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Defence Exams MCQ & Objective Questions

Defence Exams play a crucial role in shaping the future of aspiring candidates in India. These exams not only assess knowledge but also test the ability to apply concepts in real-world scenarios. Practicing MCQs and objective questions is essential for effective exam preparation, as it helps students identify important questions and enhances their understanding of key topics.

What You Will Practise Here

Fundamentals of Defence Studies
Key Historical Events and Their Impact
Important Defence Policies and Strategies
Current Affairs Related to National Security
Basic Concepts of Military Operations
Understanding Defence Technologies
Analysing Defence Budget and Expenditure

Exam Relevance

The topics covered in Defence Exams are highly relevant across various educational boards, including CBSE and State Boards, as well as competitive exams like NEET and JEE. Students can expect questions that focus on historical events, current affairs, and fundamental concepts related to defence. Common question patterns include multiple-choice questions that assess both theoretical knowledge and practical application.

Common Mistakes Students Make

Overlooking current affairs, which are often integrated into exam questions.
Confusing similar historical events or dates, leading to incorrect answers.
Neglecting the importance of definitions and key terms in objective questions.
Relying solely on rote memorization instead of understanding concepts.

FAQs

Question: What types of questions can I expect in Defence Exams?
Answer: You can expect a mix of MCQs covering historical events, current affairs, and fundamental concepts related to defence.

Question: How can I improve my performance in Defence Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Start your journey towards success by solving practice MCQs today! Testing your understanding will not only boost your confidence but also prepare you for the important Defence Exams ahead.

NDA

Q. If a plant with genotype Aa is crossed with a plant with genotype aa, what is the expected phenotypic ratio of the offspring?

A. 1:1
B. 3:1
C. 2:1
D. 1:2

Solution

The cross Aa x aa will produce offspring in a 1:1 phenotypic ratio (A:a).

Correct Answer: A — 1:1

Q. If a plant with genotype Aa is crossed with a plant with genotype aa, what is the expected genotypic ratio of the offspring?

A. 1:1
B. 3:1
C. 1:2:1
D. 2:1

Solution

The expected genotypic ratio from Aa x aa is 1 Aa to 1 aa, which is 1:1.

Correct Answer: A — 1:1

Q. If a plant with genotype Aa is crossed with another plant of genotype Aa, what is the probability of obtaining a homozygous dominant offspring?

A. 0%
B. 25%
C. 50%
D. 100%

Solution

The cross Aa x Aa results in a 1/4 chance of AA (homozygous dominant), which is 25%.

Correct Answer: B — 25%

Q. If a plant with genotype AaBb is crossed with another plant of genotype Aabb, what is the probability of obtaining an offspring with genotype Aabb?

A. 0%
B. 25%
C. 50%
D. 75%

Solution

The cross AaBb x Aabb results in 1/4 Aabb, so the probability of obtaining Aabb is 25%.

Correct Answer: C — 50%

Q. If a plant with genotype Bb is crossed with a plant with genotype bb, what is the expected phenotypic ratio of the offspring?

A. 1:0
B. 1:1
C. 2:1
D. 3:1

Solution

The cross Bb x bb results in a phenotypic ratio of 1 Bb (dominant) to 1 bb (recessive), which is 1:1.

Correct Answer: B — 1:1

Q. If a plant with genotype Tt is crossed with a plant of genotype tt, what fraction of the offspring will be tall?

A. 0
B. 1/4
C. 1/2
D. 3/4

Solution

The cross Tt x tt results in 50% Tt (tall) and 50% tt (short), so the fraction of tall offspring is 1/2.

Correct Answer: C — 1/2

Q. If a player has a batting average of 50 and has played 20 matches, how many runs has he scored in total? (2021)

A. 1000
B. 800
C. 600
D. 500

Solution

Total runs scored = Batting average * Number of matches = 50 * 20 = 1000 runs.

Correct Answer: A — 1000

Q. If a player runs 5 km in 25 minutes, what is his speed in km/h? (2022)

A. 10 km/h
B. 12 km/h
C. 15 km/h
D. 20 km/h

Solution

Speed = Distance / Time = 5 km / (25/60) hours = 5 / (25/60) = 12 km/h.

Correct Answer: A — 10 km/h

Q. If a political party needs 50% of the total seats in the Lok Sabha to form a government, how many seats does it need if there are 545 total seats?

A. 272
B. 273
C. 274
D. 275

Solution

Seats needed = (545/2) + 1 = 273 seats.

Correct Answer: B — 273

Q. If a population of 1,000 has a disease prevalence of 3%, how many individuals are expected to be affected? (2019)

A. 30
B. 25
C. 35
D. 40

Solution

Expected affected individuals = Prevalence × Population = 0.03 × 1000 = 30.

Correct Answer: A — 30

Q. If a purebred red flower (RR) is crossed with a purebred white flower (rr), what will be the color of the flowers in the F1 generation?

A. Red
B. White
C. Pink
D. Purple

Solution

The F1 generation will all be Rr, which expresses the red phenotype since red is dominant over white.

Correct Answer: A — Red

Q. If a purebred red flowered plant (RR) is crossed with a purebred white flowered plant (rr), what will be the phenotype of the F1 generation?

A. Red
B. White
C. Pink
D. Mixed

Solution

The F1 generation will all be red (Rr) since red is dominant over white.

