The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions? Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers? Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions? Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will the stone land if it is thrown with a speed of 10 m/s?
A.
20 m
B.
40 m
C.
60 m
D.
80 m
Solution
Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = speed * time = 10 m/s * 4.04 s ≈ 40 m.
Q. A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land?
A.
20 m
B.
40 m
C.
60 m
D.
80 m
Solution
Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = horizontal speed * time. Assuming horizontal speed = 10 m/s, distance = 10 m/s * 4.04 s = 40.4 m.
Q. A stone is tied to a string and swung in a vertical circle. At the highest point, the tension in the string is 5 N and the weight of the stone is 10 N. What is the speed of the stone at the highest point if the radius of the circle is 2 m?
A.
2 m/s
B.
3 m/s
C.
4 m/s
D.
5 m/s
Solution
At the highest point, T + mg = mv²/r. 5 + 10 = (m*v²)/2. Solving gives v = 4 m/s.
Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to maintain the circular motion at the same speed?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
Solution
Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for constant speed.
Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to maintain the stone's circular motion at the same speed?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
Solution
Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for constant speed.
Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to keep the stone moving in a circle at the same speed?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
Solution
Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for the same speed.
Q. A stone is tied to a string and whirled in a vertical circle of radius 1 m. What is the minimum speed at the top of the circle to keep the stone in circular motion?
A.
1 m/s
B.
2 m/s
C.
3 m/s
D.
4 m/s
Solution
At the top, centripetal force = weight. mv²/r = mg. v² = rg. v = √(1*9.8) ≈ 3.13 m/s.
Q. A student is selected at random from a class of 40 students, where 25 are boys and 15 are girls. What is the probability that the student is a girl given that the student is not a boy?
A.
1/3
B.
1/2
C.
2/3
D.
3/4
Solution
The total number of students that are not boys is 15 (girls). The probability of selecting a girl given that the student is not a boy is 15/15 = 1.
Q. A student is selected at random from a class of 40 students, where 25 are boys and 15 are girls. What is the probability that the student is a boy given that the student is not a girl?
A.
1/2
B.
3/4
C.
5/8
D.
2/5
Solution
If the student is not a girl, they must be a boy. Therefore, P(Boy | Not Girl) = 1.
Q. A student is selected at random from a group of 40 students, where 25 are studying Mathematics and 15 are studying Physics. What is the probability that the student is studying Mathematics given that they are not studying Physics?
A.
5/8
B.
3/8
C.
1/2
D.
1/3
Solution
If the student is not studying Physics, they must be studying Mathematics. Therefore, P(Math | Not Physics) = 1.
Q. A student is selected at random from a group of 40 students, where 25 are studying Mathematics and 15 are studying Physics. What is the probability that the student is studying Physics given that the student is not studying Mathematics?
A.
0
B.
1/3
C.
3/8
D.
1/2
Solution
If the student is not studying Mathematics, they must be studying Physics. Therefore, the probability is 1.
Q. A student is selected at random from a group of students who study Mathematics and Physics. If 70% study Mathematics and 40% study both subjects, what is the probability that a student studies Physics given that they study Mathematics?
A.
0.4
B.
0.3
C.
0.5
D.
0.6
Solution
Using the formula P(Physics|Mathematics) = P(Physics and Mathematics) / P(Mathematics) = 0.4 / 0.7 = 0.571.
Q. A student is selected from a class of 40 students, where 25 are girls and 15 are boys. What is the probability that the student is a girl given that the student is not a boy?
A.
1
B.
0
C.
1/2
D.
3/4
Solution
If the student is not a boy, they must be a girl. Therefore, the probability is 1.
