Major Competitive Exams

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Q. A food item contains 10 grams of carbohydrates, 5 grams of protein, and 2 grams of fat. How many total calories does this food item provide? (Carbohydrates = 4 cal/g, Protein = 4 cal/g, Fat = 9 cal/g) (2022)

A. 66
B. 58
C. 62
D. 64

Solution

Total calories = (10g * 4) + (5g * 4) + (2g * 9) = 40 + 20 + 18 = 78 calories.

Correct Answer: C — 62

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Q. A food item has 5 grams of sugar per serving. If a person consumes 4 servings, how many grams of sugar do they consume? (2019)

A. 15 grams
B. 20 grams
C. 25 grams
D. 30 grams

Solution

5 grams per serving * 4 servings = 20 grams.

Correct Answer: C — 25 grams

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Q. A food label states that a serving contains 5 grams of sugar. If a person consumes 3 servings, how many grams of sugar do they consume?

A. 10 grams
B. 12 grams
C. 15 grams
D. 18 grams

Solution

5 grams/serving * 3 servings = 15 grams.

Correct Answer: C — 15 grams

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Q. A football field is 100 meters long and 60 meters wide. What is the area of the field in square meters? (2019)

A. 6000 m²
B. 5000 m²
C. 4000 m²
D. 3000 m²

Solution

Area = Length * Width = 100 m * 60 m = 6000 m².

Correct Answer: A — 6000 m²

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Q. A football field is 100 meters long and 64 meters wide. What is the area of the field in square meters? (2019)

A. 6400
B. 10000
C. 8000
D. 6000

Solution

Area = length × width = 100 m × 64 m = 6400 square meters.

Correct Answer: A — 6400

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Q. A football field is 100 meters long and 64 meters wide. What is the perimeter of the field? (2023)

A. 328 m
B. 264 m
C. 200 m
D. 300 m

Solution

Perimeter = 2(Length + Width) = 2(100 m + 64 m) = 2 * 164 m = 328 m.

Correct Answer: A — 328 m

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Q. A football match lasts for 90 minutes. If a player plays for 60 minutes, what fraction of the match did he play? (2019)

A. 1/2
B. 2/3
C. 3/4
D. 5/6

Solution

The fraction of the match played is 60 minutes out of 90 minutes, which is 60/90 = 2/3.

Correct Answer: B — 2/3

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Q. A football match lasts for 90 minutes. If a player runs at an average speed of 8 km/h, how far does he run in the entire match? (2019)

A. 10 km
B. 12 km
C. 14 km
D. 15 km

Solution

Distance = Speed × Time. Time in hours = 90/60 = 1.5 hours. Distance = 8 km/h × 1.5 h = 12 km.

Correct Answer: B — 12 km

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Q. A football match lasts for 90 minutes. If a player runs at an average speed of 8 km/h, how far does he run during the match? (2019)

A. 10 km
B. 12 km
C. 8 km
D. 6 km

Solution

Distance = Speed × Time. Time in hours = 90/60 = 1.5 hours. Distance = 8 km/h × 1.5 h = 12 km.

Correct Answer: C — 8 km

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Q. A football team has a win rate of 40%. If they played 30 matches, how many matches did they win? (2020)

A. 10
B. 12
C. 15
D. 8

Solution

Matches won = 40% of 30 = 0.4 * 30 = 12.

Correct Answer: A — 10

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Q. A football team has a win rate of 60%. If they play 50 matches, how many matches do they win? (2019)

A. 25
B. 30
C. 35
D. 40

Solution

Number of matches won = 60% of 50 = 0.6 * 50 = 30 matches.

Correct Answer: B — 30

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Q. A football team wins 70% of its matches. If they played 30 matches, how many matches did they win? (2022)

A. 20
B. 21
C. 22
D. 23

Solution

Matches won = 70% of 30 = 0.7 * 30 = 21 matches.

Correct Answer: A — 20

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Q. A force is measured as 100 N with an uncertainty of ±2 N. What is the maximum possible value of the force?

A. 102 N
B. 98 N
C. 100 N
D. 104 N

Solution

Maximum possible value = measured value + uncertainty = 100 + 2 = 102 N.

Correct Answer: A — 102 N

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Q. A force is measured as 50 N with an uncertainty of ±1 N. What is the percentage uncertainty in the force measurement?

A. 2%
B. 1%
C. 0.5%
D. 0.1%

Solution

Percentage uncertainty = (absolute uncertainty / measured value) * 100 = (1 / 50) * 100 = 2%.

Correct Answer: B — 1%

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Q. A force is measured as 50 N with an uncertainty of ±2 N. What is the percentage uncertainty in the force measurement?