Correct Answer: A — Red

Q. If a radar can detect objects up to a distance of 100 km, what is the maximum area it can cover? (2022)

A. 31415.93 km²
B. 7853.98 km²
C. 10000 km²
D. 5000 km²

Solution

Area = πr² = π(100 km)² ≈ 31415.93 km²

Correct Answer: A — 31415.93 km²

Q. If a radar can detect objects up to a distance of 50 km, what is the maximum area it can cover? (2022)

A. 7850 km²
B. 5000 km²
C. 10000 km²
D. 15000 km²

Solution

Area = πr² = π(50 km)² ≈ 7850 km²

Correct Answer: A — 7850 km²

Q. If a radar system can detect objects up to 100 km away, how many meters is that? (2023)

A. 5000 m
B. 10000 m
C. 15000 m
D. 20000 m

Solution

100 km = 100 × 1000 m = 100000 m

Correct Answer: B — 10000 m

Q. If a radar system can detect objects up to 100 km away, what is the maximum area it can cover? (2022)

A. 31415.93 km²
B. 7853.98 km²
C. 10000 km²
D. 5000 km²

Solution

Area = πr² = π(100 km)² ≈ 31415.93 km²

Correct Answer: A — 31415.93 km²

Q. If a rectangle has a length of 10 cm and a width of 5 cm, what is its perimeter? (2022)

A. 30 cm
B. 25 cm
C. 20 cm
D. 15 cm

Solution

Perimeter of a rectangle = 2(length + width) = 2(10 + 5) = 30 cm.

Correct Answer: A — 30 cm

Q. If a rectangle has a length of 10 cm and a width of 5 cm, what is the area of the rectangle? (2022)

A. 50 cm²
B. 55 cm²
C. 60 cm²
D. 65 cm²

Solution

Area = length × width = 10 cm × 5 cm = 50 cm².

Correct Answer: A — 50 cm²

Q. If a rectangle has a length of 10 m and a width of 5 m, what is its perimeter? (2023)

A. 30 m
B. 25 m
C. 20 m
D. 15 m

Solution

Perimeter = 2(length + width) = 2(10 + 5) = 30 m.

Correct Answer: A — 30 m

Q. If a rectangle has a length of 10 units and a width of 5 units, what is its perimeter?

A. 30
B. 40
C. 50
D. 20

Solution

Perimeter = 2 * (length + width) = 2 * (10 + 5) = 30 units.

Correct Answer: A — 30

Q. If a rectangle has a length of 15 cm and a width of 10 cm, what is its perimeter? (2022)

A. 50 cm
B. 40 cm
C. 30 cm
D. 60 cm

Solution

Perimeter = 2(length + width) = 2(15 + 10) = 50 cm.

Correct Answer: A — 50 cm

Q. If a rectangle has a length of 8 cm and a width of 5 cm, what is its perimeter? (2022)

A. 26 cm
B. 30 cm
C. 40 cm
D. 20 cm

Solution

Perimeter = 2(length + width) = 2(8 + 5) = 26 cm.

Correct Answer: A — 26 cm

Q. If a rectangle has a length of 8 m and a width of 3 m, what is its perimeter? (2021)

A. 22 m
B. 24 m
C. 26 m
D. 30 m

Solution

Perimeter = 2(length + width) = 2(8 m + 3 m) = 22 m.

Correct Answer: A — 22 m

Q. If a rectangle has a length of 8 units and a width of 3 units, what is its perimeter? (2023)

A. 22
B. 24
C. 20
D. 18

Solution

The perimeter of a rectangle is given by 2(length + width). Thus, perimeter = 2(8 + 3) = 22 units.

Correct Answer: A — 22

Q. If a rectangle has a length of 8 units and a width of 5 units, what is its perimeter? (2023)

A. 26
B. 30
C. 20
D. 24

Solution

The perimeter of a rectangle is given by 2(length + width). Thus, perimeter = 2(8 + 5) = 2 * 13 = 26.

Correct Answer: A — 26

Q. If a region receives 1200 mm of rainfall in a year, what is the average monthly rainfall? (2022)

A. 100 mm
B. 120 mm
C. 150 mm
D. 200 mm

Solution

Average monthly rainfall = Total annual rainfall / 12 = 1200 mm / 12 = 100 mm.

Correct Answer: B — 120 mm

Q. If a right triangle has legs of lengths 3 cm and 4 cm, what is the length of the hypotenuse?

A. 5 cm
B. 6 cm
C. 7 cm
D. 8 cm

Solution

Using the Pythagorean theorem, hypotenuse = √(3² + 4²) = √(9 + 16) = √25 = 5 cm.

Correct Answer: A — 5 cm

Q. If a right triangle has legs of lengths 6 and 8, what is the length of the hypotenuse?

A. 10 units
B. 12 units
C. 14 units
D. 16 units

Solution

Using the Pythagorean theorem: hypotenuse = √(6^2 + 8^2) = √(36 + 64) = √100 = 10 units.

Correct Answer: A — 10 units

Q. If a river basin has an area of 2000 km² and receives an average rainfall of 800 mm per year, what is the total volume of water received by the basin in cubic meters? (2000)

A. 1600000000
B. 16000000
C. 160000000
D. 16000000000

Solution

Volume = Area × Rainfall = 2000 km² × 800 mm = 2000 × 10^6 m² × 0.8 m = 1600000000 m³.

Correct Answer: A — 1600000000

Q. If a river basin has an area of 500 km² and receives an average rainfall of 800 mm annually, what is the total volume of water received by the basin in cubic meters? (2022)

A. 400,000,000 m³
B. 500,000,000 m³
C. 600,000,000 m³
D. 700,000,000 m³

Solution

Volume = Area × Rainfall = 500 km² × 800 mm = 500,000,000 m³.

Correct Answer: B — 500,000,000 m³

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