Understanding the concepts of "Height and Distance" is crucial for students preparing for various school and competitive exams. This topic not only enhances your problem-solving skills but also plays a significant role in scoring well in exams. Practicing MCQs and objective questions related to Height and Distance helps you grasp essential concepts and improves your exam preparation, ensuring you are well-equipped to tackle important questions.
What You Will Practise Here
Basic concepts of Height and Distance
Trigonometric ratios and their applications
Formulas for calculating heights and distances
Real-life applications of Height and Distance problems
Diagrams and illustrations for better understanding
Commonly used theorems related to angles of elevation and depression
Practice questions with detailed solutions
Exam Relevance
The topic of Height and Distance is frequently featured in CBSE, State Boards, and competitive exams like NEET and JEE. Students can expect questions that involve calculating heights using angles of elevation and depression, as well as problems that require the application of trigonometric ratios. Understanding the common question patterns will help you tackle these problems efficiently and effectively during your exams.
Common Mistakes Students Make
Confusing angles of elevation with angles of depression
Incorrectly applying trigonometric ratios in problem-solving
Neglecting to draw diagrams, which can lead to misunderstandings
Overlooking units of measurement in calculations
Failing to check for the context of the problem before solving
FAQs
Question: What are the key formulas for Height and Distance problems? Answer: The primary formulas involve the basic trigonometric ratios: sin, cos, and tan, which relate the angles to the sides of the triangles formed in height and distance problems.
Question: How can I improve my accuracy in solving Height and Distance MCQs? Answer: Regular practice of objective questions, along with reviewing common mistakes, will significantly enhance your accuracy and confidence in this topic.
Now is the time to boost your understanding of Height and Distance! Dive into our practice MCQs and test your knowledge to excel in your exams. Remember, consistent practice leads to success!
Q. A person is standing 50 meters away from a cliff. If the angle of elevation to the top of the cliff is 30°, what is the height of the cliff?
Q. A person is standing 50 meters away from a statue. If the angle of elevation to the top of the statue is 45 degrees, what is the height of the statue?
Q. A person standing 15 meters away from a building observes the top of the building at an angle of elevation of 45 degrees. What is the height of the building?
Q. A person standing 20 meters away from a building observes the top of the building at an angle of elevation of 45 degrees. What is the height of the building?
Q. A person standing 25 meters away from a building observes the top of the building at an angle of elevation of 53 degrees. What is the height of the building?
Q. A person standing 40 meters away from a building observes the top of the building at an angle of elevation of 30 degrees. What is the height of the building?
Q. A person standing 50 meters away from a building observes the top of the building at an angle of elevation of 30 degrees. What is the height of the building?
Q. A person standing 50 meters away from a building observes the top of the building at an angle of elevation of 60 degrees. What is the height of the building?
Q. A tower is 100 meters high. From a point on the ground, the angle of elevation to the top of the tower is 45 degrees. How far is the point from the base of the tower?
Q. A tower is 50 meters high. From a point on the ground, the angle of elevation to the top of the tower is 45 degrees. How far is the point from the base of the tower?
Q. A tree is 15 meters tall. If the angle of elevation from a point on the ground to the top of the tree is 30 degrees, how far is the point from the base of the tree?
A.
15√3 meters
B.
15/√3 meters
C.
15 meters
D.
30 meters
Solution
Using tan(30) = height/distance, distance = height/tan(30) = 15/√3 meters.
