JEE Main Preparation Resources for Competitive Exams

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JEE Main MCQ & Objective Questions

The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.

What You Will Practise Here

Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs

Exam Relevance

The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests

FAQs

Question: How can I improve my speed in solving JEE Main MCQ questions?
Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.

Question: Are the JEE Main objective questions similar to previous years' papers?
Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.

Question: What is the best way to approach JEE Main practice questions?
Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.

Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.

Chemistry Syllabus (JEE Main) Mathematics Syllabus (JEE Main) Physics Syllabus (JEE Main)

Q. A wire of length L and cross-sectional area A is stretched by a force F. What is the expression for the elongation ΔL?

A. ΔL = FL / (AE)
B. ΔL = AE / (FL)
C. ΔL = EFL / A
D. ΔL = A / (FL)

Solution

The elongation ΔL of a wire is given by ΔL = FL / (AE), where E is Young's modulus.

Correct Answer: A — ΔL = FL / (AE)

Q. A wire of length L and cross-sectional area A is stretched by a force F. What is the expression for the elongation of the wire?

A. ΔL = (F * L) / (A * Y)
B. ΔL = (Y * F) / (A * L)
C. ΔL = (A * Y) / (F * L)
D. ΔL = (F * A) / (Y * L)

Solution

The elongation ΔL of a wire is given by ΔL = (F * L) / (A * Y), where Y is Young's modulus.

Correct Answer: A — ΔL = (F * L) / (A * Y)

Q. According to Ampere's Law, the line integral of the magnetic field B around a closed loop is equal to what?

A. 0
B. μ₀ times the total current through the loop
C. μ₀ times the total charge
D. None of the above

Solution

Ampere's Law states ∮B·dl = μ₀I_enc, where I_enc is the enclosed current.

Correct Answer: B — μ₀ times the total current through the loop

Q. According to Ampere's Law, the line integral of the magnetic field B around a closed path is equal to what?

A. Zero
B. The product of permeability and current
C. The product of permittivity and charge
D. The electric field times the area

Solution

Ampere's Law states that the line integral of the magnetic field B around a closed path is equal to μ₀ times the total current I enclosed by the path.

Correct Answer: B — The product of permeability and current

Q. According to Ampere's Law, what is the line integral of the magnetic field around a closed loop equal to?

A. 0
B. μ₀ times the total current through the loop
C. μ₀ times the total charge
D. None of the above

Solution

Ampere's Law states that the line integral of B around a closed loop is μ₀ times the total current through the loop.

Correct Answer: B — μ₀ times the total current through the loop

Q. According to Ampere's Law, what is the magnetic field inside a long straight conductor carrying current I?

A. Zero
B. μ₀I/2πr
C. μ₀I/4πr
D. μ₀I/πr

Solution

Inside a long straight conductor, the magnetic field is zero because the contributions from all parts of the conductor cancel out.

Correct Answer: A — Zero

Q. According to Boyle's law, if the volume of a gas is doubled at constant temperature, what happens to the pressure?

A. It doubles
B. It halves
C. It remains constant
D. It quadruples

Solution

Boyle's law states that pressure is inversely proportional to volume at constant temperature, so if the volume is doubled, the pressure halves.

Correct Answer: B — It halves

Q. According to Boyle's law, if the volume of a gas is doubled, what happens to its pressure?

A. It doubles
B. It halves
C. It remains constant
D. It quadruples

Solution

Boyle's law states that pressure is inversely proportional to volume at constant temperature, so if volume is doubled, pressure is halved.

Correct Answer: B — It halves

Q. According to Charles's Law, how does the volume of a gas change with temperature at constant pressure?

A. V ∝ T
B. V ∝ 1/T
C. V + T = constant
D. VT = constant

Solution

Charles's Law states that the volume of a gas is directly proportional to its absolute temperature at constant pressure, expressed as V ∝ T.

Correct Answer: A — V ∝ T

Q. According to Charles's Law, what happens to the volume of a gas when the temperature increases at constant pressure?

A. Volume decreases
B. Volume remains constant
C. Volume increases
D. Volume becomes zero

Solution

Charles's Law states that the volume of a gas is directly proportional to its absolute temperature at constant pressure, meaning that as temperature increases, volume also increases.

Correct Answer: C — Volume increases

Q. According to Faraday's law, the induced EMF in a circuit is directly proportional to what?

A. The rate of change of magnetic flux
B. The strength of the magnetic field
C. The resistance of the circuit
D. The length of the conductor

Solution

Faraday's law states that the induced EMF is directly proportional to the rate of change of magnetic flux through the circuit.

Correct Answer: A — The rate of change of magnetic flux

Q. According to Faraday's law, the induced EMF in a circuit is proportional to what?

A. The rate of change of magnetic flux
B. The strength of the magnetic field
C. The resistance of the circuit
D. The length of the conductor

Solution

Faraday's law states that the induced EMF is directly proportional to the rate of change of magnetic flux through the circuit.

Correct Answer: A — The rate of change of magnetic flux

Q. According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to what?

A. Molar mass
B. Temperature
C. Pressure
D. Volume

Solution

Graham's law states that the rate of effusion is inversely proportional to the square root of the molar mass of the gas.

Correct Answer: A — Molar mass

Q. According to Kirchhoff's Current Law, if three currents enter a junction as 2A, 3A, and 4A, what is the total current leaving the junction?

A. 1A
B. 3A
C. 5A
D. 9A

Solution

According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving it. Total entering = 2A + 3A + 4A = 9A.

