Q. What is the square root of 196?
Solution
The square root of 196 is 14, since 14 * 14 = 196.
Correct Answer:
C
— 14
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Q. What is the square root of 225?
Solution
The square root of 225 is 15, since 15 * 15 = 225.
Correct Answer:
C
— 15
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Q. What is the square root of 256?
Solution
The square root of 256 is 16, since 16 * 16 = 256.
Correct Answer:
C
— 16
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Q. What is the square root of 49?
Solution
The square root of 49 is 7, since 7 * 7 = 49.
Correct Answer:
B
— 7
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Q. What is the square root of 81?
Solution
The square root of 81 is 9, since 9 * 9 = 81.
Correct Answer:
B
— 9
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Q. What is the sum of the first 10 natural numbers?
Solution
The sum of the first n natural numbers is given by the formula n(n + 1)/2. For n = 10, the sum is 10(10 + 1)/2 = 10 * 11 / 2 = 55.
Correct Answer:
A
— 45
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Q. What is the surface area of a cube with a side length of 6 cm?
-
A.
36 cm²
-
B.
72 cm²
-
C.
144 cm²
-
D.
24 cm²
Solution
Surface Area = 6 * side² = 6 * 6² = 6 * 36 = 216 cm².
Correct Answer:
B
— 72 cm²
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Q. What is the surface area of a sphere with a diameter of 10 cm?
-
A.
100π cm²
-
B.
50π cm²
-
C.
25π cm²
-
D.
75π cm²
Solution
Surface Area = 4πr² = 4π(5)² = 4π(25) = 100π cm².
Correct Answer:
A
— 100π cm²
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Q. What is the time difference between 2:30 PM and 4:15 PM?
-
A.
1 hour 45 minutes
-
B.
1 hour 30 minutes
-
C.
2 hours 15 minutes
-
D.
2 hours 45 minutes
Solution
The time difference is 4:15 PM - 2:30 PM = 1 hour 45 minutes.
Correct Answer:
A
— 1 hour 45 minutes
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Q. What is the time shown on a clock if the angle between the hour and minute hands is 180 degrees?
-
A.
6:00
-
B.
3:00
-
C.
9:00
-
D.
12:00
Solution
At 6:00, the hour hand is at 180 degrees and the minute hand is at 0 degrees. The angle between them is 180 degrees.
Correct Answer:
A
— 6:00
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Q. What is the time shown on a clock if the hour hand is at 2 and the minute hand is at 6?
-
A.
2:30
-
B.
2:15
-
C.
2:45
-
D.
2:00
Solution
The minute hand at 6 indicates 30 minutes. Therefore, the time is 2:30.
Correct Answer:
C
— 2:45
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Q. What is the total amount after 2 years if $1000 is invested at a simple interest rate of 6% per annum?
-
A.
$1120
-
B.
$1160
-
C.
$1180
-
D.
$1200
Solution
Simple Interest = (1000 * 6 * 2) / 100 = $120. Total Amount = Principal + Interest = 1000 + 120 = $1120.
Correct Answer:
B
— $1160
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Q. What is the total amount after 5 years if $1000 is invested at a compound interest rate of 3% per annum?
-
A.
$1159.27
-
B.
$1200.00
-
C.
$1100.00
-
D.
$1050.00
Solution
Amount = P(1 + r/n)^(nt) = 1000(1 + 0.03/1)^(1*5) = 1000(1.159274) = 1159.27
Correct Answer:
A
— $1159.27
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Q. What is the total number of days from January 1, 2020 to December 31, 2020?
-
A.
365
-
B.
366
-
C.
364
-
D.
367
Solution
2020 is a leap year, so there are 366 days from January 1, 2020 to December 31, 2020.
Correct Answer:
B
— 366
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Q. What is the total percentage of expenses on R&D and Production combined?
-
A.
40%
-
B.
50%
-
C.
60%
-
D.
70%
Solution
R&D is 30% and Production is 30%, totaling 60%.
Correct Answer:
C
— 60%
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Q. What is the total population represented in the caselet?
-
A.
5000
-
B.
10000
-
C.
15000
-
D.
20000
Solution
The total population is 10000 as per the caselet data.
Correct Answer:
B
— 10000
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Q. What is the total sales for all products in Q2?
-
A.
3500
-
B.
4000
-
C.
4500
-
D.
