Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. If the temperature of a gas is doubled at constant volume, what happens to the pressure?

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

According to Gay-Lussac's Law, if the temperature of a gas is increased while keeping the volume constant, the pressure will also increase proportionally, thus it doubles.

Correct Answer: A — It doubles

Q. If the temperature of a gas is doubled, how does its RMS speed change?

A. Increases by a factor of sqrt(2)
B. Increases by a factor of 2
C. Increases by a factor of 4
D. Remains the same

Solution

The RMS speed is proportional to the square root of the temperature. If the temperature is doubled, the RMS speed increases by a factor of sqrt(2).

Correct Answer: A — Increases by a factor of sqrt(2)

Q. If the temperature of a gas is doubled, what happens to its RMS speed?

A. Increases by a factor of sqrt(2)
B. Increases by a factor of 2
C. Increases by a factor of sqrt(3)
D. Remains the same

Solution

The RMS speed is proportional to the square root of the temperature. If the temperature is doubled, the RMS speed increases by a factor of sqrt(2).

Correct Answer: A — Increases by a factor of sqrt(2)

Q. If the temperature of a gas is halved, what happens to its RMS speed?

A. Increases by sqrt(2)
B. Decreases by sqrt(2)
C. Remains the same
D. Decreases by 2

Solution

RMS speed is directly proportional to the square root of temperature. Halving the temperature results in a decrease in RMS speed by sqrt(2).

Correct Answer: B — Decreases by sqrt(2)

Q. If the temperature of a gas is increased at constant volume, what happens to the pressure?

A. Increases
B. Decreases
C. Remains constant
D. Becomes zero

Solution

According to Gay-Lussac's Law, if the temperature of a gas increases at constant volume, the pressure increases.

Correct Answer: A — Increases

Q. If the temperature of a gas is increased from 200 K to 800 K, how does the RMS speed change?

A. Increases by 2
B. Increases by 4
C. Increases by sqrt(4)
D. Decreases by sqrt(4)

Solution

RMS speed increases by sqrt(4) = 2, since v_rms is proportional to sqrt(T).

Correct Answer: C — Increases by sqrt(4)

Q. If the temperature of a gas is increased from 300 K to 600 K, how does the RMS speed change?

A. It doubles
B. It increases by sqrt(2)
C. It increases by sqrt(3)
D. It remains the same

Solution

RMS speed is proportional to the square root of temperature. Increasing from 300 K to 600 K increases the speed by sqrt(2).

Correct Answer: B — It increases by sqrt(2)

Q. If the temperature of a gas is increased while keeping the volume constant, what happens to the pressure?

A. Pressure decreases
B. Pressure increases
C. Pressure remains constant
D. Pressure becomes zero

Solution

According to Gay-Lussac's Law, if the temperature of a gas is increased while keeping the volume constant, the pressure increases.

Correct Answer: B — Pressure increases

Q. If the temperature of a liquid increases, what happens to its viscosity?

A. Increases
B. Decreases
C. Remains constant
D. Varies unpredictably

Solution

The viscosity of a liquid generally decreases with an increase in temperature.

Correct Answer: B — Decreases

Q. If the temperature of a material increases, what happens to its Young's modulus?

A. Increases
B. Decreases
C. Remains constant
D. Depends on the material

Solution

Generally, the Young's modulus of materials decreases with an increase in temperature.

Correct Answer: B — Decreases

Q. If the temperature of a metallic conductor increases, what happens to its resistivity?

A. Increases
B. Decreases
C. Remains constant
D. Becomes zero

Solution

For metals, resistivity increases with temperature due to increased lattice vibrations.

Correct Answer: A — Increases

Q. If the temperature of a system is increased, what happens to its entropy?

A. It decreases
B. It remains constant
C. It increases
D. It becomes zero

Solution

As the temperature of a system increases, the kinetic energy of the particles increases, leading to greater disorder and thus an increase in entropy.

Correct Answer: C — It increases

Q. If the temperature of an ideal gas is doubled at constant volume, what happens to the pressure?

A. It remains the same
B. It doubles
C. It triples
D. It quadruples

Solution

According to Gay-Lussac's law, at constant volume, the pressure of an ideal gas is directly proportional to its absolute temperature. Therefore, if the temperature is doubled, the pressure also doubles.

Correct Answer: B — It doubles

Q. If the temperature of an ideal gas is doubled at constant volume, what happens to its pressure?

A. It halves
B. It remains the same
C. It doubles
D. It quadruples

Solution

According to Gay-Lussac's law, pressure is directly proportional to temperature at constant volume, so it doubles.

Correct Answer: C — It doubles

Q. If the temperature of an ideal gas is doubled at constant volume, what happens to the average kinetic energy of the gas molecules?

A. It remains the same.
B. It doubles.
C. It triples.
D. It halves.

Solution

The average kinetic energy of gas molecules is directly proportional to the absolute temperature. Therefore, if the temperature is doubled, the average kinetic energy also doubles.

