Arithmetic Aptitude MCQ & Objective Questions
Arithmetic Aptitude is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your mathematical skills but also boosts your confidence in tackling objective questions. Regular practice with MCQs and practice questions helps you identify important questions and improves your exam preparation, ensuring you score better in your assessments.
What You Will Practise Here
Basic arithmetic operations: addition, subtraction, multiplication, and division
Fractions and decimals: conversion and operations
Percentage calculations: increase, decrease, and comparisons
Ratio and proportion: understanding and application
Averages: calculating and interpreting data
Simple and compound interest: formulas and problem-solving
Time, speed, and distance: concepts and related problems
Exam Relevance
Arithmetic Aptitude is a significant topic in various examinations, including CBSE, State Boards, NEET, and JEE. Students can expect questions that test their understanding of basic concepts, calculations, and problem-solving abilities. Common question patterns include direct application of formulas, word problems, and data interpretation, making it essential to practice thoroughly.
Common Mistakes Students Make
Misunderstanding the question requirements, leading to incorrect answers.
Overlooking the order of operations in complex calculations.
Confusing percentages with fractions, resulting in calculation errors.
Neglecting to convert units properly in time, speed, and distance problems.
Failing to apply the correct formula for interest calculations.
FAQs
Question: What are some effective strategies for solving Arithmetic Aptitude MCQs?Answer: Practice regularly, understand the underlying concepts, and familiarize yourself with different question types to enhance your speed and accuracy.
Question: How can I improve my speed in solving Arithmetic Aptitude questions?Answer: Time yourself while practicing and focus on shortcuts and tricks that can simplify calculations.
Start your journey towards mastering Arithmetic Aptitude today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. If a product is bought for $80 and sold for $100, what is the loss percentage?
A.
20%
B.
25%
C.
15%
D.
10%
Show solution
Solution
Loss = Cost Price - Selling Price = 80 - 100 = -20. Loss Percentage = (20/80) * 100 = 25%.
Correct Answer:
D
— 10%
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Q. If a product is marked at $150 and is sold at a 10% discount, what is the selling price?
A.
$135
B.
$140
C.
$145
D.
$150
Show solution
Solution
Selling price = 150 - (10/100 * 150) = 150 - 15 = 135.
Correct Answer:
A
— $135
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Q. If a product is marked at $150 and sold at a 10% discount, what is the selling price?
A.
$135
B.
$140
C.
$145
D.
$150
Show solution
Solution
Selling price = 150 - (10/100 * 150) = 150 - 15 = 135.
Correct Answer:
A
— $135
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Q. If a product is marked at $200 and is sold at a 10% discount, what is the selling price?
A.
$180
B.
$190
C.
$200
D.
$210
Show solution
Solution
Selling price = 200 - (0.1 * 200) = 200 - 20 = 180
Correct Answer:
A
— $180
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Q. If a product is marked at $200 and sold at a 10% discount, what is the selling price?
A.
$180
B.
$190
C.
$200
D.
$210
Show solution
Solution
Selling price = 200 - (0.10 * 200) = 200 - 20 = $180.
Correct Answer:
A
— $180
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Q. If a product is marked at $200 and sold at a 10% profit, what is the cost price?
A.
$150
B.
$160
C.
$180
D.
$190
Show solution
Solution
Let the cost price be x. Then, 1.1x = 200 => x = 200 / 1.1 = 181.82.
Correct Answer:
B
— $160
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Q. If a product is marked at $200 and sold at a discount of 10%, what is the selling price?
A.
$180
B.
$190
C.
$200
D.
$170
Show solution
Solution
Discount = 10% of 200 = 20. Selling Price = Marked Price - Discount = 200 - 20 = $180.
Correct Answer:
A
— $180
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Q. If a product is marked at $200 and sold at a discount of 15%, what is the selling price?
A.
$170
B.
$180
C.
$190
D.
$160
Show solution
Solution
Discount = 15% of 200 = 0.15 * 200 = $30. Selling Price = Marked Price - Discount = 200 - 30 = $170.
Correct Answer:
B
— $180
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Q. If a product is marked at $500 and sold at a discount of 20%, what is the selling price?
A.
$400
B.
$450
C.
$350
D.
$300
Show solution
Solution
Selling Price = Marked Price - Discount = 500 - (20% of 500) = 500 - 100 = $400.
Correct Answer:
B
— $450
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Q. If a product is sold for $120 after a 20% discount, what was the original price?
A.
$150
B.
$140
C.
$160
D.
$130
Show solution
Solution
Let the original price be x. Then, x - 0.2x = 120, 0.8x = 120, x = 120 / 0.8 = $150.
Correct Answer:
A
— $150
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Q. If a product is sold for $120 after a profit of 20%, what was the cost price?
A.
$90
B.
$100
C.
$110
D.
$80
Show solution
Solution
Let Cost Price = x. Selling Price = x + 20% of x = 1.2x. 1.2x = 120. x = 120/1.2 = 100.
Correct Answer:
B
— $100
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Q. If a product is sold for $120 at a profit of 20%, what was the cost price?
A.
$100
B.
$90
C.
$110
D.
$80
Show solution
Solution
Let Cost Price = x. Selling Price = x + 20% of x = 1.2x. 1.2x = 120. x = 120/1.2 = 100.
Correct Answer:
A
— $100
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Q. If a product is sold for $150 after a 25% discount, what was the original price?
