Q. In a reaction A → B, if the concentration of A decreases from 0.5 M to 0.1 M in 20 minutes, what is the average rate of reaction?
A.
0.02 M/min
B.
0.04 M/min
C.
0.05 M/min
D.
0.06 M/min
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Solution
Average rate = (change in concentration) / (time) = (0.5 - 0.1) / 20 = 0.02 M/min.
Correct Answer:
B
— 0.04 M/min
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Q. In a reaction A → B, if the concentration of A decreases from 0.8 M to 0.4 M in 20 minutes, what is the average rate of reaction? (2019)
A.
0.02 M/min
B.
0.04 M/min
C.
0.1 M/min
D.
0.05 M/min
Show solution
Solution
Average rate = Δ[A]/Δt = (0.8 - 0.4) / 20 = 0.02 M/min.
Correct Answer:
D
— 0.05 M/min
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Q. In a reaction A → B, if the rate of formation of B is 0.1 mol/L·s, what is the rate of disappearance of A?
A.
0.1 mol/L·s
B.
0.05 mol/L·s
C.
0.2 mol/L·s
D.
0.1 L/mol·s
Show solution
Solution
For the reaction A → B, the rate of disappearance of A is equal to the rate of formation of B, hence it is 0.1 mol/L·s. However, if stoichiometry is considered as 1:1, the rate of disappearance of A is also 0.1 mol/L·s.
Correct Answer:
C
— 0.2 mol/L·s
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Q. In a reaction A → B, if the rate of formation of B is 0.5 mol/L·s, what is the rate of disappearance of A?
A.
0.5 mol/L·s
B.
1.0 mol/L·s
C.
0.25 mol/L·s
D.
0.75 mol/L·s
Show solution
Solution
For the reaction A → B, the rate of disappearance of A is equal to the rate of formation of B, thus it is 1.0 mol/L·s.
Correct Answer:
B
— 1.0 mol/L·s
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Q. In a reaction A → B, if the rate of reaction doubles when the concentration of A is doubled, what is the order of the reaction with respect to A?
A.
Zero order
B.
First order
C.
Second order
D.
Third order
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Solution
If the rate doubles when the concentration of A is doubled, the reaction is first order with respect to A.
Correct Answer:
B
— First order
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Q. In a reaction at equilibrium, if the concentration of a reactant is decreased, what will happen?
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Increase the rate of reaction
Show solution
Solution
According to Le Chatelier's principle, decreasing the concentration of a reactant will shift the equilibrium to the left to produce more reactants.
Correct Answer:
B
— Shift to the left
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Q. In a reaction at equilibrium, if the concentration of a reactant is increased, what will happen to the equilibrium position? (2019)
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Depends on temperature
Show solution
Solution
Increasing the concentration of a reactant will shift the equilibrium position to the right, favoring the formation of products.
Correct Answer:
A
— Shift to the right
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Q. In a reaction at equilibrium, if the concentration of products increases, what will happen to the equilibrium position?
A.
Shift to the left
B.
Shift to the right
C.
No change
D.
Depends on temperature
Show solution
Solution
According to Le Chatelier's principle, if the concentration of products increases, the equilibrium will shift to the left.
Correct Answer:
A
— Shift to the left
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Q. In a reaction at equilibrium, if the concentration of products is decreased, what will happen?
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Depends on the temperature
Show solution
Solution
Decreasing the concentration of products will shift the equilibrium to the right to produce more products, according to Le Chatelier's principle.
Correct Answer:
A
— Shift to the right
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Q. In a reaction at equilibrium, if the concentration of products is increased, what will happen? (2022)
A.
Equilibrium shifts to the left
B.
Equilibrium shifts to the right
C.
No change
D.
Reaction stops
Show solution
Solution
According to Le Chatelier's principle, increasing the concentration of products will shift the equilibrium to the left, favoring the formation of reactants.
Correct Answer:
A
— Equilibrium shifts to the left
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Q. In a reaction at equilibrium, if the concentration of reactants is increased, what will happen to the equilibrium position?
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Depends on the reaction
Show solution
Solution
According to Le Chatelier's principle, increasing the concentration of reactants will shift the equilibrium position to the right to produce more products.
Correct Answer:
A
— Shift to the right
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Q. In a reaction at equilibrium, if the concentration of reactants is increased, what will happen to the equilibrium?
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Equilibrium constant increases
Show solution
Solution
According to Le Chatelier's principle, increasing the concentration of reactants will shift the equilibrium to the right to form more products.
Correct Answer:
A
— Shift to the right
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Q. In a reaction at equilibrium, if the concentration of reactants is increased, what will happen to the position of equilibrium? (2022)
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Depends on temperature
Show solution
Solution
According to Le Chatelier's principle, increasing the concentration of reactants will shift the equilibrium position to the right to produce more products.
Correct Answer:
A
— Shift to the right
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Q. In a reaction at equilibrium, if the concentration of reactants is increased, what will happen? (2022)
A.
The equilibrium will shift to the right.
B.
The equilibrium will shift to the left.
C.
The equilibrium will not change.
D.
The reaction will stop.
Show solution
Solution
According to Le Chatelier's principle, if the concentration of reactants is increased, the equilibrium will shift to the right to produce more products.
Correct Answer:
A
— The equilibrium will shift to the right.
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Q. In a reaction at equilibrium, if the temperature is decreased, what will happen to the equilibrium position if the reaction is exothermic?
