Arithmetic Aptitude for Competitive Exam Success

Arithmetic Aptitude

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Q. What is the value of (4^3) * (4^-1)?

A. 4^2
B. 4^3
C. 4^1
D. 4^0

Solution

Using the property of indices, a^m * a^n = a^(m+n), we have (4^3) * (4^-1) = 4^(3-1) = 4^2.

Correct Answer: A — 4^2

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Q. What is the value of (4^3) * (4^2)?

A. 4^5
B. 4^6
C. 4^4
D. 4^7

Solution

Using the property of indices, a^m * a^n = a^(m+n), we have (4^3) * (4^2) = 4^(3+2) = 4^5.

Correct Answer: A — 4^5

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Q. What is the value of (7^0) + (7^1)?

A. 0
B. 1
C. 7
D. 8

Solution

Using the property that any number raised to the power of 0 is 1, we have 7^0 = 1 and 7^1 = 7, thus 1 + 7 = 8.

Correct Answer: D — 8

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Q. What is the value of (7^3) * (7^-2)?

A. 7^1
B. 7^0
C. 7^2
D. 7^3

Solution

Using the property of indices, a^m * a^n = a^(m+n). Here, 7^3 * 7^-2 = 7^(3-2) = 7^1.

Correct Answer: A — 7^1

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Q. What is the value of (x^2) * (x^3) / (x^4)?

A. x^1
B. x^0
C. x^2
D. x^3

Solution

Using the property of indices, we have (x^2 * x^3) / x^4 = x^(2+3-4) = x^1.

Correct Answer: A — x^1

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Q. What is the value of (x^3) / (x^2) when x = 2?

A. 2
B. 4
C. 8
D. 16

Solution

Using the property of indices, (x^3) / (x^2) = x^(3-2) = x^1. When x = 2, it equals 2.

Correct Answer: A — 2

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Q. What is the value of 7^2 + 3^2?

A. 58
B. 62
C. 70
D. 74

Solution

Calculating 7^2 = 49 and 3^2 = 9. Therefore, 49 + 9 = 58.

Correct Answer: A — 58

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Q. What is the value of log10(0.01)?

A. -1
B. -2
C. 0
D. 1

Solution

log10(0.01) = log10(10^-2) = -2.

Correct Answer: B — -2

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Q. What is the value of log10(1)?

A. 0
B. 1
C. -1
D. undefined

Solution

log10(1) = 0 because 10^0 = 1.

Correct Answer: A — 0

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Q. What is the value of log10(100)?

A. 1
B. 2
C. 3
D. 0

Solution

log10(100) = 2 because 10^2 = 100.

Correct Answer: B — 2

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Q. What is the value of log10(1000)?

A. 1
B. 2
C. 3
D. 4

Solution

log10(1000) = log10(10^3) = 3.

Correct Answer: C — 3

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Q. What is the value of log10(50) approximately?

A. 1.5
B. 1.7
C. 1.9
D. 2.0

Solution

log10(50) is approximately 1.7.

Correct Answer: B — 1.7

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Q. What is the value of log2(1/8)?

A. -2
B. -3
C. -4
D. -5

Solution

1/8 = 2^-3, so log2(1/8) = -3.

Correct Answer: B — -3

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Q. What is the value of log2(16)?

A. 2
B. 3
C. 4
D. 5

Solution

log2(16) = 4, since 2^4 = 16.

Correct Answer: C — 4

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Q. What is the value of log2(32)?

A. 4
B. 5
C. 6
D. 7

Solution

log2(32) = log2(2^5) = 5.

Correct Answer: B — 5

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Q. What is the value of log2(8) + log2(4)?

A. 3
B. 4
C. 5
D. 6

Solution

log2(8) = 3 and log2(4) = 2, so 3 + 2 = 5.

Correct Answer: B — 4

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Q. What is the value of log3(81)?

A. 2
B. 3
C. 4
D. 5

Solution

log3(81) = log3(3^4) = 4.

Correct Answer: C — 4

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Q. What is the value of log4(16)?

A. 1
B. 2
C. 3
D. 4

Solution

log4(16) = log4(4^2) = 2.

Correct Answer: B — 2

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Q. What is the value of log5(25)?

A. 1
B. 2
C. 3
D. 4

Solution

log5(25) = log5(5^2) = 2.

Correct Answer: B — 2

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Q. What is the value of log7(49)?

A. 1
B. 2
C. 3
D. 4

Solution

log7(49) = log7(7^2) = 2.

Correct Answer: B — 2

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Q. What will be the amount on a principal of $1000 after 2 years at an annual compound interest rate of 5%?

A. $1102.50
B. $1050.00
C. $1200.00
D. $1150.00

Solution

Amount = P(1 + r)^n = 1000(1 + 0.05)^2 = 1000(1.1025) = $1102.50

Correct Answer: A — $1102.50

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Q. What will be the compound interest on $1500 for 4 years at a rate of 10% per annum?

A. $600
B. $700
C. $800
D. $900

Solution

CI = A - P; A = P(1 + r)^n = 1500(1 + 0.10)^4 = 1500(1.4641) = $2196.15, CI = 2196.15 - 1500 = $696.15.

Correct Answer: C — $800

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Q. What will be the compound interest on $2500 at a rate of 7% per annum for 3 years?

A. $577.50
B. $600.00
C. $550.00
D. $525.00

Solution

Compound Interest = 2500(1 + 0.07)^3 - 2500 = 2500(1.225043) - 2500 = 3062.61 - 2500 = 577.50

Correct Answer: A — $577.50

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Q. What will be the compound interest on $4000 at an annual interest rate of 9% for 2 years?

A. $720.00
B. $800.00
C. $900.00
D. $850.00

Solution

Compound Interest = 4000(1 + 0.09)^2 - 4000 = 4000(1.1881) - 4000 = 752.40

Correct Answer: B — $800.00

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Q. What will be the compound interest on $8000 at an interest rate of 5% per annum for 2 years?

A. $816.00
B. $800.00
C. $850.00
D. $900.00

Solution

Compound Interest = P(1 + r/n)^(nt) - P = 8000(1 + 0.05/1)^(1*2) - 8000 = 8000(1.1025) - 8000 = 816.00

Correct Answer: A — $816.00

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Q. What will be the compound interest on an amount of $2000 at an annual interest rate of 5% for 3 years?

A. $315.25
B. $300.00
C. $250.00
D. $200.00

Solution

Compound Interest = P(1 + r/n)^(nt) - P = 2000(1 + 0.05/1)^(1*3) - 2000 = 2000(1.157625) - 2000 = 315.25

Correct Answer: A — $315.25

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Q. What will be the simple interest on a principal of $2500 at a rate of 8% per annum for 4 years?

A. $600
B. $800
C. $700
D. $500

Solution

Simple Interest = (2500 * 8 * 4) / 100 = $800.

Correct Answer: C — $700

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Q. What will be the total amount after 4 years if $1000 is invested at a simple interest rate of 6% per annum?

A. $1200
B. $1400
C. $1600
D. $1800

Solution

Total Amount = Principal + Simple Interest = 1000 + (1000 × 6 × 4 / 100) = $1240.

Correct Answer: B — $1400

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Q. Which decimal represents 7/10?

A. 0.5
B. 0.7
C. 0.8
D. 0.9

Solution

7/10 equals 0.7.

Correct Answer: B — 0.7

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Q. Which number does not belong: 25%, 50%, 75%, 80%, 100%?

A. 25%
B. 50%
C. 75%
D. 80%

Solution

80% is the odd one out as it does not fit the pattern of multiples of 25%.

Correct Answer: D — 80%

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Arithmetic Aptitude

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