Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. A 10 kg object is moving with a velocity of 5 m/s. What is its momentum?
A.
10 kg·m/s
B.
25 kg·m/s
C.
50 kg·m/s
D.
75 kg·m/s
Show solution
Solution
Momentum p = mv = 10 kg * 5 m/s = 50 kg·m/s.
Correct Answer:
C
— 50 kg·m/s
Learn More →
Q. A 10 kg object is pushed with a force of 30 N. If the frictional force is 10 N, what is the net force?
A.
10 N
B.
20 N
C.
30 N
D.
40 N
Show solution
Solution
Net force = applied force - friction = 30 N - 10 N = 20 N.
Correct Answer:
B
— 20 N
Learn More →
Q. A 10 kg object is subjected to a net force of 30 N. What is its acceleration? (2022)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
Learn More →
Q. A 10 kg object is subjected to a net force of 30 N. What is the object's acceleration? (2019)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer:
C
— 3 m/s²
Learn More →
Q. A 10 kg object is thrown upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)
A.
11.5 m
B.
22.5 m
C.
15.3 m
D.
10.0 m
Show solution
Solution
Using conservation of energy, KE at the bottom = PE at the top. 0.5mv² = mgh. Solving gives h = v²/(2g) = (15)²/(2*9.8) = 11.5 m.
Correct Answer:
A
— 11.5 m
Learn More →
Q. A 10 kg object is thrown upwards with a velocity of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)
A.
11.5 m
B.
22.5 m
C.
15.0 m
D.
7.5 m
Show solution
Solution
Using energy conservation: KE_initial = PE_max; 0.5 * m * v² = mgh; h = v² / (2g) = (15 m/s)² / (2 * 9.8 m/s²) = 11.5 m.
Correct Answer:
A
— 11.5 m
Learn More →
Q. A 10 kg object is thrown vertically upward with a speed of 20 m/s. What is the maximum height reached by the object? (g = 10 m/s²) (2020)
A.
20 m
B.
30 m
C.
40 m
D.
50 m
Show solution
Solution
Using the formula h = v² / (2g), h = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Correct Answer:
B
— 30 m
Learn More →
Q. A 10 kg object is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 10 m/s²)
A.
11.25 m
B.
22.5 m
C.
15 m
D.
7.5 m
Show solution
Solution
Using energy conservation: KE_initial = PE_max; 1/2 * m * v^2 = m * g * h; h = v^2 / (2g) = (15^2) / (2 * 10) = 11.25 m
Correct Answer:
A
— 11.25 m
Learn More →
Q. A 10 kg object is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2023)
A.
20 m
B.
40 m
C.
30 m
D.
10 m
Show solution
Solution
Using the formula h = (v²)/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.
Correct Answer:
B
— 40 m
Learn More →
Q. A 10 N force is applied at an angle of 60° to the horizontal while moving an object 4 m. What is the work done?
A.
20 J
B.
40 J
C.
30 J
D.
10 J
Show solution
Solution
Work done (W) = F × d × cos(θ) = 10 N × 4 m × cos(60°) = 10 × 4 × 0.5 = 20 J.
Correct Answer:
C
— 30 J
Learn More →
Q. A 10 N force is applied to move an object 3 m. What is the work done if the force is applied at an angle of 60 degrees to the direction of motion?
A.
15 J
B.
30 J
C.
25 J
D.
20 J
Show solution
Solution
Work done = Force × Distance × cos(θ) = 10 N × 3 m × cos(60°) = 10 N × 3 m × 0.5 = 15 J
Correct Answer:
A
— 15 J
Learn More →
Q. A 10 Ω resistor and a 20 Ω resistor are connected in series. What is the total resistance?
A.
10 Ω
B.
20 Ω
C.
30 Ω
D.
5 Ω
Show solution
Solution
In series, the total resistance R = R1 + R2 = 10 Ω + 20 Ω = 30 Ω.
Correct Answer:
C
— 30 Ω
Learn More →
Q. A 10 Ω resistor is connected to a 20 V battery. What is the current flowing through the resistor?
A.
2 A
B.
0.5 A
C.
5 A
D.
10 A
Show solution
Solution
Using Ohm's law, V = IR, where V = 20 V and R = 10 Ω. Therefore, I = V/R = 20/10 = 2 A.
Correct Answer:
A
— 2 A
Learn More →
Q. A 10-ohm resistor and a 20-ohm resistor are connected in series. What is the total resistance?
A.
10 ohms
B.
20 ohms
C.
30 ohms
D.
5 ohms
Show solution
Solution
In series, the total resistance R = R1 + R2 = 10 + 20 = 30 ohms.
Correct Answer:
C
— 30 ohms
Learn More →
Q. A 10-ohm resistor has a voltage of 20 volts across it. What is the current flowing through the resistor?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Using Ohm's Law, I = V / R = 20 V / 10 Ω = 2 A.
Correct Answer:
B
— 2 A
Learn More →
Q. A 10-ohm resistor has a voltage of 50 volts across it. What is the current flowing through the resistor?
A.
5 A
B.
10 A
C.
15 A
D.
20 A
Show solution
Solution
Using Ohm's Law, I = V / R = 50 V / 10 Ω = 5 A.
Correct Answer:
B
— 10 A
Learn More →
Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power consumed by the resistor? (2021)
A.