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Depends on the concentration
Show solution
Solution
For an exothermic reaction, decreasing the temperature shifts the equilibrium to the right, favoring the formation of products.
Correct Answer:
A
— Shift to the right
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Q. In a reaction at equilibrium, if the temperature is increased and the reaction is exothermic, what will happen to the equilibrium position?
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Equilibrium constant increases
Show solution
Solution
For an exothermic reaction, increasing the temperature shifts the equilibrium position to the left, favoring the reactants.
Correct Answer:
B
— Shift to the left
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Q. In a reaction at equilibrium, if the temperature is increased and the reaction is exothermic, what will happen? (2021)
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Increase in Kc
Show solution
Solution
For an exothermic reaction, increasing the temperature shifts the equilibrium to the left, favoring the reactants.
Correct Answer:
B
— Shift to the left
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Q. In a reaction at equilibrium, if the temperature is increased for an exothermic reaction, what will happen? (2022)
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Increase in pressure
Show solution
Solution
For an exothermic reaction, increasing the temperature shifts the equilibrium to the left, favoring the reactants.
Correct Answer:
B
— Shift to the left
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Q. In a reaction at equilibrium, if the temperature is increased, what will happen to the equilibrium constant Kc for an endothermic reaction?
A.
Increase
B.
Decrease
C.
No change
D.
Depends on concentration
Show solution
Solution
For an endothermic reaction, increasing temperature shifts the equilibrium to the right, increasing Kc.
Correct Answer:
A
— Increase
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Q. In a reaction mechanism, the slowest step is known as the:
A.
Rate-determining step
B.
Intermediate step
C.
Fast step
D.
Catalytic step
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Solution
The slowest step in a reaction mechanism is called the rate-determining step, as it controls the overall reaction rate.
Correct Answer:
A
— Rate-determining step
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Q. In a reaction mechanism, the slowest step is known as what?
A.
Rate-determining step
B.
Intermediate step
C.
Fast step
D.
Catalytic step
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Solution
The slowest step in a reaction mechanism is known as the rate-determining step.
Correct Answer:
A
— Rate-determining step
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Q. In a reaction mechanism, what is the term for the slowest step that determines the overall rate of the reaction? (2019)
A.
Intermediate
B.
Rate-determining step
C.
Catalyst
D.
Transition state
Show solution
Solution
The slowest step in a reaction mechanism that determines the overall rate of the reaction is called the rate-determining step.
Correct Answer:
B
— Rate-determining step
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Q. In a reaction where 2 moles of hydrogen react with 1 mole of oxygen, how many moles of water are produced?
A.
1 mole
B.
2 moles
C.
3 moles
D.
4 moles
Show solution
Solution
According to the balanced equation 2H2 + O2 → 2H2O, 2 moles of H2 produce 2 moles of H2O.
Correct Answer:
B
— 2 moles
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Q. In a reaction where ΔH is negative and ΔS is positive, what can be said about ΔG?
A.
ΔG is always negative.
B.
ΔG is always positive.
C.
ΔG is zero.
D.
ΔG depends on temperature.
Show solution
Solution
If ΔH is negative and ΔS is positive, ΔG will always be negative at all temperatures.
Correct Answer:
A
— ΔG is always negative.
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Q. In a reaction where ΔH is positive and ΔS is negative, what is the sign of ΔG at high temperatures?
A.
Positive
B.
Negative
C.
Zero
D.
Cannot be determined
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Solution
At high temperatures, ΔG will be positive because the positive ΔH and negative ΔS will dominate the equation ΔG = ΔH - TΔS.
Correct Answer:
A
— Positive
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Q. In a reaction, 2 moles of hydrogen gas react with 1 mole of oxygen gas to form water. How many grams of water are produced? (2020)
A.
18 g
B.
36 g
C.
9 g
D.
27 g
Show solution
Solution
2H2 + O2 → 2H2O. 1 mole of water weighs 18 g, so 2 moles produce 36 g. Thus, 18 g of water is produced from 1 mole of O2.
Correct Answer:
A
— 18 g
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Q. In a reaction, 2 moles of hydrogen react with 1 mole of oxygen to form water. How many grams of water are produced? (2020)
A.
18 g
B.
36 g
C.
9 g
D.
27 g
Show solution
Solution
2 moles of H2 and 1 mole of O2 produce 2 moles of H2O. The molar mass of water is 18 g/mol, so 2 moles produce 36 g.
Correct Answer:
A
— 18 g
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Q. In a reaction, 3 moles of A react with 2 moles of B to produce 4 moles of C. What is the mole ratio of A to C?
A.
3:4
B.
2:3
C.
4:3
D.
1:1
Show solution
Solution
The mole ratio of A to C is 3:4 based on the coefficients in the balanced equation.
Correct Answer:
A
— 3:4
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Q. In a reaction, if the concentration of reactant A is halved, and the rate constant remains the same, how does the rate change for a first-order reaction? (2021)
A.
Doubles
B.
Halves
C.
Remains the same
D.
Quadruples
Show solution
Solution
For a first-order reaction, if [A] is halved, the rate also halves.
Correct Answer:
B
— Halves
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Q. In a reaction, if the concentration of reactant A is halved, and the rate of reaction decreases to one-fourth, what is the order of the reaction? (2020)
A.
Zero
B.
First
C.
Second
D.
Third
Show solution
Solution
If the rate decreases to one-fourth when concentration is halved, the reaction is second-order.
Correct Answer:
C
— Second
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