A.
$175
B.
$180
C.
$200
D.
$250
Show solution
Solution
Let the original price be x. Then, 150 = x - 0.25x => 150 = 0.75x => x = 150/0.75 = $200.
Correct Answer:
A
— $175
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Q. If a product is sold for $150 after a discount of 25%, what was the marked price?
A.
$200
B.
$180
C.
$160
D.
$220
Show solution
Solution
Let the marked price be x. Then, selling price = x - 25% of x = 0.75x. Given selling price = $150, we have 0.75x = 150, x = 150 / 0.75 = $200.
Correct Answer:
A
— $200
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Q. If a product is sold for $240 after a profit of 20%, what was the cost price?
A.
$200
B.
$180
C.
$220
D.
$240
Show solution
Solution
Let CP = x. Then, 240 = x + 0.2x => 240 = 1.2x => x = 240/1.2 = $200.
Correct Answer:
A
— $200
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Q. If a product is sold for $300 after a discount of 20%, what was the original price?
A.
$360
B.
$320
C.
$300
D.
$280
Show solution
Solution
Let the original price be x. Then, x - 0.2x = 300 => 0.8x = 300 => x = 300 / 0.8 = 360.
Correct Answer:
A
— $360
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Q. If a product is sold for $600 at a profit of 20%, what was the cost price?
A.
$480
B.
$500
C.
$520
D.
$600
Show solution
Solution
Let Cost Price = x. Selling Price = x + 20% of x = 1.2x. 1.2x = 600. x = 600/1.2 = 500.
Correct Answer:
A
— $480
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Q. If a product is sold for $80 after a 20% discount, what was the original price?
A.
$100
B.
$90
C.
$80
D.
$70
Show solution
Solution
Let original price be x. 80 = x - (20/100)x. Solving gives x = $100.
Correct Answer:
A
— $100
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Q. If a product's price increases from $150 to $180, what is the percentage increase?
A.
20%
B.
15%
C.
25%
D.
30%
Show solution
Solution
Percentage increase = ((180 - 150) / 150) * 100 = 20%.
Correct Answer:
A
— 20%
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Q. If a product's price increases from $200 to $250, what is the percentage increase?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Percentage increase = ((250 - 200) / 200) * 100 = (50 / 200) * 100 = 25%.
Correct Answer:
B
— 25%
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Q. If a product's price increases from $50 to $60, what is the percentage increase?
A.
20%
B.
15%
C.
25%
D.
10%
Show solution
Solution
Percentage increase = ((60 - 50) / 50) * 100 = 20%.
Correct Answer:
A
— 20%
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Q. If a runner completes a 10 km race in 50 minutes, what is their speed in km/h?
A.
10 km/h
B.
12 km/h
C.
14 km/h
D.
15 km/h
Show solution
Solution
Speed = Distance / Time = 10 km / (50/60) h = 12 km/h.
Correct Answer:
B
— 12 km/h
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Q. If a runner completes a 400 m track in 50 seconds, what is his speed in km/h?
A.
7.2 km/h
B.
8 km/h
C.
9 km/h
D.
10 km/h
Show solution
Solution
Speed = Distance / Time = 400 m / 50 s = 8 m/s = 8 * 18/5 = 28.8 km/h.
Correct Answer:
A
— 7.2 km/h
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Q. If a runner completes a 400 m track in 50 seconds, what is his speed in m/s?
A.
6 m/s
B.
8 m/s
C.
7 m/s
D.
5 m/s
Show solution
Solution
Speed = Distance / Time = 400 m / 50 s = 8 m/s.
Correct Answer:
A
— 6 m/s
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Q. If a runner covers 300 meters in 45 seconds, what is his speed in km/h?
A.
4 km/h
B.
5 km/h
C.
6 km/h
D.
7 km/h
Show solution
Solution
Speed = distance/time = 300 m / 45 s = 6.67 m/s. In km/h = 6.67 * 18/5 = 24 km/h.
Correct Answer:
C
— 6 km/h
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Q. If a seller sells an item for $450 at a loss of 10%, what was the cost price?
A.
$500
B.
$550
C.
$600
D.
$450
Show solution
Solution
Let Cost Price = x. Selling Price = x - 10% of x = 0.9x. 0.9x = 450. x = 450/0.9 = 500.
Correct Answer:
A
— $500
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Q. If a shirt costs $40 after a 20% discount, what was the original price?
Show solution
Solution
Let the original price be x. Then, x - 0.2x = 40, so 0.8x = 40, thus x = 50.
Correct Answer:
A
— 50
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Q. If a shirt costs $40 and is on sale for 20% off, what is the sale price?
Show solution
Solution
20% of $40 = (20/100) * 40 = $8. Sale price = $40 - $8 = $32.
Correct Answer:
A
— 32
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Q. If a shirt costs $40 and is sold at a 20% discount, what is the selling price?
Show solution
Solution
Discount = 20% of 40 = 8. Selling price = 40 - 8 = 32.
Correct Answer:
B
— 36
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Q. If a shirt is sold for $240 after a discount of 20%, what was the original price of the shirt?
A.
$300
B.
$280
C.
$250
D.
$320
Show solution
Solution
Let the original price be x. After a 20% discount, the selling price is 80% of x. Therefore, 0.8x = 240; x = 240 / 0.8 = 300.
Correct Answer:
A
— $300
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