Correct Answer: D — 9A

Q. According to Kirchhoff's Current Law, if three currents enter a junction as 2A, 3A, and 4A, what is the current leaving the junction?

A. 1A
B. 3A
C. 5A
D. 9A

Solution

According to Kirchhoff's Current Law, the sum of currents entering a junction equals the sum of currents leaving. Therefore, I_out = 2A + 3A + 4A = 9A.

Correct Answer: D — 9A

Q. According to Kirchhoff's Current Law, if three currents enter a junction as 2A, 3A, and 1A, what is the total current leaving the junction?

A. 6A
B. 5A
C. 4A
D. 3A

Solution

According to Kirchhoff's Current Law, total current entering = total current leaving. 2A + 3A + 1A = 6A.

Correct Answer: B — 5A

Q. According to Kirchhoff's Current Law, if three currents entering a junction are 2A, 3A, and 5A, what is the total current leaving the junction?

A. 10A
B. 5A
C. 3A
D. 2A

Solution

According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving it. Therefore, total current leaving = 2A + 3A + 5A = 10A.

Correct Answer: A — 10A

Q. According to Kirchhoff's Voltage Law, the sum of the potential differences around any closed loop in a circuit is equal to what?

A. Zero
B. The total current
C. The total resistance
D. The total power

Solution

Kirchhoff's Voltage Law states that the sum of the electromotive forces and potential differences in any closed loop is zero.

Correct Answer: A — Zero

Q. According to Kirchhoff's Voltage Law, the sum of the potential differences around any closed loop in a circuit must equal what?

A. Zero
B. The total current
C. The total resistance
D. The total power

Solution

Kirchhoff's Voltage Law states that the sum of the electrical potential differences (voltage) around any closed circuit is zero.

Correct Answer: A — Zero

Q. According to Newton's third law, if object A exerts a force on object B, what does object B do?

A. Exerts a greater force on A
B. Exerts an equal and opposite force on A
C. Exerts no force
D. Exerts a lesser force on A

Solution

Newton's third law states that for every action, there is an equal and opposite reaction.

Correct Answer: B — Exerts an equal and opposite force on A

Q. According to the Biot-Savart Law, the magnetic field dB at a point due to a current element Idl is proportional to which of the following?

A. Idl
B. sin(θ)
C. 1/r^2
D. Both Idl and sin(θ)

Solution

The magnetic field dB is proportional to Idl and sin(θ), where θ is the angle between the current element and the line connecting the current element to the point of interest.

Correct Answer: D — Both Idl and sin(θ)

Q. According to the ideal gas law, which of the following is the correct equation?

A. PV = nRT
B. PV = nR
C. P = nRT/V
D. V = nP/RT

Solution

The ideal gas law is represented by the equation PV = nRT.

Correct Answer: A — PV = nRT

Q. According to the kinetic molecular theory, which of the following statements is true?

A. Gas particles have significant volume.
B. Gas particles are in constant motion.
C. Gas particles attract each other.
D. Gas particles do not collide.

Solution

According to the kinetic molecular theory, gas particles are in constant motion.

Correct Answer: B — Gas particles are in constant motion.

Q. According to the kinetic theory of gases, the pressure exerted by a gas is due to:

A. the gravitational force on the gas
B. the collisions of gas molecules with the walls of the container
C. the temperature of the gas
D. the volume of the gas

Solution

The pressure exerted by a gas is due to the collisions of gas molecules with the walls of the container, which transfers momentum to the walls.

Correct Answer: B — the collisions of gas molecules with the walls of the container

Q. According to the kinetic theory, the pressure exerted by a gas is due to which of the following?

A. The weight of the gas molecules.
B. The collisions of gas molecules with the walls of the container.
C. The temperature of the gas.
D. The volume of the gas.

Solution

The pressure of a gas is caused by the collisions of gas molecules with the walls of the container, which exert force on the walls.

Correct Answer: B — The collisions of gas molecules with the walls of the container.

Q. According to the kinetic theory, the pressure exerted by a gas is due to:

A. Gravitational force
B. Molecular collisions with the walls
C. Temperature of the gas
D. Volume of the gas

Solution

The pressure exerted by a gas is due to the collisions of gas molecules with the walls of the container.

Correct Answer: B — Molecular collisions with the walls

Q. According to VSEPR theory, what is the shape of the molecule with the formula AX2E2?

A. Linear
B. Bent
C. Trigonal planar
D. Tetrahedral

Solution

AX2E2 indicates two bonding pairs and two lone pairs, resulting in a bent shape.

Correct Answer: B — Bent

Q. An object is dropped from a height of 80 m. How long will it take to reach the ground? (Assume g = 10 m/s²)

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Using the formula: h = 0.5 * g * t². 80 = 0.5 * 10 * t². Solving gives t² = 16, so t = 4 s.

Correct Answer: B — 5 s

Q. An object is dropped from a height of 80 m. How long will it take to reach the ground?

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Using the formula: h = 0.5 * g * t², where h = 80 m and g = 9.8 m/s². Solving for t gives t = sqrt(2h/g) = sqrt(2*80/9.8) ≈ 4.04 s, approximately 4 s.

Correct Answer: B — 5 s

Q. An object is in equilibrium. If two forces of 10 N and 15 N act on it in opposite directions, what is the net force?

A. 5 N
B. 10 N
C. 15 N
D. 0 N

Solution

In equilibrium, the net force is zero. The forces cancel each other out: 15 N - 10 N = 5 N.

Correct Answer: A — 5 N

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