General Aptitude MCQ & Objective Questions
General Aptitude is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your problem-solving skills but also boosts your confidence during exams. Practicing MCQs and objective questions helps you familiarize yourself with the exam format, identify important questions, and improve your overall performance in exam preparation.
What You Will Practise Here
Numerical Ability: Basic arithmetic, percentages, and ratios.
Logical Reasoning: Patterns, sequences, and analogies.
Data Interpretation: Reading charts, graphs, and tables.
Verbal Ability: Synonyms, antonyms, and comprehension.
Quantitative Aptitude: Algebra, geometry, and measurements.
Time and Work: Problems related to efficiency and time management.
Profit and Loss: Understanding financial transactions and calculations.
Exam Relevance
General Aptitude is a significant part of the curriculum for CBSE, State Boards, NEET, JEE, and various other competitive exams. Questions often focus on logical reasoning and quantitative skills, with patterns that include multiple-choice questions, fill-in-the-blanks, and problem-solving scenarios. Familiarity with these formats will help you tackle the exams with ease.
Common Mistakes Students Make
Misinterpreting questions due to lack of careful reading.
Overlooking units in numerical problems, leading to incorrect answers.
Rushing through calculations, resulting in simple arithmetic errors.
Neglecting to practice time management during mock tests.
Confusing similar concepts in logical reasoning sections.
FAQs
Question: What are General Aptitude MCQ questions?Answer: General Aptitude MCQ questions are multiple-choice questions designed to test your reasoning, numerical, and analytical skills relevant to various exams.
Question: How can I improve my performance in General Aptitude objective questions?Answer: Regular practice of important General Aptitude questions for exams, along with reviewing your mistakes, can significantly enhance your performance.
Don't wait any longer! Start solving practice MCQs today to test your understanding and boost your confidence for your upcoming exams. Every question you tackle brings you one step closer to success!
Q. If a number is divided by 6, the remainder is 4. What is the number?
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Solution
A number that gives a remainder of 4 when divided by 6 can be expressed as 6k + 4. For k = 2, the number is 6*2 + 4 = 16.
Correct Answer:
B
— 16
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Q. If a number is increased by 25% and then decreased by 20%, what is the net effect on the number?
A.
5% increase
B.
5% decrease
C.
10% increase
D.
10% decrease
Show solution
Solution
Let the number be 100. After 25% increase: 100 + 25 = 125. After 20% decrease: 125 - 25 = 100. Net effect = (100 - 100)/100 × 100% = 0%.
Correct Answer:
B
— 5% decrease
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Q. If a number is multiplied by 3 and then decreased by 9, the result is 0. What is the number?
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Solution
Let the number be x. The equation is 3x - 9 = 0. Solving gives x = 3.
Correct Answer:
C
— 3
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Q. If a number is multiplied by 9 and then decreased by 9, the result is 72. What is the number?
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Solution
Let the number be x. The equation is 9x - 9 = 72. Adding 9 to both sides gives 9x = 81, so x = 81/9 = 9.
Correct Answer:
A
— 8
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Q. If a password consists of 3 letters followed by 2 digits, how many different passwords can be formed using the first 5 letters and 5 digits?
A.
2500
B.
5000
C.
12500
D.
15000
Show solution
Solution
The number of passwords = 5^3 × 5^2 = 125 × 25 = 3125.
Correct Answer:
C
— 12500
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Q. If a password consists of 3 letters followed by 2 digits, how many different passwords can be formed?
A.
175760
B.
456976
C.
1000
D.
100
Show solution
Solution
The number of passwords is 26^3 * 10^2 = 175760.
Correct Answer:
A
— 175760
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Q. If a person borrows $1000 at a simple interest rate of 6% per annum, how much interest will he pay after 4 years?
A.
$240
B.
$260
C.
$280
D.
$300
Show solution
Solution
Simple Interest = 1000 × 6 × 4 / 100 = $240.
