Arithmetic Aptitude MCQ & Objective Questions
Arithmetic Aptitude is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your mathematical skills but also boosts your confidence in tackling objective questions. Regular practice with MCQs and practice questions helps you identify important questions and improves your exam preparation, ensuring you score better in your assessments.
What You Will Practise Here
Basic arithmetic operations: addition, subtraction, multiplication, and division
Fractions and decimals: conversion and operations
Percentage calculations: increase, decrease, and comparisons
Ratio and proportion: understanding and application
Averages: calculating and interpreting data
Simple and compound interest: formulas and problem-solving
Time, speed, and distance: concepts and related problems
Exam Relevance
Arithmetic Aptitude is a significant topic in various examinations, including CBSE, State Boards, NEET, and JEE. Students can expect questions that test their understanding of basic concepts, calculations, and problem-solving abilities. Common question patterns include direct application of formulas, word problems, and data interpretation, making it essential to practice thoroughly.
Common Mistakes Students Make
Misunderstanding the question requirements, leading to incorrect answers.
Overlooking the order of operations in complex calculations.
Confusing percentages with fractions, resulting in calculation errors.
Neglecting to convert units properly in time, speed, and distance problems.
Failing to apply the correct formula for interest calculations.
FAQs
Question: What are some effective strategies for solving Arithmetic Aptitude MCQs?Answer: Practice regularly, understand the underlying concepts, and familiarize yourself with different question types to enhance your speed and accuracy.
Question: How can I improve my speed in solving Arithmetic Aptitude questions?Answer: Time yourself while practicing and focus on shortcuts and tricks that can simplify calculations.
Start your journey towards mastering Arithmetic Aptitude today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. If a person earns a profit of 20% on a calendar that costs $50, what is the selling price?
A.
$60
B.
$70
C.
$50
D.
$40
Show solution
Solution
Selling Price = Cost Price + Profit = 50 + (20% of 50) = 50 + 10 = $60
Correct Answer:
A
— $60
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Q. If a person earns a profit of 20% on selling a watch for $120, what was the cost price of the watch?
A.
$100
B.
$110
C.
$90
D.
$80
Show solution
Solution
Let the cost price be x. Then, 120 = x + 0.2x => 120 = 1.2x => x = 120/1.2 = $100.
Correct Answer:
A
— $100
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Q. If a person invests $1000 at a rate of 5% per annum simple interest, how much interest will he earn in 3 years?
A.
$150
B.
$100
C.
$50
D.
$75
Show solution
Solution
Simple Interest = Principal * Rate * Time = 1000 * 5/100 * 3 = $150.
Correct Answer:
B
— $100
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Q. If a person invests $1000 at a simple interest rate of 5% per annum, how much interest will he earn in 3 years?
A.
$150
B.
$100
C.
$50
D.
$75
Show solution
Solution
Simple Interest = Principal * Rate * Time = 1000 * 5/100 * 3 = $150.
Correct Answer:
B
— $100
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Q. If a person invests $1000 at an annual interest rate of 5% for 3 years, what will be the total amount at the end of 3 years using simple interest?
A.
$1150
B.
$1200
C.
$1050
D.
$1100
Show solution
Solution
Simple Interest = Principal × Rate × Time = 1000 × 0.05 × 3 = $150. Total Amount = Principal + Interest = 1000 + 150 = $1150.
Correct Answer:
A
— $1150
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Q. If a person invests $1000 at an interest rate of 5% per annum, how much interest will he earn in 3 years under compound interest?
A.
$150
B.
$157.63
C.
$160
D.
$165
Show solution
Solution
Amount = P(1 + r/n)^(nt) = 1000(1 + 0.05)^3 = 1000(1.157625) = $1157.63. Interest = $1157.63 - $1000 = $157.63.
Correct Answer:
B
— $157.63
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Q. If a person invests $1000 at an interest rate of 5% per annum, how much interest will he earn in 3 years (simple interest)?
A.
150
B.
100
C.
200
D.
250
Show solution
Solution
Simple Interest = PRT = 1000 * 5/100 * 3 = 150.
Correct Answer:
B
— 100
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Q. If a person invests $1000 in shares at a compound interest rate of 5% per annum, what will be the amount after 2 years?
A.
$1102.50
B.
$1050.00
C.
$1200.00
D.
$1150.00
Show solution
Solution
Amount = Principal * (1 + Rate/100)^Time = 1000 * (1 + 5/100)^2 = 1000 * 1.1025 = $1102.50
Correct Answer:
A
— $1102.50
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Q. If a person invests $2000 at a compound interest rate of 5% per annum, what will be the amount after 2 years?
A.
$2205
B.
$2100
C.
$2150
D.
$2250
Show solution
Solution
Amount = Principal * (1 + Rate)^Time = 2000 * (1 + 0.05)^2 = 2000 * 1.1025 = $2205
Correct Answer:
A
— $2205
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Q. If a person invests $2000 at a rate of 5% per annum simple interest, how much interest will he earn in 3 years?
A.
$300
B.
$200
C.
$150
D.
$100
Show solution
Solution
Simple Interest = Principal × Rate × Time / 100 = 2000 × 5 × 3 / 100 = $300.
Correct Answer:
A
— $300
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Q. If a person invests $2000 at an interest rate of 5% per annum, how much interest will he earn in 3 years?
A.
300
B.
200
C.
150
D.
250
Show solution
Solution
Simple interest = Principal * Rate * Time = 2000 * 0.05 * 3 = $300.
Correct Answer:
A
— 300
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Q. If a person invests $2500 at a simple interest rate of 12% per annum, how much interest will he earn in 4 years?
A.
$1200
B.
