A /22 subnet mask allows for 2^(22-16) = 2^6 = 64 subnets from a Class B network.

A /22 subnet mask allows for 4 subnets when using the remaining bits for subnetting (2^(32-22) = 4).

The maximum size of a URL in HTTP requests is typically 2048 characters, although this can vary by browser.

The mid index is calculated using the formula (low + high) / 2.

The optimal substructure property in dynamic programming means that the solution can be constructed from optimal solutions of its subproblems, and the problem can be divided into smaller subproblems.

The output of a lexical analyzer, which consists of tokens, is typically fed into the parser for further processing.

When a lexical analyzer encounters an unrecognized character, it typically outputs an error message indicating the issue.

The output of a syntax-directed translation scheme is typically intermediate code.

The output of a tokenization process is a list of tokens derived from the input text.

In in-order traversal, we visit the left child first, then the parent, and finally the right child. Thus, the output is 2, 1, 3.

Dijkstra's algorithm will return one of the shortest paths, but not necessarily all of them.

Dijkstra's algorithm will return the shortest path to reachable nodes only, while unreachable nodes will have infinite distance.

The output of Dijkstra's algorithm is the shortest path from the source to all destinations in the graph.

The Bellman-Ford algorithm outputs a list of shortest path distances from the source to all vertices in the graph.

Pre-order traversal visits the root first, then the left subtree, followed by the right subtree, resulting in the output '1 2 3'.

The expression 2 ** 3 calculates 2 raised to the power of 3, which equals 8.

The output is 3 because in C, dividing two integers results in an integer, truncating any decimal.

The output is 25 because of operator precedence: 10 * 2 is evaluated first, then 5 is added.

In-order traversal visits the left child first, then the root, and finally the right child, resulting in the output 2, 1, 3.

In-order traversal visits the left subtree, then the node, and finally the right subtree, resulting in the sorted order of the nodes.

Preorder traversal visits the root node first, followed by the left subtree and then the right subtree, resulting in 'Root, Left, Right'.

Choosing the first element as the pivot can lead to poor performance (O(n^2)) if the array is already sorted or nearly sorted.

In post-order traversal, the left child is visited first, then the right child, and finally the root, resulting in 2, 3, 1.

In post-order traversal, the left subtree is visited first, then the right subtree, and finally the root. For a tree with nodes A (root), B (left), and C (right), the traversal is B, C, A.

In post-order traversal, the left child is visited first, then the right child, and finally the root, resulting in 2, 3, 1.

In post-order traversal, the left subtree is visited first, then the right subtree, and finally the root, resulting in B, C, A.

In post-order traversal, the left child is visited first (B), then the right child (C), and finally the root (A), resulting in B C A.

In post-order traversal, we visit the left subtree, then the right subtree, and finally the root. Thus, the sequence is 2, 3, 1.

In postorder traversal, the sequence is left subtree, right subtree, and then the root. Thus, for the given tree, the sequence is B C A.

The primary advantage of binary search is its better time complexity of O(log n) compared to linear search's O(n).