A. 4%
B. 2%
C. 1%
D. 5%

Solution

Percentage uncertainty = (absolute uncertainty / measured value) * 100 = (2 / 50) * 100 = 4%.

Correct Answer: A — 4%

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Q. A force is measured as 50 N with an uncertainty of ±2 N. What is the relative uncertainty in this force measurement?

A. 0.04
B. 0.02
C. 0.01
D. 0.05

Solution

Relative uncertainty = (absolute uncertainty / measured value) = 2 / 50 = 0.04 or 4%.

Correct Answer: B — 0.02

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Q. A force of 10 N is applied at a distance of 0.5 m from the pivot point. What is the torque about the pivot?

A. 2.0 Nm
B. 5.0 Nm
C. 10.0 Nm
D. 20.0 Nm

Solution

Torque (τ) = Force (F) × Distance (d) = 10 N × 0.5 m = 5 Nm.

Correct Answer: A — 2.0 Nm

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Q. A force of 10 N is applied at a distance of 2 m from the pivot point. What is the torque about the pivot?

A. 5 Nm
B. 10 Nm
C. 20 Nm
D. 15 Nm

Solution

Torque = Force × Distance = 10 N × 2 m = 20 Nm.

Correct Answer: C — 20 Nm

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Q. A force of 10 N is applied at a distance of 2 m from the pivot point. What is the torque about the pivot point?

A. 5 Nm
B. 10 Nm
C. 20 Nm
D. 15 Nm

Solution

Torque = Force × Distance = 10 N × 2 m = 20 Nm.

Correct Answer: C — 20 Nm

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Q. A force of 10 N is applied at an angle of 60 degrees to a lever arm of 2 m. What is the torque about the pivot?

A. 10 Nm
B. 17.32 Nm
C. 20 Nm
D. 5 Nm

Solution

Torque = Force × Distance × sin(60°) = 10 N × 2 m × (√3/2) = 17.32 Nm.

Correct Answer: B — 17.32 Nm

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Q. A force of 10 N is applied to a 2 kg object at rest. What is the final velocity of the object after 5 seconds?

A. 2 m/s
B. 5 m/s
C. 10 m/s
D. 15 m/s

Solution

Using F = ma, a = F/m = 10 N / 2 kg = 5 m/s². Final velocity v = u + at = 0 + 5 * 5 = 25 m/s.

Correct Answer: B — 5 m/s

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Q. A force of 10 N is applied to a 2 kg object. What is the net force acting on the object if it is also experiencing a frictional force of 4 N?

A. 6 N
B. 10 N
C. 14 N
D. 4 N

Solution

Net force = applied force - frictional force = 10 N - 4 N = 6 N.

Correct Answer: A — 6 N

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Q. A force of 10 N is applied to a 2 kg object. What is the object's acceleration?

A. 5 m/s²
B. 10 m/s²
C. 2 m/s²
D. 20 m/s²

Solution

Using F = ma, acceleration a = F/m = 10 N / 2 kg = 5 m/s².

Correct Answer: A — 5 m/s²

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Q. A force of 10 N is applied to a 2 kg object. What is the resulting acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we have a = F/m = 10 N / 2 kg = 5 m/s².

Correct Answer: A — 2 m/s²

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Q. A force of 10 N is applied to an object, causing it to accelerate at 2 m/s². What is the mass of the object? (2020)

A. 5 kg
B. 10 kg
C. 15 kg
D. 20 kg

Solution

Using F = ma, mass m = F/a = 10 N / 2 m/s² = 5 kg.

Correct Answer: A — 5 kg

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Q. A force of 10 N is applied to move a box 5 m across a floor. What is the work done on the box?

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done = Force × Distance = 10 N × 5 m = 50 J

Correct Answer: B — 20 J

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Q. A force of 10 N is applied to move a box 5 m across a floor. What is the work done by the force?

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done = Force × Distance = 10 N × 5 m = 50 J

Correct Answer: B — 20 J

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Q. A force of 10 N is applied to move a box 5 m across a frictionless surface. What is the work done on the box? (2021)

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done (W) = Force (F) × Distance (d) = 10 N × 5 m = 50 J.

Correct Answer: B — 20 J

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Q. A force of 10 N is applied to move a box 5 m along a horizontal surface. What is the work done by the force? (2021)

A. 20 J
B. 50 J
C. 10 J
D. 5 J

Solution

Work done = Force × Distance = 10 N × 5 m = 50 J

Correct Answer: B — 50 J

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Q. A force of 10 N is applied to move an object 5 m in the direction of the force. What is the work done by the force?

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done (W) = Force (F) × Distance (d) × cos(θ). Here, θ = 0° (force and displacement are in the same direction). W = 10 N × 5 m × cos(0°) = 10 N × 5 m = 50 J.

Correct Answer: B — 20 J

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Major Competitive Exams

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