in the number 5000 when no decimal point is present?

A. 1
B. 2
C. 3
D. 4

Solution

5000 has 1 significant figure unless specified otherwise (e.g., 5000. has 4 significant figures).

Correct Answer: A — 1

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Q. How many significant figures are in the number 5000?

A. 1
B. 2
C. 3
D. 4

Solution

5000 has 1 significant figure unless specified with a decimal point (e.g., 5000. has 4).

Correct Answer: A — 1

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Q. How much heat is required to convert 1 kg of water at 100°C to steam at 100°C? (Latent heat of vaporization = 2260 J/g)

A. 1000 J
B. 2260 J
C. 2260000 J
D. 100000 J

Solution

Q = m * L = 1000 g * 2260 J/g = 2260000 J.

Correct Answer: C — 2260000 J

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Q. How should the number 0.0001234 be rounded to two significant figures?

A. 0.00012
B. 0.00013
C. 0.0001
D. 0.000123

Solution

To round 0.0001234 to two significant figures, we look at the first two non-zero digits (1 and 2) and round up, resulting in 0.00013.

Correct Answer: B — 0.00013

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Q. How should the number 0.05060 be rounded to three significant figures?

A. 0.051
B. 0.0506
C. 0.05060
D. 0.050

Solution

To round 0.05060 to three significant figures, we keep the first three significant digits (5, 0, and 6), resulting in 0.0506.

Correct Answer: B — 0.0506

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Q. If 1 kg of water is heated from 20°C to 100°C, how much heat is absorbed? (Specific heat of water = 4.2 J/g°C)

A. 3360 J
B. 4000 J
C. 4200 J
D. 4800 J

Solution

Q = m*c*ΔT = 1000 g * 4.2 J/g°C * (100°C - 20°C) = 4200 J.

Correct Answer: C — 4200 J

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Q. If 1 mole of an ideal gas occupies 22.4 L at STP, what is the pressure exerted by the gas?

A. 1 atm
B. 2 atm
C. 0.5 atm
D. 4 atm

Solution

At STP (Standard Temperature and Pressure), 1 mole of an ideal gas occupies 22.4 L at a pressure of 1 atm.

Correct Answer: A — 1 atm

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Q. If 1 mole of an ideal gas occupies 22.4 L at STP, what is the volume occupied by 2 moles at the same conditions?

A. 11.2 L
B. 22.4 L
C. 44.8 L
D. 56.8 L

Solution

According to Avogadro's Law, 2 moles of gas will occupy double the volume, which is 44.8 L at STP.

Correct Answer: C — 44.8 L

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Q. If 100 g of water at 0°C is mixed with 100 g of water at 100°C, what will be the final temperature?

A. 50°C
B. 25°C
C. 75°C
D. 0°C

Solution

The final temperature will be 50°C due to equal masses and specific heat capacities.

Correct Answer: A — 50°C

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Q. If 100 g of water at 0°C is mixed with 100 g of water at 100°C, what will be the final temperature of the mixture?

A. 50°C
B. 25°C
C. 75°C
D. 0°C

Solution

Using the principle of conservation of energy, the final temperature will be 50°C.

Correct Answer: A — 50°C

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Q. If 100 g of water at 80°C is mixed with 200 g of water at 20°C, what will be the final temperature?

A. 30°C
B. 40°C
C. 50°C
D. 60°C

Solution

Using the principle of conservation of energy, the final temperature can be calculated to be 40°C.

Correct Answer: B — 40°C

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Q. If 100 J of heat is added to a system and 40 J of work is done by the system, what is the change in internal energy?

A. 60 J
B. 40 J
C. 100 J
D. 140 J

Solution

According to the First Law of Thermodynamics, ΔU = Q - W. Here, ΔU = 100 J - 40 J = 60 J.

Correct Answer: A — 60 J

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Q. If 10^(2x) = 100, what is the value of x?

A. 0
B. 0.5
C. 1
D. 2

Solution

100 = 10^2, so 2x = 2, hence x = 1.

Correct Answer: B — 0.5

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Q. If 10^x = 0.01, what is the value of x?

A. -2
B. -1
C. 0
D. 1

Solution

Since 0.01 = 10^(-2), we have x = -2.

Correct Answer: A — -2

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Q. If 2 moles of an ideal gas at 300 K occupy a volume of 10 L, what is the pressure of the gas? (Use R = 0.0821 L·atm/(K·mol))

A. 0.5 atm
B. 1.0 atm
C. 2.0 atm
D. 3.0 atm

Solution

Using the Ideal Gas Law, P = nRT/V = (2 moles * 0.0821 L·atm/(K·mol) * 300 K) / 10 L = 4.926 atm.

Correct Answer: B — 1.0 atm

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Q. If 200 g of ice at 0°C is added to 100 g of water at 80°C, what will be the final temperature of the mixture? (Latent heat of fusion of ice = 334 J/g)

A. 0°C
B. 20°C
C. 40°C
D. 60°C

Solution

Heat lost by water = Heat gained by ice. 100g * 80°C = 200g * 334 J/g + 200g * (Tf - 0°C). Solving gives Tf = 20°C.

