Undergraduate Exam Prep Resources for Competitive Exams

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Undergraduate MCQ & Objective Questions

The undergraduate level is a crucial phase in a student's academic journey, especially for those preparing for school and competitive exams. Mastering this stage can significantly enhance your understanding and retention of key concepts. Practicing MCQs and objective questions is essential, as it not only helps in reinforcing knowledge but also boosts your confidence in tackling important questions during exams.

What You Will Practise Here

Fundamental concepts in Mathematics and Science
Key definitions and theories across various subjects
Important formulas and their applications
Diagrams and graphical representations
Critical thinking and problem-solving techniques
Subject-specific MCQs designed for competitive exams
Revision of essential topics for better retention

Exam Relevance

Undergraduate topics are integral to various examinations such as CBSE, State Boards, NEET, and JEE. These subjects often feature a mix of conceptual and application-based questions. Common patterns include multiple-choice questions that assess both theoretical knowledge and practical application, making it vital for students to be well-versed in undergraduate concepts.

Common Mistakes Students Make

Overlooking the importance of understanding concepts rather than rote memorization
Misinterpreting questions due to lack of careful reading
Neglecting to practice numerical problems that require application of formulas
Failing to review mistakes made in previous practice tests

FAQs

Question: What are some effective strategies for solving undergraduate MCQ questions?
Answer: Focus on understanding the concepts, practice regularly, and review your answers to learn from mistakes.

Question: How can I improve my speed in answering objective questions?
Answer: Time yourself while practicing and gradually increase the number of questions you attempt in a set time.

Start your journey towards mastering undergraduate subjects today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!

Engineering Entrance Medical Entrance

Q. A 20 kg object is thrown vertically upward with a force of 100 N. What is the net force acting on the object? (2023)

A. 0 N
B. 20 N
C. 80 N
D. 100 N

Solution

Net force = Applied force - Weight = 100 N - (20 kg * 10 m/s²) = 100 N - 200 N = -100 N (downward).

Correct Answer: C — 80 N

Q. A 200 g piece of metal at 100°C is placed in 300 g of water at 20°C. What is the final temperature of the system? (Specific heat of water = 4.18 J/g°C, specific heat of metal = 0.9 J/g°C) (2022)

A. 22.5°C
B. 30°C
C. 35°C
D. 40°C

Solution

Using the principle of conservation of energy: m1c1(T_initial - T_final) = m2c2(T_final - T_initial). Solving gives T_final = 35°C.

Correct Answer: C — 35°C

Q. A 25 kg object is acted upon by a force of 100 N. What is its acceleration? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we find a = F/m = 100 N / 25 kg = 4 m/s².

Correct Answer: D — 5 m/s²

Q. A 25 kg object is pulled with a force of 100 N. If the frictional force is 25 N, what is the acceleration of the object? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 100 N - 25 N = 75 N. Acceleration = Net force / Mass = 75 N / 25 kg = 3 m/s².

Correct Answer: C — 4 m/s²

Q. A 3 kg object is dropped from a height of 10 m. What is its potential energy at the top? (g = 9.8 m/s²)

A. 294 J
B. 30 J
C. 39.2 J
D. 19.6 J

Solution

Potential Energy (PE) = m × g × h = 3 kg × 9.8 m/s² × 10 m = 294 J.

Correct Answer: A — 294 J

Q. A 3 kg object is dropped from a height of 10 m. What is the potential energy at the top? (2022)

A. 30 J
B. 60 J
C. 90 J
D. 120 J

Solution

Potential Energy = mass × g × height = 3 kg × 10 m/s² × 10 m = 300 J

Correct Answer: C — 90 J

Q. A 3 kg object is dropped from a height of 12 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)

A. 15 m/s
B. 10 m/s
C. 12 m/s
D. 20 m/s

Solution

Using conservation of energy, PE = KE: mgh = 1/2 mv²; v = sqrt(2gh) = sqrt(2 * 10 m/s² * 12 m) = 15.49 m/s

Correct Answer: A — 15 m/s

Q. A 3 kg object is dropped from a height of 5 m. What is the potential energy at the top? (g = 9.8 m/s²)

A. 14.7 J
B. 29.4 J
C. 39.2 J
D. 49.05 J

Solution

PE = mgh = 3 kg × 9.8 m/s² × 5 m = 147 J.