5000
Solution
Total sales in Q2: Product A (1200) + Product B (900) + Product C (1500) + Product D (400) = 4000.
Correct Answer:
B
— 4000
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Q. What is the total sales for all products in Q4?
-
A.
$8000
-
B.
$9000
-
C.
$10000
-
D.
$11000
Solution
The total sales for all products in Q4 is $10000.
Correct Answer:
C
— $10000
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Q. What is the total sales for all products in the fourth quarter?
-
A.
$12000
-
B.
$15000
-
C.
$18000
-
D.
$20000
Solution
The total sales for all products in the fourth quarter is $15000 as shown in the bar chart.
Correct Answer:
B
— $15000
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Q. What is the total sales for Product A in Q1 and Q2 combined?
-
A.
$2000
-
B.
$3000
-
C.
$4000
-
D.
$5000
Solution
The total sales for Product A in Q1 is $1000 and in Q2 is $2000. Combined, they total $3000.
Correct Answer:
B
— $3000
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Q. What is the total sales for Product A in the first quarter according to the bar chart?
-
A.
$2000
-
B.
$3000
-
C.
$4000
-
D.
$5000
Solution
The bar for Product A in the first quarter shows a height corresponding to $3000.
Correct Answer:
B
— $3000
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Q. What is the total sales for Product A in the first quarter?
-
A.
$2000
-
B.
$3000
-
C.
$4000
-
D.
$5000
Solution
The bar chart shows that Product A had sales of $3000 in the first quarter.
Correct Answer:
B
— $3000
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Q. What is the total sales for Product B across all quarters?
-
A.
2400
-
B.
2600
-
C.
2800
-
D.
3000
Solution
Total sales for Product B: Q1 (600) + Q2 (900) + Q3 (800) + Q4 (1000) = 3300.
Correct Answer:
A
— 2400
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Q. What is the total sales of all products combined?
-
A.
1000
-
B.
1200
-
C.
1500
-
D.
1800
Solution
Total sales of all products combined is 1200 units.
Correct Answer:
B
— 1200
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Q. What is the total surface area of a cube with a side length of 6 cm?
-
A.
72 cm²
-
B.
144 cm²
-
C.
36 cm²
-
D.
48 cm²
Solution
Surface Area = 6 * side² = 6 * 6² = 6 * 36 = 216 cm².
Correct Answer:
B
— 144 cm²
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Q. What is the true discount on a bill of Rs. 10000 due in 1 year if the Banker's Discount is Rs. 1000?
-
A.
Rs. 900
-
B.
Rs. 1000
-
C.
Rs. 1100
-
D.
Rs. 800
Solution
True Discount = Banker's Discount × (Time / (Time + 1)) = 1000 × (1 / (1 + 1)) = Rs. 500.
Correct Answer:
A
— Rs. 900
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Q. What is the true discount on a bill of Rs. 30000 due in 2 years if the Banker's Discount is Rs. 3000?
-
A.
Rs. 2500
-
B.
Rs. 3000
-
C.
Rs. 3500
-
D.
Rs. 2000
Solution
True Discount = Banker's Discount × (Time / (Time + 1)) = 3000 × (2 / (2 + 1)) = Rs. 2000.
Correct Answer:
A
— Rs. 2500
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Q. What is the true discount on a bill of Rs. 5000 due in 3 months if the Banker's Discount is Rs. 125?
-
A.
Rs. 100
-
B.
Rs. 125
-
C.
Rs. 150
-
D.
Rs. 200
Solution
True Discount = Banker's Discount * (Time / (Time + 1)) = 125 * (3/12) = Rs. 31.25.
Correct Answer:
A
— Rs. 100
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Q. What is the value of (3^4) / (3^2)?
-
A.
3^2
-
B.
3^1
-
C.
3^3
-
D.
3^4
Solution
Using the property of indices, a^m / a^n = a^(m-n), we have (3^4) / (3^2) = 3^(4-2) = 3^2.
Correct Answer:
A
— 3^2
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Q. What is the value of (4^3) * (4^-1)?
-
A.
4^2
-
B.
4^3
-
C.
4^1
-
D.
4^0
Solution
Using the property of indices, a^m * a^n = a^(m+n), we have (4^3) * (4^-1) = 4^(3-1) = 4^2.
Correct Answer:
A
— 4^2
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Showing 1381 to 1410 of 1482 (50 Pages)
