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Q. In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω), what is the current flowing through the circuit?

A. 2A
B. 1A
C. 0.5A
D. 3A

Solution

Total resistance R_total = R1 + R2 = 2Ω + 3Ω = 5Ω. Current I = V / R_total = 10V / 5Ω = 2A.

Correct Answer: B — 1A

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Q. In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 8Ω), what is the current flowing through the circuit?

A. 0.5A
B. 1A
C. 2A
D. 5A

Solution

Total resistance R_total = R1 + R2 = 2Ω + 8Ω = 10Ω. Current I = V/R = 10V/10Ω = 1A.

Correct Answer: B — 1A

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Q. In a circuit with a 10V battery and two resistors of 5 ohms each in series, what is the current flowing through the circuit?

A. 1 A
B. 2 A
C. 0.5 A
D. 5 A

Solution

Total resistance R_total = 5 + 5 = 10 ohms. Current I = V/R_total = 10V / 10 ohms = 1 A.

Correct Answer: B — 2 A

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Q. In a circuit with a 10V battery and two resistors of 5Ω each in series, what is the voltage across the second resistor?

A. 5V
B. 10V
C. 2.5V
D. 0V

Solution

In series, the voltage is divided equally: V2 = (R2 / (R1 + R2)) * Vtotal = (5 / (5 + 5)) * 10 = 5V.

Correct Answer: A — 5V

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Q. In a circuit with a 10Ω resistor and a 5V battery, what is the power consumed by the resistor? (2023)

A. 1W
B. 2W
C. 5W
D. 10W

Solution

Power P = V^2/R = 5^2/10 = 25/10 = 2.5W.

Correct Answer: B — 2W

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Q. In a circuit with a 10Ω resistor and a 5Ω resistor in series, what is the total voltage across the circuit if the current is 2A? (2023)

A. 30V
B. 20V
C. 10V
D. 40V

Solution

Total resistance R = 10Ω + 5Ω = 15Ω. Voltage V = I * R = 2A * 15Ω = 30V.

Correct Answer: B — 20V

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Q. In a circuit with a 12 V battery and two resistors in series (4 ohms and 8 ohms), what is the voltage drop across the 8 ohm resistor?

A. 4 V
B. 8 V
C. 6 V
D. 12 V

Solution

The total resistance is 4 + 8 = 12 ohms. The current I = V / R = 12 V / 12 ohms = 1 A. The voltage drop across the 8 ohm resistor is V = I * R = 1 A * 8 ohms = 8 V.

Correct Answer: B — 8 V

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Q. In a circuit with a 12V battery and two 4Ω resistors in series, what is the current flowing through the circuit? (2023)

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R = 4Ω + 4Ω = 8Ω. Current I = V/R = 12V/8Ω = 1.5A.

Correct Answer: B — 2A

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Q. In a circuit with a 12V battery and two resistors in parallel (4 ohms and 6 ohms), what is the total current supplied by the battery?

A. 3 A
B. 2 A
C. 1 A
D. 4 A

Solution

First, find the equivalent resistance: 1/R_eq = 1/4 + 1/6 = 5/12, so R_eq = 12/5 = 2.4 ohms. Then, using Ohm's law, I = V/R, we have I = 12V / 2.4 ohms = 5 A.

Correct Answer: A — 3 A

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Q. In a circuit with a 12V battery and two resistors in series (3 ohms and 6 ohms), what is the voltage drop across the 6 ohm resistor?

A. 8 V
B. 4 V
C. 6 V
D. 12 V

Solution

The total resistance is 9 ohms. The current is I = V/R = 12V / 9 ohms = 4/3 A. The voltage drop across the 6 ohm resistor is V = I * R = (4/3 A) * 6 ohms = 8 V.

Correct Answer: A — 8 V

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Q. In a circuit with a 12V battery and two resistors in series (4Ω and 8Ω), what is the current flowing through the circuit?

A. 0.5A
B. 1A
C. 1.5A
D. 2A

Solution

Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω. Using Ohm's law, I = V/R = 12V / 12Ω = 1A.

Correct Answer: B — 1A

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Q. In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the current flowing through the circuit?

A. 0.5A
B. 1A
C. 1.5A
D. 2A

Solution

Total resistance R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. Current I = V/R_total = 12V/12Ω = 1A.

Correct Answer: B — 1A

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Q. In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the voltage across R2?

A. 4V
B. 6V
C. 8V
D. 12V

Solution

The total resistance is R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. The current is I = V/R_total = 12V / 12Ω = 1A. The voltage across R2 is V_R2 = I * R2 = 1A * 8Ω = 8V.

Correct Answer: C — 8V

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Q. In a circuit with a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage drop across the 8 ohm resistor?

A. 4V
B. 6V
C. 8V
D. 12V

Solution

Total resistance R_total = 4 + 8 = 12 ohms. Current I = V/R_total = 12V/12 ohms = 1A. Voltage drop across 8 ohm resistor = I * R = 1A * 8 ohms = 8V.

Correct Answer: B — 6V

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Q. In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?

A. 4V
B. 6V
C. 8V
D. 12V

Solution

Using the voltage divider rule, V = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 12 = 8V.

Correct Answer: C — 8V

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Q. In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the current flowing through the circuit?

A. 0.5A
B. 1A
C. 1.5A
D. 2A

Solution

Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω. Current I = V/R = 12V / 12Ω = 1A.