Correct Answer: C — 39.2 J

Q. A 3 kg object is lifted to a height of 4 m. What is the gravitational potential energy gained? (2023)

A. 120 J
B. 60 J
C. 30 J
D. 90 J

Solution

Potential Energy (PE) = m * g * h = 3 kg * 9.8 m/s^2 * 4 m = 117.6 J (approximately 120 J)

Correct Answer: A — 120 J

Q. A 3 kg object is lifted to a height of 4 m. What is the work done against gravity? (g = 9.8 m/s²)

A. 117.6 J
B. 29.4 J
C. 39.2 J
D. 78.4 J

Solution

Work done (W) = mgh = 3 kg × 9.8 m/s² × 4 m = 117.6 J.

Correct Answer: A — 117.6 J

Q. A 3 kg object is moving with a velocity of 2 m/s. What is its kinetic energy? (2021)

A. 6 J
B. 12 J
C. 3 J
D. 9 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 3 kg * (2 m/s)^2 = 6 J

Correct Answer: B — 12 J

Q. A 3 kg object is moving with a velocity of 6 m/s. What is its momentum? (2021)

A. 18 kg m/s
B. 12 kg m/s
C. 9 kg m/s
D. 6 kg m/s

Solution

Momentum (p) = mv = 3 kg * 6 m/s = 18 kg m/s

Correct Answer: A — 18 kg m/s

Q. A 3 kg object is pushed with a force of 12 N over a distance of 4 m. What is the work done on the object?

A. 24 J
B. 36 J
C. 48 J
D. 60 J

Solution

Work done (W) = Force (F) × Distance (d) = 12 N × 4 m = 48 J.

Correct Answer: C — 48 J

Q. A 3 kg object is subjected to a net force of 12 N. What is the acceleration of the object? (2022)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: C — 4 m/s²

Q. A 3 kg object is thrown upwards with a velocity of 15 m/s. What is its maximum height? (2020)

A. 11.5 m
B. 17.5 m
C. 22.5 m
D. 10.5 m

Solution

Using the formula v^2 = u^2 - 2gh, we find h = u^2 / (2g) = (15 m/s)^2 / (2 * 9.8 m/s²) = 11.5 m.

Correct Answer: B — 17.5 m

Q. A 4 kg block is pulled with a force of 20 N. What is the acceleration of the block? (2020)

A. 5 m/s²
B. 4 m/s²
C. 3 m/s²
D. 2 m/s²

Solution

Using F = ma, acceleration (a) = F/m = 20 N / 4 kg = 5 m/s².

Correct Answer: A — 5 m/s²

Q. A 4 kg object is lifted to a height of 2 m. What is the work done against gravity? (2022)

A. 40 J
B. 80 J
C. 20 J
D. 60 J

Solution

Work done = mass × g × height = 4 kg × 10 m/s² × 2 m = 80 J

Correct Answer: B — 80 J

Q. A 4 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)

A. 19.6 J
B. 39.2 J
C. 49 J
D. 196 J

Solution

Work done against gravity = mgh = 4 kg × 9.8 m/s² × 5 m = 196 J.

Correct Answer: B — 39.2 J

Q. A 4 kg object is moving with a velocity of 5 m/s. What is its kinetic energy? (2021)

A. 10 J
B. 20 J
C. 50 J
D. 100 J

Solution

Kinetic energy KE = 1/2 mv² = 1/2 * 4 kg * (5 m/s)² = 50 J.

