The solid sphere will have a greater linear speed because it has a smaller moment of inertia, allowing it to convert more potential energy into translational kinetic energy.

The solid sphere will have a greater translational speed because it has a smaller moment of inertia.

The solid sphere has a smaller moment of inertia compared to the hollow sphere, allowing it to accelerate faster down the incline.

Total angular momentum L = Iω, where I = (2/5)MR^2 for a solid sphere.

The moment of inertia of a solid sphere about its center is I = 2/5 MR^2.

The moment of inertia of a solid sphere about an axis through its center is I = 2/5 MR^2.

The acceleration of the center of mass of a rolling object is given by a = g sin(θ) / (1 + k^2/r^2). For a solid sphere, k^2/r^2 = 2/5, thus a = g sin(θ) / (1 + 2/5) = g sin(θ) / (7/5) = (5/7)g sin(θ).

The acceleration of the center of mass of a solid sphere rolling down an incline is given by a = g sin(θ) / (1 + (2/5)) = g sin(θ) / (7/5) = (5/7) g sin(θ).

Using conservation of energy, the final velocity of the solid sphere at the bottom is v = √(5gh/7).

Using conservation of energy, potential energy at the top (mgh) converts to kinetic energy (1/2 mv^2 + 1/2 Iω^2). For a solid sphere, I = (2/5)mr^2 and ω = v/r. Solving gives v = √(2gh).

The total kinetic energy is the sum of translational and rotational kinetic energy. For a solid sphere, the ratio of translational to total kinetic energy is 2:3.

The total kinetic energy is the sum of translational and rotational kinetic energy. For a solid sphere, the ratio of translational to total kinetic energy is 2:5, which simplifies to 2:3.

For a solid sphere, the ratio of translational kinetic energy to total kinetic energy is 2:3.

Mass of glucose = (20/100) x 200 g = 40 g.

Mass = moles x molar mass = 0.1 moles x 58.5 g/mol = 5.85 g.

Moles of solute = Molarity × Volume = 0.2 M × 1.5 L = 0.3 moles.

Mass of NaCl = (10/100) x 1000 mL = 100 g.

Mass of NaOH = (10/100) x 1000 mL = 100 g.

Volume of solution = mass / density = 30 g / 1.2 g/mL = 25 mL = 0.025 L. Moles of solute = 30 g / 60 g/mol = 0.5 moles. Molarity = 0.5 moles / 0.025 L = 20 M.

Mass percent = (mass of solute / (mass of solute + mass of solvent)) × 100 = (50 g / (50 g + 250 g)) × 100 = 20%.

Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = moles of solute / liters of solution = 1 mole / 1 L = 1 M.

Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.

Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.

Freezing point depression = K_f * m = 1.86 * 0.1 = 0.186 °C

Using the wave equation v = fλ, we can find λ = v/f = 340/170 = 2 m.

Using the wave equation v = fλ, we can find the wavelength: λ = v/f = 340 m/s / 1700 Hz = 0.2 m.

Using the wave equation v = fλ, we can find the wavelength: λ = v/f = 340 m/s / 680 Hz = 0.5 m.

Using the wave equation v = fλ, we can find the wavelength: λ = v/f = 340/170 = 2 m.

Sound travels faster in water than in air, so its speed increases when it enters water.

Wavelength λ = v/f = 340 m/s / 170 Hz = 2 m.