20 W
B.
40 W
C.
10 W
D.
2 W
Show solution
Solution
Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20^2 / 10 = 400 / 10 = 40 W.
Correct Answer:
B
— 40 W
Learn More →
Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power dissipated by the resistor?
A.
40 W
B.
20 W
C.
10 W
D.
2 W
Show solution
Solution
Power (P) can be calculated using P = V^2 / R = 20^2 / 10 = 400 / 10 = 40 W.
Correct Answer:
A
— 40 W
Learn More →
Q. A 100 g piece of metal at 100°C is placed in 200 g of water at 20°C. What will be the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.5 J/g°C) (2023)
A.
30°C
B.
40°C
C.
50°C
D.
60°C
Show solution
Solution
Using the heat transfer equation, we can find the final temperature to be 50°C.
Correct Answer:
C
— 50°C
Learn More →
Q. A 100 g piece of metal at 150°C is placed in 200 g of water at 25°C. What is the final temperature of the system assuming no heat loss? (2019)
A.
30°C
B.
40°C
C.
50°C
D.
60°C
Show solution
Solution
Using the principle of conservation of energy, we can calculate the final temperature to be 50°C.
Correct Answer:
C
— 50°C
Learn More →
Q. A 100 W bulb is connected to a 220 V supply. What is the current flowing through the bulb?
A.
0.45 A
B.
1.0 A
C.
2.2 A
D.
2.5 A
Show solution
Solution
Using the formula P = VI, where P = 100 W and V = 220 V, the current I = P/V = 100/220 ≈ 0.45 A.
Correct Answer:
A
— 0.45 A
Learn More →
Q. A 100 W bulb is used for 5 hours. How much energy does it consume? (2016)
A.
500 Wh
B.
1000 Wh
C.
200 Wh
D.
250 Wh
Show solution
Solution
Energy consumed = Power × Time = 100 W × 5 h = 500 Wh.
Correct Answer:
A
— 500 Wh
Learn More →
Q. A 1000 kg car accelerates from rest to a speed of 20 m/s in 10 seconds. What is the average power exerted by the engine?
A.
2000 W
B.
4000 W
C.
5000 W
D.
6000 W
Show solution
Solution
First, calculate the work done: W = (1/2)mv^2 = (1/2)(1000 kg)(20 m/s)^2 = 200000 J. Then, power is P = W/t = 200000 J / 10 s = 20000 W.
Correct Answer:
C
— 5000 W
Learn More →
Q. A 1000 kg car is moving at a speed of 15 m/s. What is its kinetic energy?
A.
112,500 J
B.
75,000 J
C.
50,000 J
D.
25,000 J
Show solution
Solution
Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (15 m/s)² = 112,500 J.
Correct Answer:
A
— 112,500 J
Learn More →
Q. A 1000 kg car is moving at a speed of 20 m/s. What is its momentum? (2000)
A.
2000 kg m/s
B.
10000 kg m/s
C.
5000 kg m/s
D.
4000 kg m/s
Show solution
Solution
Momentum (p) is calculated using the formula p = m * v. Here, p = 1000 kg * 20 m/s = 20000 kg m/s.
Correct Answer:
B
— 10000 kg m/s
Learn More →
Q. A 1000 kg car is moving at a speed of 36 km/h. What is its kinetic energy? (1 km/h = 1/3.6 m/s) (2000)
A.
500 J
B.
1000 J
C.
2000 J
D.
5000 J
Show solution
Solution
First convert speed: 36 km/h = 10 m/s. KE = 0.5 × m × v² = 0.5 × 1000 kg × (10 m/s)² = 0.5 × 1000 × 100 = 50000 J.
Correct Answer:
C
— 2000 J
Learn More →
Q. A 1000 W electric motor runs for 2 hours. How much work does it do? (2023)
A.
720,000 J
B.
1,000,000 J
C.
2,000,000 J
D.
1,440,000 J
Show solution
Solution
Work = Power × Time = 1000 W × (2 × 3600 s) = 7,200,000 J.
Correct Answer:
D
— 1,440,000 J
Learn More →
Q. A 1000 W heater is used to heat water. How much heat is supplied in 10 minutes? (2020)
A.
600 kJ
B.
300 kJ
C.
100 kJ
D.
150 kJ
Show solution
Solution
Heat (Q) = Power (P) * Time (t) = 1000 W * 600 s = 600 kJ.
Correct Answer:
A
— 600 kJ
Learn More →
Q. A 1000 W heater operates for 1 hour. How much energy does it consume?
A.
3600 J
B.
1000 J
C.
3600000 J
D.
100000 J
Show solution
Solution
Energy consumed is E = P * t. Here, P = 1000 W and t = 1 hour = 3600 seconds. Thus, E = 1000 W * 3600 s = 3600000 J.
Correct Answer:
C
— 3600000 J
Learn More →
Q. A 1000 W heater operates for 2 hours. How much energy does it consume?
A.
7200000 J
B.
2000000 J
C.
3600000 J
D.
1000000 J
Show solution
Solution
Energy consumed can be calculated using E = P * t. Here, P = 1000 W and t = 2 hours = 7200 seconds. Thus, E = 1000 W * 7200 s = 7200000 J.
Correct Answer:
C
— 3600000 J
Learn More →
Showing 91 to 120 of 31669 (1056 Pages)