Correct Answer: C — 50 J

Q. A 5 kg block of ice at 0°C is converted to water at 0°C. If the latent heat of fusion of ice is 334 kJ/kg, how much heat is absorbed?

A. 1670 kJ
B. 334 kJ
C. 167 kJ
D. 3340 kJ

Solution

Heat absorbed (Q) = m * Lf = 5 kg * 334 kJ/kg = 1670 kJ.

Correct Answer: B — 334 kJ

Q. A 5 kg block of ice at 0°C is placed in a calorimeter containing 2 kg of water at 80°C. What is the final temperature of the system when thermal equilibrium is reached? (Latent heat of fusion of ice = 334 kJ/kg)

A. 0°C
B. 20°C
C. 40°C
D. 60°C

Solution

The heat lost by water = heat gained by ice. Solving gives the final temperature as 0°C.

Correct Answer: B — 20°C

Q. A 5 kg object is dropped from a height of 10 m. What is its potential energy at the top? (g = 9.8 m/s²)

A. 490 J
B. 98 J
C. 50 J
D. 100 J

Solution

Potential Energy = mgh = 5 kg * 9.8 m/s² * 10 m = 490 J.

Correct Answer: A — 490 J

Q. A 5 kg object is dropped from a height of 10 m. What is its speed just before it hits the ground? (g = 9.8 m/s²)

A. 14 m/s
B. 20 m/s
C. 10 m/s
D. 15 m/s

Solution

Using energy conservation, Potential Energy = Kinetic Energy at the ground: mgh = 0.5mv²; v = √(2gh) = √(2 × 9.8 m/s² × 10 m) = 14 m/s

Correct Answer: A — 14 m/s

Q. A 5 kg object is lifted to a height of 2 m. How much work is done against gravity? (g = 9.8 m/s²) (2022)

A. 98 J
B. 196 J
C. 39 J
D. 49 J

Solution

Work done = mgh = 5 kg * 9.8 m/s² * 2 m = 98 J.

Correct Answer: A — 98 J

Q. A 5 kg object is lifted to a height of 2 m. What is the work done against gravity?

A. 10 J
B. 20 J
C. 50 J
D. 100 J

Solution

Work done (W) against gravity is given by W = mgh. Here, m = 5 kg, g = 9.8 m/s², h = 2 m. W = 5 * 9.8 * 2 = 98 J.

Correct Answer: B — 20 J

Q. A 5 kg object is moving with a constant velocity. What is the net force acting on it? (2022)

A. 0 N
B. 5 N
C. 10 N
D. 15 N

Solution

If the object is moving with constant velocity, the net force acting on it is 0 N according to Newton's first law.

Correct Answer: A — 0 N

Q. A 5 kg object is moving with a velocity of 10 m/s. What is its momentum? (2021)

A. 50 kg m/s
B. 100 kg m/s
C. 150 kg m/s
D. 200 kg m/s

Solution

Momentum p = mv = 5 kg * 10 m/s = 50 kg m/s.

Correct Answer: B — 100 kg m/s

Q. A 5 kg object is moving with a velocity of 4 m/s. What is its momentum? (2023)

A. 10 kg m/s
B. 15 kg m/s
C. 20 kg m/s
D. 25 kg m/s

Solution

Momentum = mass × velocity = 5 kg × 4 m/s = 20 kg m/s.

Correct Answer: C — 20 kg m/s

Q. A 50 kg crate is pushed with a force of 200 N. If the frictional force is 50 N, what is the acceleration of the crate? (2022)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 200 N - 50 N = 150 N. Acceleration a = F/m = 150 N / 50 kg = 3 m/s².

Correct Answer: B — 3 m/s²

Q. A 50 kg crate is pushed with a force of 200 N. If the frictional force is 50 N, what is the acceleration? (2022)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = applied force - friction = 200 N - 50 N = 150 N. Acceleration a = F/m = 150 N / 50 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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