Correct Answer:
C
— $280
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Q. If a person borrows $5000 at a compound interest rate of 6% per annum, what will be the amount after 2 years?
A.
$5632
B.
$6000
C.
$5300
D.
$5500
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Solution
Amount = Principal * (1 + Rate)^Time = 5000 * (1 + 0.06)^2 = 5000 * 1.1236 = $5618.
Correct Answer:
A
— $5632
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Q. If a person buys a laptop for $800 and sells it for $720, what is the loss percentage?
A.
10%
B.
15%
C.
12.5%
D.
8%
Show solution
Solution
Loss = Cost Price - Selling Price = 800 - 720 = 80. Loss Percentage = (Loss/Cost Price) * 100 = (80/800) * 100 = 10%.
Correct Answer:
C
— 12.5%
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Q. If a person buys a watch for $150 and sells it for $180, what is the profit in dollars?
A.
$20
B.
$30
C.
$25
D.
$15
Show solution
Solution
Profit = Selling Price - Cost Price = 180 - 150 = 30.
Correct Answer:
B
— $30
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Q. If a person buys a watch for $80 and sells it for $100, what is the profit in dollars?
A.
$15
B.
$20
C.
$25
D.
$30
Show solution
Solution
Profit = Selling Price - Cost Price = 100 - 80 = 20.
Correct Answer:
B
— $20
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Q. If a person buys a watch for $80 and sells it for $64, what is the loss percentage?
A.
15%
B.
20%
C.
25%
D.
30%
Show solution
Solution
Loss = Cost Price - Selling Price = 80 - 64 = 16. Loss Percentage = (Loss/Cost Price) * 100 = (16/80) * 100 = 20%.
Correct Answer:
C
— 25%
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Q. If a person can complete a task in 12 hours, how much of the task can he complete in 3 hours?
A.
1/4
B.
1/3
C.
1/2
D.
1/6
Show solution
Solution
In 3 hours, he can complete 3/12 = 1/4 of the task.
Correct Answer:
A
— 1/4
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Q. If a person can complete a work in 10 days, how much work can he complete in 3 days?
A.
1/10
B.
1/5
C.
3/10
D.
3/5
Show solution
Solution
Work done in 1 day = 1/10. Work done in 3 days = 3 * (1/10) = 3/10.
Correct Answer:
C
— 3/10
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Q. If a person can do a piece of work in 15 days, how much work can he do in 5 days?
A.
1/3
B.
1/4
C.
1/5
D.
1/2
Show solution
Solution
Work done in 5 days = 5/15 = 1/3 of the work.
Correct Answer:
A
— 1/3
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Q. If a person can run 100 meters in 12 seconds, what is his speed in km/h?
A.
30 km/h
B.
36 km/h
C.
25 km/h
D.
20 km/h
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Solution
Speed = Distance / Time = 100 m / 12 s = (100/12) * 18/5 = 30 km/h.
Correct Answer:
B
— 36 km/h
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Q. If a person can run 100 meters in 12 seconds, what is his speed in meters per second?
A.
8.33 m/s
B.
9 m/s
C.
7.5 m/s
D.
10 m/s
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Solution
Speed = Distance / Time = 100 m / 12 s = 8.33 m/s.
Correct Answer:
A
— 8.33 m/s
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Q. If a person earns $120 as simple interest on a principal of $800 in 2 years, what is the rate of interest?
A.
5%
B.
6%
C.
7.5%
D.
8%
Show solution
Solution
Rate = (Simple Interest × 100) / (Principal × Time) = (120 × 100) / (800 × 2) = 7.5%.
Correct Answer:
B
— 6%
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Q. If a person earns $120 as simple interest on a principal of $800 in 2 years, what is the rate of interest per annum?
A.
5%
B.
6%
C.
7.5%
D.
8%
Show solution
Solution
Rate = (Simple Interest × 100) / (Principal × Time) = (120 × 100) / (800 × 2) = 7.5%.