$1000
C.
$800
D.
$600
Show solution
Solution
Simple Interest = 2500 × 12 × 4 / 100 = $1200
Correct Answer:
B
— $1000
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Q. If a person invests $2500 at a simple interest rate of 3% per annum, how much interest will he earn in 4 years?
A.
$300
B.
$200
C.
$150
D.
$100
Show solution
Solution
Simple Interest = Principal × Rate × Time / 100 = 2500 × 3 × 4 / 100 = $300
Correct Answer:
B
— $200
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Q. If a person invests $2500 at a simple interest rate of 7% per annum, how much interest will he earn in 6 years?
A.
$700
B.
$800
C.
$900
D.
$1000
Show solution
Solution
Simple Interest = 2500 × 7 × 6 / 100 = $1050.
Correct Answer:
B
— $800
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Q. If a person invests $2500 at a simple interest rate of 8% per annum, how much interest will he earn in 6 years?
A.
$1200
B.
$1000
C.
$800
D.
$600
Show solution
Solution
Simple Interest = 2500 × 8 × 6 / 100 = $1200.
Correct Answer:
B
— $1000
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Q. If a person invests $3000 at a simple interest rate of 7% per annum, how much interest will he earn in 6 years?
A.
$1260
B.
$1440
C.
$1500
D.
$1800
Show solution
Solution
Simple Interest = (3000 × 7 × 6) / 100 = $1260.
Correct Answer:
A
— $1260
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Q. If a person invests $500 at a compound interest rate of 4% per annum for 2 years, what will be the total amount?
A.
$520.80
B.
$540.80
C.
$550.00
D.
$560.00
Show solution
Solution
Total Amount = P(1 + r/n)^(nt) = 500(1 + 0.04)^2 = 500 * 1.0816 = $540.80.
Correct Answer:
B
— $540.80
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Q. If a person invests $800 at a simple interest rate of 7% per annum, how much interest will he earn in 2 years?
A.
$100
B.
$112
C.
$120
D.
$140
Show solution
Solution
Simple Interest = (800 * 7 * 2) / 100 = $112.
Correct Answer:
B
— $112
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Q. If a person is 20 meters away from a tree and the angle of elevation to the top of the tree is 45 degrees, what is the height of the tree?
A.
10 meters
B.
20 meters
C.
30 meters
D.
40 meters
Show solution
Solution
Height = distance * tan(angle) = 20 * 1 = 20 meters.
Correct Answer:
B
— 20 meters
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Q. If a person is 25 years old now, how old will he be in 5 years?
Show solution
Solution
In 5 years, the person will be 25 + 5 = 30 years old.
Correct Answer:
B
— 30
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Q. If a person is standing 15 meters away from a building and the angle of elevation to the top of the building is 30 degrees, what is the height of the building?
A.
7.5 meters
B.
10 meters
C.
12.5 meters
D.
15 meters
Show solution
Solution
Height = distance * tan(30) = 15 * (1/√3) = 15/√3 = 5√3 meters ≈ 7.5 meters.
Correct Answer:
A
— 7.5 meters
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Q. If a person is standing 40 meters away from a vertical pole and the angle of elevation to the top of the pole is 60 degrees, what is the height of the pole?
A.
20√3 meters
B.
40√3 meters
C.
60√3 meters
D.
80√3 meters
Show solution
Solution
Height = distance * tan(60) = 40 * √3 = 20√3 meters.
Correct Answer:
A
— 20√3 meters
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Q. If a person runs 5 km in 30 minutes, what is their speed in km/h?
A.
8 km/h
B.
10 km/h
C.
12 km/h
D.
15 km/h
Show solution
Solution
Speed = Distance / Time = 5 km / 0.5 h = 10 km/h.
Correct Answer:
B
— 10 km/h
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Q. If a person runs at a speed of 10 km/h, how far can he run in 45 minutes?
A.
5 km
B.
7.5 km
C.
10 km
D.
12.5 km
Show solution
Solution
Distance = Speed * Time = 10 km/h * (45/60) h = 7.5 km.
Correct Answer:
B
— 7.5 km
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Q. If a person runs at a speed of 8 km/h, how long will it take to run 32 km?
A.
3 hours
B.
4 hours
C.
5 hours
D.
6 hours
Show solution
Solution
Time = Distance / Speed = 32 km / 8 km/h = 4 hours
Correct Answer:
B
— 4 hours
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Q. If a person saves 15% of his salary and his salary is $1200, how much does he save?
A.
$150
B.
$180
C.
$200
D.
$220
Show solution
Solution
Savings = 0.15 * 1200 = $180.
Correct Answer:
B
— $180
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Q. If a person saves 15% of his salary and his salary is $800, how much does he save?
A.
$100
B.
$120
C.
$150
D.
$180
Show solution
Solution
Savings = 0.15 * 800 = $120.
Correct Answer:
B
— $120
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Q. If a person saves 20% of his salary and his salary is $2000, how much does he save?
A.
$300
B.
$400
C.
$500
D.
$600
Show solution
Solution
Savings = 20% of $2000 = 0.20 * 2000 = $400.
Correct Answer:
B
— $400
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Q. If a person saves 25% of his salary and his salary is $800, how much does he save?
A.
$150
B.
$200
C.
$250
D.
$300
Show solution
Solution
Savings = 25% of 800 = 0.25 * 800 = 200.
Correct Answer:
B
— $200
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Q. If a person saves 30% of his salary and his salary is $2000, how much does he save?
A.
$500
B.
$600
C.
$700
D.
$800
Show solution
Solution
Savings = 30% of 2000 = 0.3 * 2000 = $600.
Correct Answer:
B
— $600
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