Correct Answer: B — 20°C

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Q. If 2^(x+1) = 16, what is the value of x?

A. 2
B. 3
C. 4
D. 5

Solution

16 = 2^4 => x + 1 = 4 => x = 3

Correct Answer: B — 3

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Q. If 300 g of water at 25°C is mixed with 200 g of water at 75°C, what is the final temperature? (Specific heat of water = 4.2 J/g°C)

A. 40°C
B. 50°C
C. 60°C
D. 70°C

Solution

Using m1*T1 + m2*T2 = (m1 + m2)*Tf, we find Tf = (300*25 + 200*75) / (300 + 200) = 50°C.

Correct Answer: B — 50°C

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Q. If 3^(2x) = 81, what is the value of x?

A. 2
B. 3
C. 4
D. 1

Solution

Since 81 = 3^4, we have 3^(2x) = 3^4, thus 2x = 4, giving x = 2.

Correct Answer: A — 2

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Q. If 4^x = 64, what is the value of x?

A. 2
B. 3
C. 4
D. 5

Solution

Since 64 = 4^3, we have x = 3.

Correct Answer: B — 3

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Q. If 500 J of heat is added to a system and 200 J of work is done by the system, what is the change in internal energy?

A. 300 J
B. 500 J
C. 700 J
D. 200 J

Solution

According to the first law of thermodynamics, ΔU = Q - W. Here, ΔU = 500 J - 200 J = 300 J.

Correct Answer: A — 300 J

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Q. If 5^(x+1) = 125, what is the value of x?

A. 1
B. 2
C. 3
D. 4

Solution

125 = 5^3, so x + 1 = 3, hence x = 2.

Correct Answer: B — 2

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Q. If 5^(x-1) = 25, what is the value of x?

A. 2
B. 3
C. 4
D. 1

Solution

Since 25 = 5^2, we have 5^(x-1) = 5^2, thus x - 1 = 2, giving x = 3.

Correct Answer: A — 2

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Q. If 5^x = 125, what is the value of x?

A. 1
B. 2
C. 3
D. 4

Solution

125 = 5^3 => x = 3

Correct Answer: C — 3

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Q. If 5^x = 25, what is the value of x?

A. 1
B. 2
C. 3
D. 4

Solution

Since 25 = 5^2, we have 5^x = 5^2, thus x = 2.

Correct Answer: B — 2

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Q. If 7^(x) = 49, what is the value of x?

A. 1
B. 2
C. 3
D. 4

Solution

49 = 7^2, so x = 2.

Correct Answer: B — 2

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Q. If 8^(x) = 64, what is the value of x?

A. 1
B. 2
C. 3
D. 4

Solution

64 = 8^2, so x = 2.

Correct Answer: B — 2

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Showing 1441 to 1470 of 5000 (167 Pages)

Physics Syllabus (JEE Main) MCQ & Objective Questions

The Physics Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances problem-solving skills through practice. Engaging with MCQs and objective questions is essential for effective exam preparation, as it allows students to identify important questions and strengthen their knowledge base.

What You Will Practise Here

Mechanics: Laws of Motion, Work, Energy, and Power
Thermodynamics: Laws of Thermodynamics, Heat Transfer
Waves and Oscillations: Simple Harmonic Motion, Wave Properties
Electromagnetism: Electric Fields, Magnetic Fields, and Circuits
Optics: Reflection, Refraction, and Optical Instruments
Modern Physics: Quantum Theory, Atomic Models, and Nuclear Physics
Fluid Mechanics: Properties of Fluids, Bernoulli's Principle

Exam Relevance

The Physics Syllabus (JEE Main) is integral to various examinations, including CBSE, State Boards, and competitive exams like NEET and JEE. Questions often focus on conceptual understanding and application of theories. Common patterns include numerical problems, conceptual MCQs, and assertion-reason type questions, which test both knowledge and analytical skills.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers.
Neglecting units and dimensions in calculations.
Overlooking the significance of diagrams in understanding concepts.
Confusing similar concepts, such as velocity and acceleration.
Failing to apply formulas correctly in different contexts.

FAQs

Question: What are the key topics in the Physics Syllabus for JEE Main?
Answer: Key topics include Mechanics, Thermodynamics, Waves, Electromagnetism, Optics, Modern Physics, and Fluid Mechanics.

Question: How can I improve my performance in Physics MCQs?
Answer: Regular practice of MCQs, understanding concepts deeply, and revising important formulas can significantly enhance your performance.

Start solving practice MCQs today to test your understanding of the Physics Syllabus (JEE Main). This will not only boost your confidence but also prepare you effectively for your upcoming exams. Remember, consistent practice is the key to success!

Physics Syllabus (JEE Main)

Physics Syllabus (JEE Main) MCQ & Objective Questions

What You Will Practise Here

Exam Relevance

Common Mistakes Students Make

FAQs

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