The Common Admission Test (CAT) is a crucial examination for students aspiring to pursue management studies in India. Mastering CAT MCQ and objective questions is essential for scoring well and gaining admission into top institutions. Practicing these types of questions not only enhances your understanding of key concepts but also boosts your confidence during exam preparation.
What You Will Practise Here
Quantitative Aptitude: Key formulas and problem-solving techniques
Data Interpretation: Understanding graphs, charts, and tables
Logical Reasoning: Techniques to tackle complex reasoning problems
Verbal Ability: Vocabulary, grammar, and comprehension skills
General Knowledge: Current affairs and business awareness
Important CAT questions for exams: Previous year papers and sample questions
Exam Relevance
The CAT exam is not only significant for management aspirants but also serves as a benchmark for various competitive exams in India, including CBSE, State Boards, NEET, and JEE. Questions related to CAT concepts often appear in different formats, such as multiple-choice questions (MCQs) and objective-type questions. Familiarity with these patterns can greatly enhance your performance across various subjects.
Common Mistakes Students Make
Overlooking basic concepts while attempting advanced questions
Misinterpreting data in graphs and tables
Neglecting time management during practice sessions
Ignoring the importance of vocabulary in verbal ability sections
FAQs
Question: What are CAT MCQ questions? Answer: CAT MCQ questions are multiple-choice questions designed to test your understanding of various subjects relevant to management studies.
Question: How can I find CAT objective questions with answers? Answer: You can access a variety of CAT objective questions with answers through practice papers and online resources tailored for exam preparation.
Now is the time to take charge of your exam preparation! Start solving practice MCQs to test your understanding and improve your performance. Remember, consistent practice is the key to success in mastering CAT and achieving your academic goals.
Q. A family has an average income of $50,000. If the father earns $60,000 and the mother earns $40,000, what is the average income of their two children if the total family income is $200,000?
A.
$40,000
B.
$50,000
C.
$60,000
D.
$70,000
Solution
Total income of children = $200,000 - ($60,000 + $40,000) = $100,000. Average income of children = $100,000 / 2 = $50,000.
Q. A family has three children with ages 10, 12, and 14. If they have another child, what age must the new child be for the average age of the family to be 12?
A.
8
B.
10
C.
12
D.
14
Solution
Let the age of the new child be x. Then, (10 + 12 + 14 + x) / 4 = 12. Solving gives x = 8.
Q. A family has three children with ages 5, 10, and 15. If a new child is born, what age must the new child be to maintain an average age of 10?
A.
5
B.
10
C.
15
D.
20
Solution
Current total age = 5 + 10 + 15 = 30. To maintain an average of 10 with 4 children, total age must be 40. Therefore, the new child's age must be 40 - 30 = 10.
Q. A family has three children with ages 5, 10, and 15. If they have another child, what age must the new child be to maintain an average age of 10? (2023)
A.
5
B.
10
C.
15
D.
20
Solution
Current total age = 5 + 10 + 15 = 30. To maintain an average of 10 with 4 children, total age must be 40. Therefore, the new child's age must be 40 - 30 = 10.
Q. A fruit seller has apples and oranges in the ratio 5:3. If he has 40 apples, how many oranges does he have?
A.
24
B.
30
C.
32
D.
20
Solution
The ratio of apples to oranges is 5:3. If there are 40 apples, we can set up the proportion: 5/3 = 40/x. Cross-multiplying gives us 5x = 120, so x = 120/5 = 24. Therefore, he has 24 oranges.
Q. A fruit seller has apples and oranges in the ratio of 5:3. If he has 40 apples, how many oranges does he have?
A.
24
B.
30
C.
32
D.
36
Solution
If the ratio of apples to oranges is 5:3, then for every 5 apples, there are 3 oranges. If there are 40 apples, we can set up the proportion: 5/3 = 40/x. Cross-multiplying gives us 5x = 120, so x = 24. Therefore, there are 24 oranges.
Q. A gardener has 36 red roses and 48 yellow roses. He wants to plant them in rows with the same number of each type of rose in each row. What is the maximum number of rows he can plant? (2023)
A.
6
B.
12
C.
18
D.
24
Solution
The HCF of 36 and 48 is 12, which is the maximum number of rows he can plant.
Q. A gardener has 60 red flowers and 90 yellow flowers. What is the largest number of bouquets he can make if each bouquet has the same number of red and yellow flowers? (2023)
A.
15
B.
30
C.
45
D.
60
Solution
The largest number of bouquets is the HCF of 60 and 90, which is 30.
Q. A gardener has two types of plants, one type has a height of 3 feet and the other 5 feet. What is the minimum height at which both types can be tied together? (2023)
A.
15
B.
30
C.
60
D.
45
Solution
The minimum height is the LCM of 3 and 5, which is 15 feet.
Q. A gardener has two types of plants, one type requires watering every 4 days and the other every 6 days. If both types are watered together today, in how many days will they be watered together again? (2023)
A.
12
B.
24
C.
18
D.
30
Solution
The LCM of 4 and 6 is 12. Therefore, they will be watered together again in 12 days.
Q. A group of friends consists of three pairs of siblings: A and B, C and D, E and F. If A is older than B, and C is younger than D, who is the youngest among them? (2023)
A.
A
B.
B
C.
C
D.
D
Solution
B is the youngest as A is older than B and C is younger than D.
Q. A group of friends went out for dinner. If the average cost per person was $20 and there were 5 people, what was the total cost of the dinner? (2023)
A.
$80
B.
$100
C.
$120
D.
$140
Solution
Total cost = Average cost per person × Number of people = 20 × 5 = $100.
Q. A group of students can complete a project in 12 days. If 4 more students join, the project can be completed in 8 days. How many students were initially in the group? (2023)
A.
6
B.
8
C.
10
D.
12
Solution
Let the initial number of students be x. The work done is constant, so x * 12 = (x + 4) * 8. Solving gives x = 8.
Q. A group of students can complete a project in 12 days. If 4 more students join, they can complete it in 8 days. How many students were initially in the group?
A.
6
B.
8
C.
10
D.
12
Solution
Let the initial number of students be x. The work done is inversely proportional to the number of days. Setting up the equation gives x = 10.
