To find the sum of the coefficients, substitute x = 1: (2*1 - 3)^4 = (-1)^4 = 1. The sum of coefficients is 81.

The sum of the coefficients in the expansion of (x + 1)^4 is (1 + 1)^4 = 2^4 = 16.

The sum of the coefficients in the expansion of (x + 1)^n is given by (1 + 1)^n = 2^n. Here, n=8, so the sum is 2^8 = 256.

To find the sum, we add the real parts and the imaginary parts: (2 + 3) + (2 - 4)i = 5 - 2i.

The sum of two complex numbers z1 + z2 = (2 + 3i) + (4 - 2i) = (2 + 4) + (3 - 2)i = 6 + i.

Sum of interior angles = (n-2) * 180° = (6-2) * 180° = 720 degrees

The sum of the interior angles of any triangle is always 180 degrees.

The sum of the interior angles of any triangle is always 180 degrees.

Using Vieta's formulas, the sum of the roots is -(-8)/2 = 4.

The sum of the roots is given by -b/a = 5/1 = 5.

The sum of the squares of the roots is given by (sum of roots)^2 - 2(product of roots). Here, sum = 5, product = 6. So, 5^2 - 2*6 = 25 - 12 = 13.

The trace of a matrix is the sum of its diagonal elements. For matrix A, the trace is 3 + 4 = 7.

The trace of a matrix is the sum of its diagonal elements. For matrix A, the trace is a + d.

The trace of a matrix is the sum of its diagonal elements. For the matrix [[a, b], [c, d]], the trace is a + d.

The trace of a matrix is defined as the sum of the elements on the main diagonal.

The trace of a square matrix is defined as the sum of the elements on its main diagonal.

The trace of a matrix is the sum of its diagonal elements. Here, trace(H) = 2 + 3 + 4 = 9.

The trace of a matrix is the sum of its diagonal elements. Here, trace(H) = 2 + 3 = 5.

The trace of a matrix is the sum of its diagonal elements. Here, trace(I) = 3 + 4 = 7.

The trace of a matrix is the sum of its diagonal elements. Thus, trace(I) = 5 + 4 = 9.

Unit vector = A / |A| = (4i + 3j) / √(4^2 + 3^2) = (4i + 3j) / 5 = (4/5)i + (3/5)j.

Using the binomial theorem, (1 + 2)^5 = 3^5 = 243.

(1 + i)² = 1² + 2(1)(i) + i² = 1 + 2i - 1 = 2i.

To add the complex numbers, we combine the real parts and the imaginary parts: (2 + 4) + (3 - 2)i = 6 + 1i = 6 + i.

(2x + 3)(2x - 3) = 4x² - 9.

(2x + 3)² = 4x² + 12x + 9 by expanding the square of a binomial.

Convert 1/2 to 2/4, then (3/4) + (2/4) = 5/4.

(3x + 4)(3x - 4) = (3x)² - 4² = 9x² - 16.

(a + b)² - (a² + b²) = 2ab.

(a + b)² = a² + 2ab + b² by the expansion of the square of a binomial.