Correct Answer: B — It doubles.

Q. If the temperature of an ideal gas is doubled while keeping the pressure constant, what happens to its volume?

A. It halves
B. It doubles
C. It remains the same
D. It quadruples

Solution

According to Charles's Law, at constant pressure, the volume of an ideal gas is directly proportional to its temperature. Therefore, if the temperature doubles, the volume also doubles.

Correct Answer: B — It doubles

Q. If the temperature of an ideal gas is doubled while keeping the volume constant, what happens to the pressure?

A. It remains the same.
B. It doubles.
C. It triples.
D. It halves.

Solution

According to Gay-Lussac's law, if the volume is constant, the pressure of an ideal gas is directly proportional to its absolute temperature. Therefore, doubling the temperature doubles the pressure.

Correct Answer: B — It doubles.

Q. If the temperature of an object increases, what happens to the rate of heat radiation from that object?

A. Decreases
B. Increases
C. Remains constant
D. Becomes zero

Solution

According to Stefan-Boltzmann law, the rate of heat radiation increases with the fourth power of the temperature, so as the temperature increases, the rate of radiation also increases.

Correct Answer: B — Increases

Q. If the temperature of an object increases, what happens to the rate of heat transfer by radiation?

A. Decreases
B. Increases
C. Remains constant
D. Becomes zero

Solution

The rate of heat transfer by radiation increases with the fourth power of the absolute temperature, according to Stefan-Boltzmann law.

Correct Answer: B — Increases

Q. If the temperature of an object is doubled, how does its thermal radiation change according to the Stefan-Boltzmann law?

A. It doubles
B. It quadruples
C. It remains the same
D. It increases eightfold

Solution

According to the Stefan-Boltzmann law, if the temperature is doubled, the thermal radiation increases by a factor of 2^4 = 16, not quadruples.

Correct Answer: B — It quadruples

Q. If the temperature of an object is doubled, how does the rate of heat radiation change?

A. It doubles
B. It quadruples
C. It remains the same
D. It halves

Solution

According to the Stefan-Boltzmann law, if the temperature is doubled, the rate of heat radiation increases by a factor of 2^4 = 16.

Correct Answer: B — It quadruples

Q. If the terms of a harmonic progression are 1, 1/4, and 1/9, what is the common difference of the corresponding arithmetic progression?

A. 1/36
B. 1/12
C. 1/9
D. 1/4

Solution

The reciprocals are 1, 4, and 9. The common difference is 4 - 1 = 3.

Correct Answer: B — 1/12

Q. If the terms of a harmonic progression are 3, 6, and x, what is the value of x?

A. 9
B. 12
C. 15
D. 18

Solution

The reciprocals of the terms are 1/3, 1/6, and 1/x. Since they form an arithmetic progression, we can set up the equation: 1/6 - 1/3 = 1/x - 1/6, solving gives x = 12.

Correct Answer: B — 12

Q. If the terms of a harmonic progression are 4, 2, and x, what is the value of x?

A. 1
B. 1.5
C. 2
D. 3

Solution

The reciprocals are 1/4, 1/2, and 1/x. The common difference is 1/2 - 1/4 = 1/4, so 1/x = 1/2 + 1/4 = 3/4, thus x = 4/3.

Correct Answer: D — 3

Q. If the torque is doubled while keeping the distance constant, what happens to the force applied?

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

Torque = Force × Distance; if Torque is doubled and Distance is constant, Force must also double.

Correct Answer: A — It doubles

Q. If the torque on a rotating object is doubled while the radius remains constant, what happens to the force applied?

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

If torque is doubled and radius remains constant, the force must also double to maintain the relationship τ = F × r.

Correct Answer: A — It doubles

Q. If the torque on an object is zero, what can be said about the forces acting on it?

A. The object is at rest.
B. The net force is zero.
C. The forces are balanced.
D. The forces are acting along the same line.

Solution

If the torque is zero, it means that the forces are acting along the same line, resulting in no rotational effect.

Correct Answer: D — The forces are acting along the same line.

Q. If the torque on an object is zero, which of the following must be true?

A. The net force is zero.
B. The object is at rest.
C. The forces are balanced.
D. The line of action of the forces passes through the pivot.

Solution

If the torque is zero, it means that the line of action of the forces passes through the pivot point.

Correct Answer: D — The line of action of the forces passes through the pivot.

Q. If the total amount after 2 years is $1100 from a principal of $1000 at a compound interest rate of 5%, what is the interest earned?

A. $100
B. $110
C. $120
D. $150

Solution

Interest Earned = Total Amount - Principal = 1100 - 1000 = 100.

Correct Answer: A — $100

Q. If the total charge enclosed by a Gaussian surface is zero, what can be said about the electric field on that surface?

A. It is zero everywhere
B. It can be non-zero
C. It is constant
D. It is infinite

Solution

If the total charge enclosed is zero, the electric field can still be non-zero at points on the surface due to external charges.

Correct Answer: B — It can be non-zero

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