Correct Answer:
B
— 6%
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Q. If a person earns $1200 after a 20% raise, what was his salary before the raise?
A.
$1000
B.
$1100
C.
$900
D.
$950
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Solution
Let the original salary be x. After a 20% raise, the salary is x + 0.2x = 1.2x. Therefore, 1.2x = 1200, so x = 1200 / 1.2 = $1000.
Correct Answer:
A
— $1000
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Q. If a person earns $180 as simple interest on a principal of $1200 in 3 years, what is the rate of interest?
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Solution
Rate = (Interest * 100) / (Principal * Time) = (180 * 100) / (1200 * 3) = 5%.
Correct Answer:
B
— 5%
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Q. If a person earns $5000 and spends 60% of it, how much does he save?
A.
$1500
B.
$2000
C.
$2500
D.
$3000
Show solution
Solution
Spending = 60% of 5000 = 3000. Savings = 5000 - 3000 = $2000.
Correct Answer:
B
— $2000
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Q. If a person earns a profit of 20% on a calendar that costs $50, what is the selling price?
A.
$60
B.
$70
C.
$50
D.
$40
Show solution
Solution
Selling Price = Cost Price + Profit = 50 + (20% of 50) = 50 + 10 = $60
Correct Answer:
A
— $60
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Q. If a person earns a profit of 20% on selling a watch for $120, what was the cost price of the watch?
A.
$100
B.
$110
C.
$90
D.
$80
Show solution
Solution
Let the cost price be x. Then, 120 = x + 0.2x => 120 = 1.2x => x = 120/1.2 = $100.
Correct Answer:
A
— $100
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Q. If a person invests $1000 at a rate of 5% per annum simple interest, how much interest will he earn in 3 years?
A.
$150
B.
$100
C.
$50
D.
$75
Show solution
Solution
Simple Interest = Principal * Rate * Time = 1000 * 5/100 * 3 = $150.
Correct Answer:
B
— $100
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Q. If a person invests $1000 at a simple interest rate of 5% per annum, how much interest will he earn in 3 years?
A.
$150
B.
$100
C.
$50
D.
$75
Show solution
Solution
Simple Interest = Principal * Rate * Time = 1000 * 5/100 * 3 = $150.
Correct Answer:
B
— $100
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Q. If a person invests $1000 at an annual interest rate of 5% for 3 years, what will be the total amount at the end of 3 years using simple interest?
A.
$1150
B.
$1200
C.
$1050
D.
$1100
Show solution
Solution
Simple Interest = Principal × Rate × Time = 1000 × 0.05 × 3 = $150. Total Amount = Principal + Interest = 1000 + 150 = $1150.
Correct Answer:
A
— $1150
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Q. If a person invests $1000 at an interest rate of 5% per annum, how much interest will he earn in 3 years under compound interest?
A.
$150
B.
$157.63
C.
$160
D.
$165
Show solution
Solution
Amount = P(1 + r/n)^(nt) = 1000(1 + 0.05)^3 = 1000(1.157625) = $1157.63. Interest = $1157.63 - $1000 = $157.63.
Correct Answer:
B
— $157.63
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Q. If a person invests $1000 at an interest rate of 5% per annum, how much interest will he earn in 3 years (simple interest)?
A.
150
B.
100
C.
200
D.
250
Show solution
Solution
Simple Interest = PRT = 1000 * 5/100 * 3 = 150.
Correct Answer:
B
— 100
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Q. If a person invests $1000 in shares at a compound interest rate of 5% per annum, what will be the amount after 2 years?
A.
$1102.50
B.
$1050.00
C.
$1200.00
D.
$1150.00
Show solution
Solution
Amount = Principal * (1 + Rate/100)^Time = 1000 * (1 + 5/100)^2 = 1000 * 1.1025 = $1102.50
Correct Answer:
A
— $1102.50
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