Correct Answer: B — 1A

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Q. In a circuit with a 15V battery and a 5Ω resistor, what is the voltage drop across the resistor? (2019)

A. 3V
B. 5V
C. 15V
D. 0V

Solution

The voltage drop across the resistor is equal to the battery voltage, which is 15V.

Correct Answer: C — 15V

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Q. In a circuit with a 15V battery and three resistors (5Ω, 10Ω, and 15Ω) in parallel, what is the equivalent resistance?

A. 2Ω
B. 3Ω
C. 5Ω
D. 10Ω

Solution

1/R_eq = 1/5 + 1/10 + 1/15 = 0.1 + 0.0667 + 0.0667 = 0.2334. Therefore, R_eq = 4.29Ω.

Correct Answer: B — 3Ω

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Q. In a circuit with a 15V battery and two resistors in series (5Ω and 10Ω), what is the voltage drop across the 10Ω resistor?

A. 5V
B. 10V
C. 15V
D. 20V

Solution

Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (10 / (5 + 10)) * 15 = 10V.

Correct Answer: B — 10V

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Q. In a circuit with a 15V battery and two resistors in series (R1 = 5Ω, R2 = 10Ω), what is the voltage across R2?

A. 10V
B. 5V
C. 15V
D. 0V

Solution

Voltage across R2 = (R2 / (R1 + R2)) * V = (10Ω / (5Ω + 10Ω)) * 15V = 10V.

Correct Answer: A — 10V

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Q. In a circuit with a 15V battery and two resistors of 5Ω and 10Ω in series, what is the voltage drop across the 10Ω resistor? (2022)

A. 5V
B. 10V
C. 15V
D. 0V

Solution

The total resistance is 15Ω. The current I = V/R = 15V/15Ω = 1A. Voltage drop across 10Ω = I * R = 1A * 10Ω = 10V.

Correct Answer: B — 10V

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Q. In a circuit with a 20V battery and two resistors (4Ω and 8Ω) in parallel, what is the total current supplied by the battery?

A. 2A
B. 3A
C. 4A
D. 5A

Solution

Total resistance in parallel, 1/Req = 1/R1 + 1/R2 = 1/4 + 1/8 = 3/8. Therefore, Req = 8/3Ω. Total current I = V/Req = 20V / (8/3) = 7.5A.

Correct Answer: C — 4A

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Q. In a circuit with a 24 V battery and a 6 ohm resistor, what is the current flowing through the resistor?

A. 2 A
B. 4 A
C. 6 A
D. 8 A

Solution

Using Ohm's law, I = V/R = 24 V / 6 ohms = 4 A.

Correct Answer: B — 4 A

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Q. In a circuit with a 24 V battery and a total resistance of 6 ohms, what is the total current flowing through the circuit?

A. 2 A
B. 4 A
C. 6 A
D. 8 A

Solution

Using Ohm's law, I = V/R = 24 V / 6 ohms = 4 A.

Correct Answer: B — 4 A

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Q. In a circuit with a 24V battery and a 6 ohm resistor, what is the voltage drop across the resistor?

A. 4 V
B. 12 V
C. 24 V
D. 6 V

Solution

Using Ohm's law, V = I * R. First, find the current I = V/R = 24V / 6 ohms = 4 A. Then, V_drop = I * R = 4 A * 6 ohms = 24 V.

Correct Answer: B — 12 V

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Q. In a circuit with a 24V battery and a 6Ω resistor, what is the power consumed by the resistor? (2020)

A. 48W
B. 72W
C. 96W
D. 144W

Solution

Power (P) can be calculated using P = V^2 / R. Here, P = 24V^2 / 6Ω = 96W.

Correct Answer: B — 72W

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Q. In a circuit with a 24V battery and a total resistance of 8 ohms, what is the total current flowing in the circuit?

A. 3 A
B. 2 A
C. 4 A
D. 6 A

Solution

Using Ohm's law, I = V/R = 24V / 8Ω = 3 A.

Correct Answer: C — 4 A

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Q. In a circuit with a 24V battery and a total resistance of 8Ω, what is the power consumed by the circuit? (2023)

A. 72 W
B. 48 W
C. 36 W
D. 24 W

Solution

Power P = V^2/R = 24^2/8 = 576/8 = 72 W.

Correct Answer: B — 48 W

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Q. In a circuit with a 24V battery and three resistors (R1 = 4Ω, R2 = 4Ω, R3 = 4Ω) in parallel, what is the total current supplied by the battery?

A. 2A
B. 3A
C. 4A
D. 6A

Solution

Equivalent resistance R_eq = 1/(1/R1 + 1/R2 + 1/R3) = 1/(1/4 + 1/4 + 1/4) = 1.33Ω. Total current I = V/R_eq = 24V/1.33Ω = 18A.

Correct Answer: D — 6A

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Q. In a circuit with a 24V battery and three resistors in parallel (4Ω, 6Ω, and 12Ω), what is the total current supplied by the battery?

A. 2A
B. 3A
C. 4A
D. 6A

Solution

1/R_eq = 1/4 + 1/6 + 1/12 = 1. Therefore, R_eq = 2Ω. Total current I = V/R_eq = 24V/2Ω = 12A.

Correct Answer: C — 4A

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Major Competitive Exams

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